Java 如何遍历多维数组的列[行]
我使用多维数组存储特定销售人员(1到4名销售人员)销售的产品总量(产品范围1到5) T将销售人员排在第1至第4行,产品ID排在第1至第5列 我唯一做不到的就是以独占方式遍历行以获得每个产品的总数,即第1列:第1到4行之和=总产品1,第2列:第1到4行之和=总产品2等 请参阅test salesTest应用程序代码,然后是Sales类:Java 如何遍历多维数组的列[行],java,Java,我使用多维数组存储特定销售人员(1到4名销售人员)销售的产品总量(产品范围1到5) T将销售人员排在第1至第4行,产品ID排在第1至第5列 我唯一做不到的就是以独占方式遍历行以获得每个产品的总数,即第1列:第1到4行之和=总产品1,第2列:第1到4行之和=总产品2等 请参阅test salesTest应用程序代码,然后是Sales类: /* test application for sales class */ package salestest; import SalesLibary.Sal
/*
test application for sales class
*/
package salestest;
import SalesLibary.Sales;
public class SalesTest {
public static void main(String[] args) {
// pass monthly stats to 4r(salespesons) * c5(products 1 to 5) using initialization method
int monthlySales [][]= {{13, 23, 45, 67, 56},
{43, 65, 76, 89, 90},
{43, 45, 76, 98, 90},
{34, 56, 76, 43, 87}};
//pass default values to constructor when creating object of class
Sales companySales = new Sales("Monneys Inc.", monthlySales);
companySales.displayMessage();
companySales.displaySales();
}//end main
}//end SalesTest class
//class Sales with associated methods
/*
Chapter 7: Practical Question 2
*/
package SalesLibary;
public class Sales {
//declare fields/members
private int salesTotals[][];
private String companyName;
//passs string and two dimensional array of sales stats to constructor from application object
public Sales(String name, int monthlySales[][]) {
companyName = name;
salesTotals = monthlySales;
}//end constructor
public void setCompanyName(String name) {
companyName = name;
}
public String getCompanyName() {
return companyName;
}
public void displaySales() {
//table heading
System.out.printf("The monthly sales stats for company %s are: ", companyName);
System.out.println(" ");//set columns headings
//create column headings representing products sold 1 to 5 by looping thru each colmn of row(salsperson)
System.out.print(" ");
for (int product = 0; product < salesTotals[0].length; product++) {
System.out.printf("Product %d ", product + 1);
}
System.out.println("Total ");
//create rows of table represnting salespersons 1 too 4, ten loop through array and print element
for (int salesPerson = 0; salesPerson < salesTotals.length; salesPerson++) {
System.out.printf("SalesPerson %2d", salesPerson + 1);
//use nested for loop to output all results
for (int total : salesTotals[salesPerson]) {
System.out.printf("%10d", total);
}
//call method to get total for each sales person by passing
//a row of products sold for each sales person to method
double total = getTotal(salesTotals[salesPerson]);
System.out.printf("%10.2f\n", total);
}//end outer for
System.out.println("Product Total: ");
double productSum = getTotalProduct();
System.out.printf("%10.2f", productSum);
//enumerate through each column and get sum to represent product total
}//end method Display sales
//method to calculate total, argument is array of results
public double getTotal(int salesTotals[]) {
int total = 0;
//loop thru array passed
for (int count : salesTotals) {
total += count;
}
return total;
}// end get salesPerson tital
//display message
public void displayMessage() {
System.out.printf("\nWlecome to %s monthly sales summaries!!!\n\n", getCompanyName());
}//end display message
//get total product sold
public double getTotalProduct() {
int productTotal[];
int totalProduct = 0;
//loop through array passed
for (int salesPerson = 0; salesPerson < salesTotals.length; salesPerson++) {
//go through each column of row[row]
productTotal = salesTotals[salesPerson];
//loop thirugh product total and get sum
for (int count : productTotal) {
totalProduct += count;
}
}//end outer for loop
return totalProduct;
}// end get salesPerson total
}//end Sales class
/*
销售类考试申请表
*/
包装销售测试;
进口销售文库。销售;
公共类销售测试{
公共静态void main(字符串[]args){
//使用初始化方法将每月统计数据传递给4r(销售人员)*c5(产品1到5)
int monthlySales[][]={{13,23,45,67,56},
{43, 65, 76, 89, 90},
{43, 45, 76, 98, 90},
{34, 56, 76, 43, 87}};
//创建类的对象时将默认值传递给构造函数
销售公司销售额=新销售额(“Monneys Inc.,月销售额”);
companySales.displayMessage();
companySales.displaySales();
}//端干管
}//结束测试类
//使用关联的方法初始化Sales
/*
第7章:实际问题2
*/
包装销售文库;
公务舱销售{
//声明字段/成员
私人整数销售总额[];
私有字符串companyName;
//将字符串和二维销售统计数据数组从应用程序对象传递给构造函数
公开销售(字符串名称,int monthlySales[]]){
companyName=名称;
销售总额=月销售额;
}//端构造函数
public void setCompanyName(字符串名称){
companyName=名称;
}
公共字符串getCompanyName(){
返回公司名称;
}
公开销售(){
//表格标题
System.out.printf(“公司%s的月度销售统计数据为:”,companyName);
System.out.println(“”;//设置列标题
//通过循环遍历行(salsperson)的每一列,创建表示1到5个销售产品的列标题
系统输出打印(“”);
对于(int product=0;product
要在二维数组中迭代一行k
:
for (int j = 0; j < multiarray[k].length; j++)
multiarray[k][j]; // do something
for (int i = 0; i < multiarray.length; i++)
multiarray[i][k]; // do something
首先,如果不需要,不要使用所有代码。您只需要声明,可能还需要一个for循环 循环通过列:
for(int i=0; i<monthlySales[salesPerson].length; i++) {
monthlySales[i][salesPerson]; //do something with it!
}
for(int i=0;i得到它:)
有点头晕目眩试图想象阵列,但最终到达了那里,为帮助欢呼
//loop thorugh each column to get total products sold
for (int product = 0; product < salesTotals[0].length; product++) {
int totalProduct = 0;
for (int salePerson = 0; salePerson < salesTotals.length; salePerson++) {
totalProduct += salesTotals[salePerson][product];
}//end inner for
System.out.printf("%10d", totalProduct);
}//end outer for
//循环遍历每列以获得销售的产品总数
对于(int product=0;product
假设您有一个二维数组作为
int[][] salesData={{13, 23, 45, 67, 56},
{43, 65, 76, 89, 90},
{43, 45, 76, 98, 90},
{34, 56, 76, 43, 87}};
这是一个4*5的矩阵
int[0]表示第一行的值,即{13,23,45,67,56},如果需要单个单元格中的值,则需要为每个循环重复2次,如
for (int[] rowData: salesData){
for(int cellData: rowData)
{
System.out.printn("the indiviual data is" +cellData);
}
}
@shutefan重要的是最后一次编辑,我及时发现了错误。我知道这与结果无关,但为什么不把答案想清楚然后发送。。。通过这种方式,我多次重新键入注释以指出错误。任何人都可以通过重复//do something代码,以简洁的方式在一个循环中执行行和列迭代,这给了他们额外的分数。相关:按基数方向自由遍历2D数组(下、上、左、右):