Java模式匹配器和正则表达式

我需要正则表达式的帮助，请。。。基本上是匹配以下字符串的模式

G1:k6YxekrAP71LqRv[P:3]    
G1:k6YxekrAP71LqRv[S:2,3,4|P:3]
G1:k6YxekrAP71LqRv[P:3|R:2,3,4,5]
G1:k6YxekrAP71LqRv[S:2,3,4|P:3|R:2,3,4,5]

G1:k6YxekrAP71LqRv和p:3是最主要的匹配对象

我已经做了下面的匹配第一个字符串，但失去了与其他字符串

G1:k6YxekrAP71LqRv(\[|\|)P:3(\||\])

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如果我没有弄错的话，字符串都以G1:k6YxekrAP71LqRv开头

在那之后，有[p:3]本身，或者有左S:2,3,4 |，右R:2,3,4,5，或者有左和右。值2,3,4和2,3,4,5可以是用逗号除以的重复数字

要匹配完整模式，您可以使用：

解释

对于？：\d，+\d，您也可以使用2,3,4和2,3,4,5 fi，您希望从字面上匹配它们

要在开始时将整个字符串与G1:k6YxekrAP71LqRv匹配，并且应该包含p:3，可以使用正向前瞻？=.*p:3:

解决方案：

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G1:k6YxekrAP71LqRv\\[.*？谢谢你的解决方案伙伴。你的表达不起作用。请在这里@zoro74查看。我在第一次尝试时更新了我的答案，以弥补这个漏洞，希望对你有所帮助：- (G1:k6YxekrAP71LqRv) # Match literally in group 1 \[ # Match [ (?: # Non capturing group S: # Match literally (?:\d,)+\d\| # Match repeatedly a digit and comma one or more times \d\| # Followed by a digit and | )? # Close group and make it optional (P:3) # Capture P:3 in group 2 (?: # Non capturing group \|R: # match |R: (?:\d,)+ # Match repeatedly a digit and comma one or more times \d # Followed by a digit )? # Close group and make it optional \] # Match ]

String s1 = "G1:k6YxekrAP71LqRv[P:3]";
String s2 = "G1:k6YxekrAP71LqRv[S:2,3,4|P:3]";
String s3 = "G1:k6YxekrAP71LqRv[P:3|R:2,3,4,5]";
String s4 = "G1:k6YxekrAP71LqRv[S:2,3,4|P:3|R:2,3,4,5]";
String withCommaAfter = "G1:k6YxekrAP71LqRv[S:2,3,4|P:3,4]";
String notMatch1 ="G1:k6YxekrAP71LqRv[P:33]";
String notMatch2 = "G1:k6YxekrAP71LqRv[S:2,3,4|P:33]";

String[] sampleStrings = new String[] {s1, s2, s3, s4, withCommaAfter, notMatch1, notMatch2}; // to store source strings and to print results in a loop
Pattern p = Pattern.compile("(G1:k6YxekrAP71LqRv)\\[.*(?<=\\||\\[)(P:3)(?=\\]|\\,|\\|)[^\\]]*\\]");
for(String s : sampleStrings) {
    System.out.println("Checked String: \"" + s + "\"");
    Matcher m = p.matcher(s);
    while(m.find()) { // if match is found print the following line to the console
        System.out.println("\t whole String  : " + m.group());
        System.out.println("\t G1...qRv part : " + m.group(1));
        System.out.println("\t P:3      part : " + m.group(2) + "\n");
    }
}

Checked String: "G1:k6YxekrAP71LqRv[P:3]"
     whole String  : G1:k6YxekrAP71LqRv[P:3]
     G1...qRv part : G1:k6YxekrAP71LqRv
     P:3      part : P:3

Checked String: "G1:k6YxekrAP71LqRv[S:2,3,4|P:3]"
     whole String  : G1:k6YxekrAP71LqRv[S:2,3,4|P:3]
     G1...qRv part : G1:k6YxekrAP71LqRv
     P:3      part : P:3

Checked String: "G1:k6YxekrAP71LqRv[P:3|R:2,3,4,5]"
     whole String  : G1:k6YxekrAP71LqRv[P:3|R:2,3,4,5]
     G1...qRv part : G1:k6YxekrAP71LqRv
     P:3      part : P:3

Checked String: "G1:k6YxekrAP71LqRv[S:2,3,4|P:3|R:2,3,4,5]"
     whole String  : G1:k6YxekrAP71LqRv[S:2,3,4|P:3|R:2,3,4,5]
     G1...qRv part : G1:k6YxekrAP71LqRv
     P:3      part : P:3

Checked String: "G1:k6YxekrAP71LqRv[S:2,3,4|P:3,4]"
     whole String  : G1:k6YxekrAP71LqRv[S:2,3,4|P:3,4]
     G1...qRv part : G1:k6YxekrAP71LqRv
     P:3      part : P:3

Checked String: "G1:k6YxekrAP71LqRv[P:33]"
Checked String: "G1:k6YxekrAP71LqRv[S:2,3,4|P:33]"