使用XPath解析Java iTunes XML库
因此,我试图创建一个方法,允许我输入一个曲目ID,然后返回属于该曲目ID的曲目名称 我需要使用XPath将XML文档解析为java,java反过来将序列化一个新库。下面是我的XML文档示例:使用XPath解析Java iTunes XML库,java,xml,parsing,xpath,itunes,Java,Xml,Parsing,Xpath,Itunes,因此,我试图创建一个方法,允许我输入一个曲目ID,然后返回属于该曲目ID的曲目名称 我需要使用XPath将XML文档解析为java,java反过来将序列化一个新库。下面是我的XML文档示例: <plist version="1.0"> <dict> <key>Major Version</key> <integer>1</integer> <key>Mino
<plist version="1.0">
<dict>
<key>Major Version</key>
<integer>1</integer>
<key>Minor Version</key>
<integer>1</integer>
<key>Date</key>
<date>2015-03-16T15:04:23Z</date>
<key>Application Version</key>
<string>12.1.0.71</string>
<key>Features</key>
<integer>5</integer>
<key>Show Content Ratings</key>
<true/>
<key>Music Folder</key>
<string>
file://localhost/C:/Users/Mark/Music/iTunes/iTunes%20Media/
</string>
<key>Library Persistent ID</key>
<string>3B01AE08EA513C21</string>
<key>Tracks</key>
<dict>
<key>646</key>
<dict>
<key>Track ID</key>
<integer>646</integer>
<key>Name</key>
<string>Save Me</string>
<key>Artist</key>
<string>Avenged Sevenfold</string>
<key>Album Artist</key>
<string>Avenged Sevenfold</string>
<key>Album</key>
<string>Nightmare</string>
<key>Genre</key>
<string>Metal</string>
<key>Kind</key>
<string>MPEG audio file</string>
<key>Size</key>
<integer>23257166</integer>
<key>Total Time</key>
<integer>656535</integer>
<key>Disc Number</key>
<integer>1</integer>
<key>Disc Count</key>
<integer>1</integer>
<key>Track Number</key>
<integer>11</integer>
<key>Track Count</key>
<integer>11</integer>
<key>Year</key>
<integer>2010</integer>
<key>Date Modified</key>
<date>2012-10-21T22:07:20Z</date>
<key>Date Added</key>
<date>2012-10-21T22:07:20Z</date>
<key>Bit Rate</key>
<integer>276</integer>
<key>Sample Rate</key>
<integer>44100</integer>
<key>Play Count</key>
<integer>2</integer>
<key>Play Date</key>
<integer>3415934327</integer>
<key>Play Date UTC</key>
<date>2012-03-30T06:38:47Z</date>
<key>Artwork Count</key>
<integer>1</integer>
<key>Persistent ID</key>
<string>0000000000001389</string>
<key>Track Type</key>
<string>File</string>
<key>Location</key>
<string>
file://localhost/C:/Users/Mark/Music/Avenged%20Sevenfold/Nightmare/11%20-%20Save%20Me.mp3
</string>
<key>File Folder Count</key>
<integer>2</integer>
<key>Library Folder Count</key>
<integer>1</integer>
</dict>
<key>648</key>
<dict>
<key>Track ID</key>
<integer>648</integer>
<key>Name</key>
<string>Welcome 2 Hell</string>
<key>Artist</key>
<string>Bad Meets Evil</string>
<key>Album Artist</key>
<string>Bad Meets Evil</string>
<key>Composer</key>
<string>Havoc, Magnedo7</string>
<key>Album</key>
<string>Hell: The Sequel (Deluxe Edition)</string>
<key>Genre</key>
<string>Rap</string>
<key>Kind</key>
<string>MPEG audio file</string>
<key>Size</key>
<integer>7467977</integer>
<key>Total Time</key>
<integer>177606</integer>
<key>Track Number</key>
<integer>1</integer>
<key>Year</key>
<integer>2011</integer>
<key>Date Modified</key>
<date>2012-10-21T22:07:20Z</date>
<key>Date Added</key>
<date>2012-10-21T22:07:20Z</date>
<key>Bit Rate</key>
<integer>320</integer>
<key>Sample Rate</key>
<integer>44100</integer>
<key>Play Count</key>
<integer>3</integer>
<key>Play Date</key>
<integer>3424485861</integer>
<key>Play Date UTC</key>
<date>2012-07-07T06:04:21Z</date>
<key>Skip Count</key>
<integer>2</integer>
<key>Skip Date</key>
<date>2012-11-26T14:02:44Z</date>
<key>Artwork Count</key>
<integer>1</integer>
<key>Persistent ID</key>
<string>000000000000138A</string>
<key>Track Type</key>
<string>File</string>
<key>Location</key>
<string>
file://localhost/C:/Users/Mark/Music/Bad%20Meets%20Evil/Hell_%20The%20Sequel%20(Deluxe%20Edition)/01%20-%20Welcome%202%20Hell.mp3
</string>
<key>File Folder Count</key>
<integer>2</integer>
<key>Library Folder Count</key>
<integer>1</integer>
</dict>
</plist>
任何帮助都将不胜感激
编辑:
使用Mathias Müller的建议产生了正确的结果,如预期的那样,第646轨道“保存我”。但是,当我输入另一个曲目ID时,它也会返回“Save Me”,这是不正确的
我不知道它为什么这样做,因为我以为它只会返回我输入的ID的曲目名称,但它会返回不同的曲目名称
第二次编辑:
-包含了更多的XML
第三次编辑:
使用Mathias的建议,将XPath表达式更改为
//dict[integer=“+id+”]/string[1]/text()
。这工作得很好。我无法对Java代码进行评论,但我可以向您解释应该使用的XPath表达式。假设您显示的输入示例,应用
//dict[key='646']/dict/key[. = 'Name']/following-sibling::*[1]
会回来的
<string>Save Me</string>
结果将是
Save Me
路径表达式的工作原理如下:
//dict select `dict` elements anywhere in the document
[key='646'] but only if they have an immediate child `key` whose text
content is equal to "646"
/dict select their child elements called `dict`
/key[. = 'Name'] of those `dict` elements select their child elements `key`,
but only if their text content is equal to "Name"
/following-sibling::*[1] of those `key` elements, select the first following sibling
element
/text() and select its text content
原始表达式依赖于
字符串
元素的位置,也可以进行细微的更改:
//dict[key ="646"]/dict/string[1]/text()
您的解决方案部分有效,解释得很好,但当我搜索其他曲目ID时,它仍然返回曲目名称为“Save Me”,而它不应该返回。您有什么建议吗?@user3068854当然,但您需要显示输入文档的更多内容。包含多个曲目的示例。我假设您没有在表达式中硬编码ID值?更新了XML以显示前两个轨迹。我尝试对ID进行硬编码,结果也一样。请原谅任何不正确的缩进,该文件对我来说非常难以正确读取。@user3068854不,我的意思是对ID值进行硬编码是错误的;)。您的新XML示例格式不正确,也不清楚应该如何更正,但我提出的表达式很可能现在会返回两个结果,都是跟踪名称字符串,而不管ID如何。如果您仍然需要帮助,请确保您的示例格式正确(即,正确关闭位于正确位置的
dict
元件)。再次感谢您的帮助,我通过在其他地方搜索曲目ID并使用您提供的语法,成功地识别了曲目名称。是因为我,还是iTunes库XML文件真的很难读取?我的库有9000首曲目,我很难找到dict元素的结尾和新曲目的开始位置。也许是我在直截了当地?
//dict select `dict` elements anywhere in the document
[key='646'] but only if they have an immediate child `key` whose text
content is equal to "646"
/dict select their child elements called `dict`
/key[. = 'Name'] of those `dict` elements select their child elements `key`,
but only if their text content is equal to "Name"
/following-sibling::*[1] of those `key` elements, select the first following sibling
element
/text() and select its text content
//dict[key ="646"]/dict/string[1]/text()