Java 爪哇的石头剪刀

我正在用java写一个石头剪刀布游戏，但有些事情我搞不懂。首先，我想让用户可以输入Rock或paper，而不是1、2和3，但我想不出来。其次，我应该使用嵌套的if-else语句，但我也不知道如何使用我一直在做的事情。我的代码在下面

导入java.util.Scanner； 公共级摇滚游戏{

  private final static int ROCK=1;
  private final static int PAPER =2;
  private final static int SCISSOR =3;

  private static Scanner key;




public static void main(String args[]){
         int playerOneScore = 0;
         int computerScore = 0;

         int userPlay, computerPlay;


        String val = key.nextLine().toLowerCase();

         key = new Scanner(System.in);
         while(playerOneScore <2 && computerScore <2){


                 System.out.println("Choose 1 for rock, 2 for paper, and 3 for sciscors!");
                 userPlay = key.nextInt();
                 computerPlay = (int)(Math.random()*3) +1;
                 if(val.equals("rock"))
                       userPlay = ROCK;

                 else if (val.equals("paper"))
                         userPlay =PAPER;

                 else if (val.equals("scissors"))
                         userPlay=SCISSOR;


                 if (val.equals("rock"))
                         computerPlay = ROCK;
                 else if (val.equals("paper"))
                         computerPlay =PAPER;
                 else if (val.equals("scissors"))
                         computerPlay=SCISSOR;

                 if (computerPlay ==ROCK && userPlay==SCISSOR ){
                         System.out.println("The computer chose rock, you chose scissors.\n You lose!");
                         computerScore++;
                 }
                 if (computerPlay ==ROCK && userPlay==PAPER ){
                         System.out.println("You computer chose rock, you chose paper.\n You win!");
                         playerOneScore++;
                 }
                 if (computerPlay ==PAPER && userPlay==SCISSOR ){
                        System.out.println("The computer chose scissors, you chose paper.\n You win!");
                         playerOneScore++;
                 }
                 if (computerPlay ==PAPER && userPlay==ROCK ){
                         System.out.println("The computer chose paper and you chose rock. \n You lose!");
                         computerScore++;
                 }
                 if (computerPlay ==SCISSOR && userPlay==ROCK ){
                         System.out.println("The computer chose scissors and you chose rock. \n You win!");
                         playerOneScore++;
                 }
                 if (computerPlay ==SCISSOR && userPlay==PAPER ){
                         System.out.println("The computer chose scissors and you chose paper. \n You lose!");
                         computerScore++;
                 }
                 if (computerPlay == userPlay ){
                         System.out.println("The computer chose the same thing you did! \n Tie!");

                 }


         }
         if(computerScore > playerOneScore)
                 System.out.println("Computer win score is: - "+ computerScore + " -" + playerOneScore  );
         else
                 System.out.println("Your score is: " + playerOneScore + "-" + computerScore );


  }


}

使用：

然后：

if(val.equals("rock") {
   userPlay = ROCK;
}
else if(...) {
   //..
}

可以使用嵌套的if循环，如：

if(userPlay == ROCK) {
  if(computerPlay == ROCK) {
    System.out.println("The computer chose the same thing you did! \n Tie!");
  }
  else if(computerPlay == PAPER) {
    System.out.println("The computer chose paper and you chose rock. \n You lose!");
    computerScore++;
  }
  else {
    System.out.println("The computer chose scissors and you chose rock. \n You win!");
    playerOneScore++;
  }
}
else if(userPlay == PAPER) {
  if(computerPlay == ROCK) {
    System.out.println("You computer chose rock, you chose paper.\n You win!");
    playerOneScore++;
  }
  else if(computerPlay == PAPER) {
    System.out.println("The computer chose the same thing you did! \n Tie!");
  }
  else {
    System.out.println("The computer chose scissors and you chose paper. \n You lose!");
    computerScore++;
  }
}
//I think you get the idea...

使用：

然后：

if(val.equals("rock") {
   userPlay = ROCK;
}
else if(...) {
   //..
}

可以使用嵌套的if循环，如：

if(userPlay == ROCK) {
  if(computerPlay == ROCK) {
    System.out.println("The computer chose the same thing you did! \n Tie!");
  }
  else if(computerPlay == PAPER) {
    System.out.println("The computer chose paper and you chose rock. \n You lose!");
    computerScore++;
  }
  else {
    System.out.println("The computer chose scissors and you chose rock. \n You win!");
    playerOneScore++;
  }
}
else if(userPlay == PAPER) {
  if(computerPlay == ROCK) {
    System.out.println("You computer chose rock, you chose paper.\n You win!");
    playerOneScore++;
  }
  else if(computerPlay == PAPER) {
    System.out.println("The computer chose the same thing you did! \n Tie!");
  }
  else {
    System.out.println("The computer chose scissors and you chose paper. \n You lose!");
    computerScore++;
  }
}
//I think you get the idea...

我想让用户可以输入岩石或纸张，而不是1、2和3

使用key.nextLine.toLower，然后测试该值是否等于rock等

我应该使用嵌套的if-else语句

请注意，在代码中：

if (computerPlay ==SCISSOR && userPlay==ROCK ){
    // etc.
}
if (computerPlay ==SCISSOR && userPlay==PAPER ){
    // etc.
}

您可以检查computerPlay==SCISSOR两次。而使用嵌套语句，您可以执行以下操作：

if (computerPlay == SCISSOR) {
    if (userPlay == ROCK) {
        // etc.
    else if (userPlay == PAPER) {
        // etc.
    }
}

我想让用户可以输入岩石或纸张，而不是1、2和3

使用key.nextLine.toLower，然后测试该值是否等于rock等

我应该使用嵌套的if-else语句

请注意，在代码中：

if (computerPlay ==SCISSOR && userPlay==ROCK ){
    // etc.
}
if (computerPlay ==SCISSOR && userPlay==PAPER ){
    // etc.
}

您可以检查computerPlay==SCISSOR两次。而使用嵌套语句，您可以执行以下操作：

if (computerPlay == SCISSOR) {
    if (userPlay == ROCK) {
        // etc.
    else if (userPlay == PAPER) {
        // etc.
    }
}

---

首先，您需要创建一个枚举，然后将用户的输入解析到该枚举中：

至于嵌套的if-else语句，从技术上讲

if(something){
    // do something
}else if(somethingElse){
    // do something else
}else{
    // do another things
}

是一个嵌套的if-else语句。至少在编译器看来是这样的

我怀疑你的老师想看到这样的结构：

if(computerPlay == ROCK){
    if(userPlay == PAPER){
    }
    else if(userPlay == ROCK){
    }
    else if(userPlay == SCISSOR){
    }
}
else if(computerPlay == PAPER){
    // same as above
}
else if(computerPlay == SCISSOR){
    // same as above
}

---

首先，您需要创建一个枚举，然后将用户的输入解析到该枚举中：

至于嵌套的if-else语句，从技术上讲

if(something){
    // do something
}else if(somethingElse){
    // do something else
}else{
    // do another things
}

是一个嵌套的if-else语句。至少在编译器看来是这样的

我怀疑你的老师想看到这样的结构：

if(computerPlay == ROCK){
    if(userPlay == PAPER){
    }
    else if(userPlay == ROCK){
    }
    else if(userPlay == SCISSOR){
    }
}
else if(computerPlay == PAPER){
    // same as above
}
else if(computerPlay == SCISSOR){
    // same as above
}

---

首先，您不需要这些行：

if (computerPlay==1)
    computerPlay = ROCK;
if (computerPlay==2)
    computerPlay =PAPER;
if (computerPlay==3)
    computerPlay=SCISSOR;

其次，你说你应该使用嵌套的if/else语句——也许这就是你的老师想要的：

if (computerPlay == ROCK)
{
    if (userPlay==ROCK)
    {
        ...
    }
    else if (userPlay == PAPER)
    {
        ...
    }
    else if (userPlay == SCISSORS)
    {
        ...
    }
    else
    {
        // Cheating!
    }
}
else if (computerPlay == PAPER)
{
    if (userPlay==ROCK)
    {
        ...
    }
    // And so on...

---

这是一个非常冗长的方法，我个人会做一个二维数组查找，您的原始代码看起来可以接受，但我想这是一个学习练习，让您习惯嵌套if/else。

首先，您不需要这些行：

if (computerPlay==1)
    computerPlay = ROCK;
if (computerPlay==2)
    computerPlay =PAPER;
if (computerPlay==3)
    computerPlay=SCISSOR;

其次，你说你应该使用嵌套的if/else语句——也许这就是你的老师想要的：

if (computerPlay == ROCK)
{
    if (userPlay==ROCK)
    {
        ...
    }
    else if (userPlay == PAPER)
    {
        ...
    }
    else if (userPlay == SCISSORS)
    {
        ...
    }
    else
    {
        // Cheating!
    }
}
else if (computerPlay == PAPER)
{
    if (userPlay==ROCK)
    {
        ...
    }
    // And so on...

这是一种非常冗长的方法，我个人会做一个二维数组查找，您的原始代码看起来可以接受，但我想这是一个学习练习，让您习惯嵌套的if/else。

您可以使用.equalsIgnoreCase；检查岩石、纸张等，或者如果用户输入岩石、纸张等，它甚至会匹配。另外嵌套if语句中的ng将使函数更加高效。要生成嵌套if语句，只需将一条if语句放在另一条if语句中，如下所示

    if(userPlay.equalsIgnoreCase("Rock")) {

         if (computerPlay.equalsIgnoreCase("Scissors"){
                System.out.println("The computer chose scissors, you chose rock.\n You win!");
                             playerOneScore++;
         }
         else if (computerPlay.equalsIgnoreCase("Paper")){
                System.out.println("You computer chose paper, you chose rock.\n You lose!");
                             computerScore--;
         }
     }

使用这些嵌套的if语句，每个选项只需检查用户选择一次，而不是像示例代码中那样多次

您还需要将key.nextInt更改为key.next，以便将字符串作为输入，并将其存储在userPlay中，而不是整数中

userPlay=key.next

希望这对您有所帮助！

您可以使用.equalsIgnoreCase；来检查岩石、纸张等，或者如果用户输入岩石、纸张等，它甚至会匹配。此外，添加嵌套的if语句将使您的函数更加高效。要生成嵌套的if语句，您只需将一条if语句放在另一条if语句中，如图所示下面

    if(userPlay.equalsIgnoreCase("Rock")) {

         if (computerPlay.equalsIgnoreCase("Scissors"){
                System.out.println("The computer chose scissors, you chose rock.\n You win!");
                             playerOneScore++;
         }
         else if (computerPlay.equalsIgnoreCase("Paper")){
                System.out.println("You computer chose paper, you chose rock.\n You lose!");
                             computerScore--;
         }
     }

使用这些嵌套的if语句，每个选项只需检查用户选择一次，而不是像示例代码中那样多次

您还需要将key.nextInt更改为key.next，以便将字符串作为输入，并将其存储在userPlay中，而不是整数中

userPlay=key.next

---

希望这对你有用！

经过一番思考，这就是你能做的

使用元素创建枚举

enum Elements{ROCK ,PAPER ,SCISSORS};

为元素的各种组合创建第二个枚举，并实现一个接口

enum ElementCombinations implements RockPaperScissorssLogic
{
    ROCK_PAPER
    {
        int decideWinner()
        {
            //For second player
            return 2;
        }
    }, 
    PAPER_SCISSORS
    {
        int decideWinner()
        {
            //For second player
            return 2;
        }
    }, 
    ..... ;

    // For obtaining decide the type of combination object to be used.
    public static ElementCombinations getCombination(Element player1, Element player2)
    {
        // Some logic...
    }
};

---

最后，在您的代码中，您可以简单地调用ElementCombinations对象的Decise winner方法来获得获胜的玩家。

经过一些思考后，您可以这样做

使用元素创建枚举

enum Elements{ROCK ,PAPER ,SCISSORS};

为元素的各种组合创建第二个枚举，并实现一个接口

enum ElementCombinations implements RockPaperScissorssLogic
{
    ROCK_PAPER
    {
        int decideWinner()
        {
            //For second player
            return 2;
        }
    }, 
    PAPER_SCISSORS
    {
        int decideWinner()
        {
            //For second player
            return 2;
        }
    }, 
    ..... ;

    // For obtaining decide the type of combination object to be used.
    public static ElementCombinations getCombination(Element player1, Element player2)
    {
        // Some logic...
    }
};

---

最后，在您的代码中，您可以简单地调用ElementCombinations对象的Decise winner方法来获得获胜的玩家。

在我个人的选择中，所有给定的答案都会使事情复杂化

下面是一个非常简单的示例，它存储了一个简单的二维数组

---

数组存储所有可能的结果。

在我的个人选项中，所有给定的答案都通过co

import java.util.Scanner;

public class RockPaperScissors {
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.println("Hey let's play Rock, Paper, Scissors!");
System.out.println("You must choose 1 for Rock, 2 for Paper and 3 for Scissors");
System.out.print("Rock, Paper or Scissors? ");
int play = console.nextInt();
String user = intToName(play,console);
int person = play;
int computer = generateRandomNumber(1,3);

}
    public static String intToName(int play,Scanner console){
    String choose = "";
     if (play == -1){
         System.out.print("Game Over!");
     }
    while (play != -1){
    if (play == 1){
        System.out.println("Your play is: Rock");
         if (generateRandomNumber(1,3) == 1){
                System.out.println("Computer player is: Rock");  
                System.out.println("It's a tie!");
              }
         else if (generateRandomNumber(1,3) == 2){
                    System.out.println("Computer player is: Paper"); 
                    System.out.println("Paper eats Rock. You lose!");
              }
           else if (generateRandomNumber(1,3) == 3){
                    System.out.println("Computer player is: Scissors"); 
                    System.out.println("Rock eats Scissors. You win!");
              }
    }
    else if (play == 2){
        System.out.println("Your play is: Paper");
         if (generateRandomNumber(1,3) == 1){
                System.out.println("Computer player is: Rock");  
                System.out.println("Paper eats Rock. You win!");
              }
         else if (generateRandomNumber(1,3) == 2){
                    System.out.println("Computer player is: Paper");  
                    System.out.println("It's a tie!");
              }
         else  if (generateRandomNumber(1,3) == 3){
                    System.out.println("Computer player is: Scissors"); 
                    System.out.println("Scissors eats Paper. You lose!");
              }
    }
    else if (play == 3){
     System.out.println("Your play is: Scissors");
     if (generateRandomNumber(1,3) == 1){
            System.out.println("Computer player is: Rock"); 
            System.out.println("Rock eats Scissors. You lose!");
          }
     else if (generateRandomNumber(1,3) == 2){
                System.out.println("Computer player is: Paper");  
                System.out.println("Scissors eats Paper. You win!");
          }
     else if (generateRandomNumber(1,3) == 3){
                System.out.println("Computer player is: Scissors");  
                System.out.println("It's a tie!");
          }
    }
    System.out.println();
    System.out.print("Rock, Paper or Scissors? ");
   play = console.nextInt();
  }
    return choose;
    }
    public static int generateRandomNumber(int a, int b){
        return a+(int)(Math.random()*b-a+1);
    }
    public static int winner(int person, int computer){
        int win =0;
        int lose =0;
        int tie=0;
        if (person == 1 && computer == 1){
            tie++;
        }
        if (person == 2 && computer == 2){
            tie++;
        }
        if (person == 3 && computer == 3){
            tie++;
        }
        if (person == 1 && computer == 2){
             lose++;
        }
        if (person == 1 && computer == 3){
            win++;
        }
        if (person == 2 && computer == 1){
            win++;
        }
            if (person == 2 && computer == 3){
                lose++;
    }
            if (person == 3 && computer == 1){
                lose++;
            }
            if (person == 3 && computer == 2){
                win++;
            }
            return win;
    }
}

使事情复杂化

下面是一个非常简单的示例，它存储了一个简单的二维数组

---

数组存储所有可能的结果

对不起，我真的是新手，第一行做什么？它从命令行读取一行。。。并将其存储到val字符串中。当然，如果愿意，您可以使用另一个变量名。你不必感到抱歉，我们都是从这个层次开始的。。。尽管我不得不说，回头看，代码看起来并不优雅。但无意冒犯：DNice新型循环，如果循环！：toLower将字符串转换为小写字符。所以岩石变成了岩石。@Diego C Nascimento:在荷兰语中，有些书说如果卢森。字面翻译意味着if循环。此外，这并不罕见：很抱歉，我真的是新手，第一行做什么？它从命令行读取一行。。。并将其存储到val字符串中。当然，如果愿意，您可以使用另一个变量名。你不必感到抱歉，我们都是从这个层次开始的。。。尽管我不得不说，回头看，代码看起来并不优雅。但无意冒犯：DNice新型循环，如果循环！：toLower将字符串转换为小写字符。所以岩石变成了岩石。@Diego C Nascimento:在荷兰语中，有些书说如果卢森。字面翻译意味着if循环。此外，这并不少见：如果您希望用户键入字符串，则使用字符串而不是整数。下面的答案解释了如何操作。您使用key.nextInt，因此必须输入数字。如果使用key.next，则可以输入字符串。您应该在计算机与用户逻辑中使用else if结构，因为所有对都是互斥的。如果您希望用户键入字符串，则使用字符串而不是整数。下面的答案解释了如何操作。您使用key.nextInt，因此必须输入数字。如果使用key.next，则可以输入字符串。你应该在你的计算机和用户逻辑中使用else if结构，因为所有对都是互斥的。你帮了很大的忙，但无论出于什么原因，我的代码现在都无法工作。我知道我可能是个白痴，但你能看出问题所在吗？我编辑了代码以反映我现在拥有的内容。在初始化扫描仪之前，请使用密钥。因此，移动表示String val=key.nextLine.toLowerCase的行；向下至下方键=新扫描系统.in；。你帮了大忙，但不管出于什么原因，我的代码现在无法工作。我知道我可能是个白痴，但你能看出问题所在吗？我编辑了代码以反映我现在拥有的内容。在初始化扫描仪之前，请使用密钥。因此，移动表示String val=key.nextLine.toLowerCase的行；向下至下方键=新扫描系统.in；。

import java.util.Scanner;

public class RockPaperScissors {
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.println("Hey let's play Rock, Paper, Scissors!");
System.out.println("You must choose 1 for Rock, 2 for Paper and 3 for Scissors");
System.out.print("Rock, Paper or Scissors? ");
int play = console.nextInt();
String user = intToName(play,console);
int person = play;
int computer = generateRandomNumber(1,3);

}
    public static String intToName(int play,Scanner console){
    String choose = "";
     if (play == -1){
         System.out.print("Game Over!");
     }
    while (play != -1){
    if (play == 1){
        System.out.println("Your play is: Rock");
         if (generateRandomNumber(1,3) == 1){
                System.out.println("Computer player is: Rock");  
                System.out.println("It's a tie!");
              }
         else if (generateRandomNumber(1,3) == 2){
                    System.out.println("Computer player is: Paper"); 
                    System.out.println("Paper eats Rock. You lose!");
              }
           else if (generateRandomNumber(1,3) == 3){
                    System.out.println("Computer player is: Scissors"); 
                    System.out.println("Rock eats Scissors. You win!");
              }
    }
    else if (play == 2){
        System.out.println("Your play is: Paper");
         if (generateRandomNumber(1,3) == 1){
                System.out.println("Computer player is: Rock");  
                System.out.println("Paper eats Rock. You win!");
              }
         else if (generateRandomNumber(1,3) == 2){
                    System.out.println("Computer player is: Paper");  
                    System.out.println("It's a tie!");
              }
         else  if (generateRandomNumber(1,3) == 3){
                    System.out.println("Computer player is: Scissors"); 
                    System.out.println("Scissors eats Paper. You lose!");
              }
    }
    else if (play == 3){
     System.out.println("Your play is: Scissors");
     if (generateRandomNumber(1,3) == 1){
            System.out.println("Computer player is: Rock"); 
            System.out.println("Rock eats Scissors. You lose!");
          }
     else if (generateRandomNumber(1,3) == 2){
                System.out.println("Computer player is: Paper");  
                System.out.println("Scissors eats Paper. You win!");
          }
     else if (generateRandomNumber(1,3) == 3){
                System.out.println("Computer player is: Scissors");  
                System.out.println("It's a tie!");
          }
    }
    System.out.println();
    System.out.print("Rock, Paper or Scissors? ");
   play = console.nextInt();
  }
    return choose;
    }
    public static int generateRandomNumber(int a, int b){
        return a+(int)(Math.random()*b-a+1);
    }
    public static int winner(int person, int computer){
        int win =0;
        int lose =0;
        int tie=0;
        if (person == 1 && computer == 1){
            tie++;
        }
        if (person == 2 && computer == 2){
            tie++;
        }
        if (person == 3 && computer == 3){
            tie++;
        }
        if (person == 1 && computer == 2){
             lose++;
        }
        if (person == 1 && computer == 3){
            win++;
        }
        if (person == 2 && computer == 1){
            win++;
        }
            if (person == 2 && computer == 3){
                lose++;
    }
            if (person == 3 && computer == 1){
                lose++;
            }
            if (person == 3 && computer == 2){
                win++;
            }
            return win;
    }
}