Java 如何格式化持续时间字符串?
我有一个值为“3D7H40M20S”的字符串 应转换为3天7小时40分20秒”。 以下是我迄今为止所做的尝试:Java 如何格式化持续时间字符串?,java,Java,我有一个值为“3D7H40M20S”的字符串 应转换为3天7小时40分20秒”。 以下是我迄今为止所做的尝试: BindingContainer bindings = BindingContext.getCurrent().getCurrentBindingsEntry(); AttributeBinding attr = (AttributeBinding)bindings.getControlBinding("ScreeningSLAWaitTimeDuration"
BindingContainer bindings = BindingContext.getCurrent().getCurrentBindingsEntry();
AttributeBinding attr = (AttributeBinding)bindings.getControlBinding("ScreeningSLAWaitTimeDuration");
scrSlaWaitDur = (String)attr.getInputValue();
System.out.println("-------------------------------------------SCREENING SLA WAIT DURATION---------------"+scrSlaWaitDur);
scrSlaWaitDur = scrSlaWaitDur.substring(2, scrSlaWaitDur.length());
System.out.println("--------------------------------------------SUBSTRING--------------------"+scrSlaWaitDur);
int dIndex = scrSlaWaitDur.indexOf("D");
System.out.println("*******************************************INDEX OF D**********************************"+dIndex);
if(dIndex != -1){
String newDur = scrSlaWaitDur.substring(0, dIndex)+" days "+scrSlaWaitDur.substring(dIndex+1);
int mIndex = scrSlaWaitDur.lastIndexOf("M");
String newDur2 = scrSlaWaitDur.substring(0, mIndex)+" minute "+scrSlaWaitDur.substring(mIndex+1);
int sIndex = newDur2.lastIndexOf("S");
String newDur3 = newDur2.substring(0,sIndex)+" second";
scrSlaWaitDur = newDur3;
return scrSlaWaitDur;
}
我知道这很烦人,也很冗长。
我可以用一种更简单的方法来实现需求吗?一种实用的方法是替换单元令牌:
return scrSlaWaitDur.replace("D", " Days ").replace("H", " Hours ").replace("M", " Minutes ").replace("S", " Seconds");
输出:
3 Days 7 Hours 40 Minutes 20 Seconds
可以使用不带索引()的子字符串(),即:
但我相信有人会想出一个芬西正则表达式的解决方案
String result =
scrSlaWaitDur.replace("D"," Days ").replace("H"," Hours ").replace("M"," Minutes ").replace("S"," Seconds");