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Java 如何从jdbc用户服务获取用户信息_Java_Spring_Spring Mvc_Spring Security_Spring Mybatis - Fatal编程技术网

Java 如何从jdbc用户服务获取用户信息

Java 如何从jdbc用户服务获取用户信息,java,spring,spring-mvc,spring-security,spring-mybatis,Java,Spring,Spring Mvc,Spring Security,Spring Mybatis,我正在使用spring安全授权,通过使用以下代码保护用户登录到我的应用程序: <jdbc-user-service data-source-ref="dataSource" users-by-username-query="SELECT username, password as password,1 as enabled FROM users WHERE username=?" authorities-by-username-query="SELECT username, author

我正在使用spring安全授权,通过使用以下代码保护用户登录到我的应用程序:

<jdbc-user-service data-source-ref="dataSource" users-by-username-query="SELECT username, password as password,1 as enabled FROM users  WHERE username=?" authorities-by-username-query="SELECT username, authority,1 as enabled FROM users WHERE username =?" />


有没有办法将其他字段添加到此查询中,例如:ID、电子邮件

这仅用于身份验证,用户登录后,您可以通过以下方式检查登录用户:

@RequestMapping(path="loggedInUser", method={RequestMethod.GET}, produces={MediaType.APPLICATION_JSON_UTF8_VALUE})
    @ResponseBody
    public User getLoggedInUser(Principal principal) throws SQLException{
        return database.getUser(principal.getName());
    }

或者,如果要从数据库加载完整的自定义用户对象,然后在
SecurityContextHolder
/
会话中设置它,则可以使用自定义UserDetailService()返回带有
principal.getName()的用户名

创建自定义用户实体: 首先根据数据库表创建一个简单的自定义用户实体

@Entity
@Table(name = "users")
public class SecurityUser implements Serializable{  

    /**
     * 
     */
    private static final long serialVersionUID = 1L;

    @Id
    @Column(name = "username", nullable = false, unique = true)
    private String username;

    @Column(name = "password", nullable = false)
    @NotNull
    private String password;

    @Column(name = "type", nullable = false)
    @NotNull
    private String type;

    @Column(name = "full_name", nullable = false)
    @NotNull
    private String fullName;

    @Column(name = "email", nullable = false)
    @NotNull
    private String email;

    //Gettters & Setters plus Default constructor
}
创建用于从数据库访问上述用户的存储库/DAO 创建自定义用户详细信息服务 在配置中设置UserDetailService 在使用基于XML的配置时,请在配置文件中执行以下操作:

<bean id="myUserDetailsService"
  class="complete-path-to-serviceClasss.MyUserDetailsService"/>

<security:authentication-manager>
    <security:authentication-provider
      user-service-ref="myUserDetailsService" >
        <security:password-encoder ref="passwordEncoder">
        </security:password-encoder>
    </security:authentication-provider>
</security:authentication-manager>
public class CurrentUser extends User {
    /**
     * 
     */
    private static final long serialVersionUID = 1L;
    private SecurityUser securityUser;

    public CurrentUser(SecurityUser securityUser) {
        super(securityUser.getUsername(), securityUser.getPassword(), AuthorityUtils.createAuthorityList(securityUser.getRole().toString()));
        this.securityUser = securityUser;
    }

    public SecurityUser getSecurityUser() {
        return securityUser;
    }

    public String getRole() {
        return securityUser.getRole();
    }
}
@Service
public class CurrentUserDetailsService implements UserDetailsService {

    @Autowired
    private UserRepository userService;

    @Autowired
    public CurrentUserDetailsService(UserRepository userService) {
        this.userService = userService;
    }

    public CurrentUserDetailsService() {

    }

    @Override
    public CurrentUser loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException {
        SecurityUser user = userService.findByUsername(username);
        return new CurrentUser(user);
    }
}
<bean id="myUserDetailsService"
  class="complete-path-to-serviceClasss.MyUserDetailsService"/>

<security:authentication-manager>
    <security:authentication-provider
      user-service-ref="myUserDetailsService" >
        <security:password-encoder ref="passwordEncoder">
        </security:password-encoder>
    </security:authentication-provider>
</security:authentication-manager>
CurrentUser user = SecurityContextHolder.getContext().getAuthentication().getPrincipal()