Java 持久化实体时SQLServerException-索引超出范围

我无法将一个实体与另一个实体保持@OneToOne关系。我们最近用Spring4和Hibernate4升级到了Java8，所以我确信有一些注释或配置发生了变化

相关代码

Caused by: org.hibernate.exception.GenericJDBCException: could not insert: [dao.srs.model.PermitState]
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3099)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3521)
    at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:88)
    at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:395)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:387)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:303)
    at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:349)
    at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:56)
    at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1195)
    at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:404)
    at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
    at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175)
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:75)
    at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:515)
    ... 65 more
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: The index 6 is out of range.
    at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDriverError(SQLServerException.java:171)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setterGetParam(SQLServerPreparedStatement.java:700)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setValue(SQLServerPreparedStatement.java:709)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setString(SQLServerPreparedStatement.java:1034)
    at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.setString(NewProxyPreparedStatement.java:963)
    at org.hibernate.type.descriptor.sql.VarcharTypeDescriptor$1.doBind(VarcharTypeDescriptor.java:57)
    at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:93)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:284)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:279)
    at org.hibernate.type.ComponentType.nullSafeSet(ComponentType.java:343)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrateId(AbstractEntityPersister.java:2835)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2804)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3076)
    ... 78 more

PermitState.java：

@Entity
@Table(schema = "dbo", name = "PermitState")
public class PermitState implements Serializable {

private String oid;
private Permit permit;
private Integer invoiced;
private Integer used;
private Integer ordered;
private String permitId;


@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PERMITID")
public Permit getPermit() {
    return permit;
}

@Id
@Column(name = "PERMITID", nullable = true, length = 8,insertable = false,updatable = false)
public String getPermitId() {
    return permitId;
}

... more getters and setters (irrelevant)

Permit.java：

@Entity
@Table(schema = "dbo")
public class Permit {

private String permitid;
private PermitState permitState;


...some more attributes, irrelevant


@Id
@Column(name = "PERMITID", length = 8)
public String getPermitid() {
    return permitid;
}

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

private String permitid;
private PermitState permitState;

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

Stacktrace

Caused by: org.hibernate.exception.GenericJDBCException: could not insert: [dao.srs.model.PermitState]
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3099)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3521)
    at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:88)
    at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:395)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:387)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:303)
    at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:349)
    at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:56)
    at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1195)
    at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:404)
    at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
    at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175)
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:75)
    at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:515)
    ... 65 more
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: The index 6 is out of range.
    at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDriverError(SQLServerException.java:171)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setterGetParam(SQLServerPreparedStatement.java:700)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setValue(SQLServerPreparedStatement.java:709)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setString(SQLServerPreparedStatement.java:1034)
    at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.setString(NewProxyPreparedStatement.java:963)
    at org.hibernate.type.descriptor.sql.VarcharTypeDescriptor$1.doBind(VarcharTypeDescriptor.java:57)
    at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:93)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:284)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:279)
    at org.hibernate.type.ComponentType.nullSafeSet(ComponentType.java:343)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrateId(AbstractEntityPersister.java:2835)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2804)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3076)
    ... 78 more

如您所见，PermitState实体既有一个与Permit的关系（通过PERMITID，这是Permit中的PK），也有一个名为PERMITID的字段，该字段应该是连接的许可证的ID。但这似乎不起作用，它似乎试图插入所有6个属性，即使不应该将Permit插入数据库。我试图在PermitState中用@Transient注释Permit，但随后得到一个AnnotationException：

Caused by: org.hibernate.AnnotationException: Unknown mappedBy in: dao.srs.model.Permit.permitState, referenced property unknown: dao.srs.model.PermitState.permit

任何帮助都将不胜感激

更新

---

只是澄清一下，DB只有5个字段-OID、PERMITID、发票、使用和订购-这就是为什么我认为它也尝试插入许可实体的原因。当我们使用Java 7、Spring 3、hibernate annotations 3.3.1.GA和hibernate entitymanager 3.3.2.GA时，完全相同的代码在没有修改的情况下工作。我们现在使用Java 8、Spring 4和Hibernate core+entitymanager+ehcache 4.2.19。

从异常情况来看，您尝试了@Transient，但仍然有@OneToOne和@JoinColumn。这并没有真正的意义，因为您告诉Hibernate您希望自己处理它，并且它也应该处理它

另外，我发现它有点让人困惑，你们都有PermitState中的Permit实体和permitId。您告诉它您不想更新permitId，但仍将其用作联接列

我建议删除permitId，并且只将许可证实体设置为PermitState。如果愿意，您仍然可以使用getPermitId方法，但可以将其视为agregate

---

如果所有其他操作都失败，请尝试记录Hibernate生成的SQL以查看发生了什么。也许是贴出来让我们看看。

我想我解决了。我仍然不完全确定为什么会这样，但它确实：

我从PermitState.java中删除了PermitId（字符串属性），而是在PermitState中使用了PermitId

看起来是这样的：

Permit.java：

@Entity
@Table(schema = "dbo")
public class Permit {

private String permitid;
private PermitState permitState;


...some more attributes, irrelevant


@Id
@Column(name = "PERMITID", length = 8)
public String getPermitid() {
    return permitid;
}

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

private String permitid;
private PermitState permitState;

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

PermitState.java

private Permit permit;

@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PERMITID")
public Permit getPermit() {
    return permit;
}

---

感谢Martin和Bilbo的帮助。

还有一件事我发现PERMITID在两个地方被用作列名。在permitState中作为PERMITID，也用于映射。不，DB只有5个字段，因为Permit不应该被持久化。应仅持久化从Permit.PermitId派生的PermitId。此外，在Java/Spring/Hibernate升级之前，该代码工作正常。当您在Permit上指定@OneTONE（mappedBy）时，Permit作为对象不会持久化到您的案例PermitState中，这是一种双向关系，因此它将在PermitState表中创建使用Permit映射的FK。现在，您指定@JoinColumn的问题是什么，然后名称是PERMITID，并且在@ID和@Column上名称是PERMITID，谢谢您的回复。我同意同时拥有Permit和PermitId看起来很奇怪（维护旧代码可能非常令人沮丧……）。我试图删除PermitId，但许可证实体仅位于PermitState中。但是，我无法更改数据库，因此我仍然需要将PermitId（许可证实体的PK）保存在PermitState中。这里有一个简单的UML图，显示了我对它的设想。关于如何实现这一点有什么帮助吗？我使用permitState.java中permitState属性上的@OneToOne（mappedBy=“permit”）和permitState.java中permitState属性上的@OneToOne，@JoinColumn（name=“PERMITID”）解决了这个问题。见下面我的答案。谢谢你的帮助！