Java 如何将用户输入存储在整数数组中？

我不知道用户将输入多少个数字，我需要程序在到达行尾时停止在数组中插入数字，因为在新行中，用户将输入一个与此无关的数字

例如：

用户可以输入：

1577895

四,

或：

5 4 8 9 4 2 1 3 2 4

七,

---

我需要的数组是，例如1:[1,5,7,8,9,5]

从我的头顶上：

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
String value = reader.readLine();
String[] strArr = value.split(" ");
int intArr[]= new int[strArr.length]; 
for(int i = 0; i < strArr.length; i++)
    intArr[i] = Integer.parseInt(strArr[i]);

BufferedReader reader=新的BufferedReader（新的InputStreamReader（System.in））；
字符串值=reader.readLine（）；
字符串[]strArr=value.split（“”）；
int intArr[]=新int[strArr.length]；
对于（int i=0；i

您可以使用列表保存号码。 如果确实需要数组类型变量。可以从列表中创建数组

    List<Integer> list = Arrays.asList(1,2,3,4,5);
    Integer[] array = list.toArray(new Integer[0]);

List List=Arrays.asList（1,2,3,4,5）；
整数[]数组=list.toArray（新整数[0]）；

我同意您应该询问用户数组的大小，因为数组是静态数据结构。

---

使用链表数据结构。

如果您的需求允许您询问用户，您可以按如下方式执行：

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner=new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if(scanner.hasNextInt()) {
            n=scanner.nextInt();
        }
        num=new int[n];
        for(int i=0;i<n;i++) {
            System.out.printf("Enter integer %d: ",i+1);
            if(scanner.hasNextInt()) {
                num[i]=scanner.nextInt();
            }           
        }
        System.out.println(Arrays.toString(num));
    }
}

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner = new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if (scanner.hasNextInt()) {
            n = scanner.nextInt();
            scanner.nextLine();
        }
        num = new int[n];
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (int i = 0; i < n; i++) {
                try {
                    num[i] = Integer.parseInt(strNums[i]);
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(Arrays.toString(num));
        }
    }
}

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        List <Integer> intList=new ArrayList<Integer>();
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (String strNum: strNums) {
                try {
                    intList.add(Integer.parseInt(strNum.trim()));
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(intList);

            //You can even get an array out of the list as follows:
            Integer[] nums = intList.toArray(new Integer[0]);
            System.out.println(Arrays.toString(nums));
        }
    }
}

您也可以按如下方式执行此操作：

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner=new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if(scanner.hasNextInt()) {
            n=scanner.nextInt();
        }
        num=new int[n];
        for(int i=0;i<n;i++) {
            System.out.printf("Enter integer %d: ",i+1);
            if(scanner.hasNextInt()) {
                num[i]=scanner.nextInt();
            }           
        }
        System.out.println(Arrays.toString(num));
    }
}

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner = new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if (scanner.hasNextInt()) {
            n = scanner.nextInt();
            scanner.nextLine();
        }
        num = new int[n];
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (int i = 0; i < n; i++) {
                try {
                    num[i] = Integer.parseInt(strNums[i]);
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(Arrays.toString(num));
        }
    }
}

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        List <Integer> intList=new ArrayList<Integer>();
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (String strNum: strNums) {
                try {
                    intList.add(Integer.parseInt(strNum.trim()));
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(intList);

            //You can even get an array out of the list as follows:
            Integer[] nums = intList.toArray(new Integer[0]);
            System.out.println(Arrays.toString(nums));
        }
    }
}

但是，如果希望整数的数量不受限制，则应使用

列表

而不是数组（因为数组的大小在初始化时是固定的），如下所示：

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner=new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if(scanner.hasNextInt()) {
            n=scanner.nextInt();
        }
        num=new int[n];
        for(int i=0;i<n;i++) {
            System.out.printf("Enter integer %d: ",i+1);
            if(scanner.hasNextInt()) {
                num[i]=scanner.nextInt();
            }           
        }
        System.out.println(Arrays.toString(num));
    }
}

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int[] num;
        Scanner scanner = new Scanner(System.in);
        System.out.print("How many integers you want to enter: ");
        int n = 0;
        if (scanner.hasNextInt()) {
            n = scanner.nextInt();
            scanner.nextLine();
        }
        num = new int[n];
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (int i = 0; i < n; i++) {
                try {
                    num[i] = Integer.parseInt(strNums[i]);
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(Arrays.toString(num));
        }
    }
}

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        List <Integer> intList=new ArrayList<Integer>();
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter the integers separated by a space: ");
        String[] strNums = null;
        if (scanner.hasNextLine()) {
            strNums = scanner.nextLine().split(" ");
        }
        if (strNums != null) {
            for (String strNum: strNums) {
                try {
                    intList.add(Integer.parseInt(strNum.trim()));
                } catch (Exception e) {
                    System.out.println("Invalid input");
                    break;
                }
            }
            System.out.println(intList);

            //You can even get an array out of the list as follows:
            Integer[] nums = intList.toArray(new Integer[0]);
            System.out.println(Arrays.toString(nums));
        }
    }
}

---

祝你一切顺利

到目前为止你试过什么？你能给我们看一些代码吗？如果你不知道要存储多少个数字，你应该使用

ArrayList

而不是

int[]

。数组不是动态的。这意味着它们在运行时的大小是固定的。这意味着，如果您不总是要求用户提供相同数量的项目，那么这就不是理想的数据结构。查看java数组列表，我认为这个问题特别要求用户不输入他们输入的整数数量。在回答中，您要求用户输入该值。如果我们知道价值观的数量，我们就不会问这个问题。谢谢，你发布的第三个程序成功了