Java 事务提交异常_Java_Hibernate_Transactions

Java 事务提交异常

java hibernate transactions

Java 事务提交异常,java,hibernate,transactions,Java,Hibernate,Transactions,我使用以下代码开始并提交事务 final static Object lock = new Object(); @Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = Exception.class) public String addRequest(String actionCode) throws Exception { synchronized (this.getClass

我使用以下代码开始并提交事务

final static Object lock = new Object();
@Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = Exception.class)
public String addRequest(String actionCode) throws Exception {
    synchronized (this.getClass()) {

        Session session = dao.getCurrentSession();
        try {
            System.out.println("start");

            Transaction tr = session.getTransaction();
            tr.begin();

            certRequest
                    .setRequestNbr(generateRequestNumber(certInsuranceRequestAddRq
                            .getAccountInfo().getAccountNumberId()));
            reqId = Utils.getUniqueId();
            certRequest.setRequestId(reqId);

            ItemIdInfo itemIdInfo = new ItemIdInfo();

            itemIdInfo.setInsurerId(certRequest.getRequestId());

            certRequest.setItemIdInfo(itemIdInfo);

            Serializable it = session.save(certRequest);
            if (it != null) {
                addAccountRel();

                System.out.println("\n \n Transaction value is as " + it);
                if (!tr.wasCommitted())
                    tr.commit();
                System.out.println("\n \n Refresh value is "
                        + generateRequestNumber(certInsuranceRequestAddRq
                                .getAccountInfo().getAccountNumberId()));


    }
        } catch (HibernateException e) {
            e.printStackTrace();
        } finally {
            session.close();
        }
        System.out.println("end1");
    }
    return reqId;
}

然而，我得到了以下例外

org.springframework.transaction.TransactionSystemException: Could not commit Hibernate transaction; nested exception is org.hibernate.TransactionException: Transaction not successfully started
    at org.springframework.orm.hibernate3.HibernateTransactionManager.doCommit(HibernateTransactionManager.java:660)
    at org.springframework.transaction.support.AbstractPlatformTransactionManager.processCommit(AbstractPlatformTransactionManager.java:754)
    at org.springframework.transaction.support.AbstractPlatformTransactionManager.commit(AbstractPlatformTransactionManager.java:723)
    at org.springframework.transaction.interceptor.TransactionAspectSupport.commitTransactionAfterReturning(TransactionAspectSupport.java:393)
    at org.springframework.transaction.aspectj.AbstractTransactionAspect.ajc$afterReturning$org_springframework_transaction_aspectj_AbstractTransactionAspect$3$2a73e96c(AbstractTransactionAspect.aj:82)
    at com.csc.exceed.uow.RequestAddUOW.addRequest(RequestAddUOW.java:405)
    at com.csc.exceed.uow.RequestAddUOW.invokeService(RequestAddUOW.java:82)
    at resources.rules.uow.Rule_Add_Request_0.defaultConsequence(Rule_Add_Request_0.java:7)
    at resources.rules.uow.Rule_Add_Request_0DefaultConsequenceInvoker.evaluate(Rule_Add_Request_0DefaultConsequenceInvoker.java:29)
    at org.drools.common.DefaultAgenda.fireActivation(DefaultAgenda.java:917)
    at org.drools.common.DefaultAgenda.fireNextItem(DefaultAgenda.java:856)
    at org.drools.common.DefaultAgenda.fireAllRules(DefaultAgenda.java:1071)
    at org.drools.common.AbstractWorkingMemory.fireAllRules(AbstractWorkingMemory.java:785)
    at org.drools.common.AbstractWorkingMemory.fireAllRules(AbstractWorkingMemory.java:761)
    at org.drools.impl.StatefulKnowledgeSessionImpl.fireAllRules(StatefulKnowledgeSessionImpl.java:226)
    at com.csc.exceed.infrastructure.BusinessProcessManager.executeRules(BusinessProcessManager.java:35)
    at com.csc.exceed.infrastructure.BusinessProcessManager.executeUOWSequence(BusinessProcessManager.java:72)
    at com.csc.exceed.controller.RequestHandler.service(RequestHandler.java:169)
    at com.csc.exceed.controller.ControllerServlet.doPost(ControllerServlet.java:54)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
    at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
    at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
    at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
    at java.lang.Thread.run(Thread.java:619)
Caused by: org.hibernate.TransactionException: Transaction not successfully started
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:131)
    at org.springframework.orm.hibernate3.HibernateTransactionManager.doCommit(HibernateTransactionManager.java:656)
    ... 32 more


 error msz is Could not commit Hibernate transaction; nested exception is org.hibernate.TransactionException: Transaction not successfully started

我也试过了事务tr=session.beginTransaction（）

代替“Transaction tr=session.getTransaction（）；

但这也不起作用。请建议

编写事务同步代码很困难，一旦开始将应用程序部署到多个服务器，就会失败。要解决此问题，请使用适当的方法进行交易

首先，删除所有事务和会话管理代码以及不需要的同步内容。接下来，只需使用

@Transactional（isolation=SERIALIZABLE）

注释您的方法，即可在数据库级别进行锁定，无论您拥有多少个应用程序服务器，锁定都会起作用

@Transactional(isolation=SERIALIZABLE, rollbackFor = Exception.class)
public String addRequest(String actionCode) throws Exception {

    Session session = dao.getCurrentSession();
    System.out.println("start");

    certRequest
                .setRequestNbr(generateRequestNumber(certInsuranceRequestAddRq
                        .getAccountInfo().getAccountNumberId()));
    reqId = Utils.getUniqueId();
    certRequest.setRequestId(reqId);

    ItemIdInfo itemIdInfo = new ItemIdInfo();

    itemIdInfo.setInsurerId(certRequest.getRequestId());

    certRequest.setItemIdInfo(itemIdInfo);

    Serializable it = session.save(certRequest);
    if (it != null) {
            addAccountRel();
            System.out.println("\n \n Transaction value is as " + it);
            System.out.println("\n \n Refresh value is "
                    + generateRequestNumber(certInsuranceRequestAddRq
                            .getAccountInfo().getAccountNumberId()));
    }
    System.out.println("end1");
    return reqId;
}

在我看来，您的代码似乎也有缺陷，因为

reqId

和

certRequest

是实例变量，我没有看到它们被传递到方法中。出于某种原因，我认为您两次生成一个

requestNumber

，一次在

if

语句外部，一次在

if

语句内部，这也是错误的。

您试图创建一个新的事务，但您似乎说的是Spring来处理该事务。要么你做，要么它做

从您在帖子上的评论/链接中，我了解到您有一些肮脏的阅读，不允许您实现您想要的。您的
隔离。可序列化的将在这方面帮助您无论M.Deinum发布了什么都是正确的。不要。。。Spring正在管理事务，请从代码中删除所有事务会话管理逻辑。只需执行sessionFactory.getCurrentSession 完成你的事情，然后就可以了。这就是@Transactional 的全部要点。嗨@M.Deinum，我正在努力解决以下问题。这就是我应用事务逻辑的原因。如果我从我的代码中删除事务逻辑，你能建议一些替代解决方案吗？@pkn1230如果（it！=null）{
使用
@Transactional（隔离=SERIALIZABLE），你必须在的情况下添加一个roleback 。不要尝试在代码中修复此问题，因为这将始终失败，您可能可以为单个节点修复此问题，但一旦您将其部署到多台计算机上，它将不再工作。请使用数据库解决此问题。generateRequestNumber 实际上在做什么？（但在其他线程中可能更合适）.Hi@M.Deinum，我已经从Java代码中删除了事务和会话逻辑。但是现在发生的是，我的一个线程执行成功，而另一个线程执行了“Hibernate-flushing”例外。毫无例外，这条评论没有多大作用……将它添加到你的问题中，或者开始一个新的问题。我在回答中表达了几个问题，你能回答这些问题吗，以及你的课程在多个层面上似乎有错吗？嗨@M.Deinum，请在没有cl的地方找到新问题以及你的问题的澄清arification.您的服务存在缺陷，因为您似乎正在保留实例状态…不要这样做。请您澄清保留“实例状态…”是什么意思？