Blowfish的java和Python实现产生不同的结果
我有一个用java实现的传统blowfish,我正在尝试将其移植到Python 爪哇: Python:Blowfish的java和Python实现产生不同的结果,java,python-3.x,pycrypto,blowfish,Java,Python 3.x,Pycrypto,Blowfish,我有一个用java实现的传统blowfish,我正在尝试将其移植到Python 爪哇: Python: from Crypto.Cipher import Blowfish import binascii def encrypt(encr_str, key_str): cipher = Blowfish.new(key_str, Blowfish.MODE_ECB) return binascii.hexlify(cipher.encrypt(encr_str)).decode
from Crypto.Cipher import Blowfish
import binascii
def encrypt(encr_str, key_str):
cipher = Blowfish.new(key_str, Blowfish.MODE_ECB)
return binascii.hexlify(cipher.encrypt(encr_str)).decode('utf-8')
如果要加密的字符串为“12345678”,密钥为“1234567890123456”,则java代码输出“E00723BBB58234A”,python代码输出“61d2570dc6e09632”
因为java代码是遗留的,所以我不能碰它。表示pycrypto对河豚的实现存在问题。但是,我可以确认接受的答案是有效的。不知道为什么。我尝试了pycrypto和pycrypto,结果相同
你知道如何在Python中复制与传统java代码相同的河豚输出吗?所有这些都归功于@Kai Iskratsch指出了正确的方向 参考: 这是对我有用的代码 Python:
from Crypto.Cipher import Blowfish
from binascii import hexlify
def encrypt(key, string):
"""
Encrypts input string using BlowFish-Compat ECB algorithm.
:param key: secret key
:param string: string to encrypt
:return: encrypted string
"""
cipher = Blowfish.new(key, Blowfish.MODE_ECB)
return hexlify(_reverse_bytes(cipher.encrypt(_reverse_bytes(string)))).decode('utf-8')
@staticmethod
def _reverse_bytes(data):
"""
Takes data and reverses byte order to fit blowfish-compat format. For example, using _reverse_bytes('12345678')
will return 43218765.
:param data as bytes
:return: reversed bytes
"""
data_size = 0
for n in data:
data_size += 1
reversed_bytes = bytearray()
i = 0
for x in range(0, data_size // 4):
a = (data[i:i + 4])
i += 4
z = 0
n0 = a[z]
n1 = a[z + 1]
n2 = a[z + 2]
n3 = a[z + 3]
reversed_bytes.append(n3)
reversed_bytes.append(n2)
reversed_bytes.append(n1)
reversed_bytes.append(n0)
return bytes(reversed_bytes)
您的java代码似乎使用了河豚的ECB模式。您是否检查了pyhon是否也在ECB模式下运行,而不是在CBC或其他模式下运行?我使用的是
cipher=blowfish.new(key\u str,blowfish.mode\u ECB)
。这不是将python河豚设置为ECB模式吗?是的,你是对的,在我自己检查了一下之后,我认为python实际上为河豚生成了正确的结果。java似乎是河豚紧凑型什么是河豚紧凑型?请你详细说明一下好吗?有没有一种方法可以在python上实现这一点?以前从未听说过,但现在我已经在测试时选择作为选项的工具中看到了它。它似乎是由一个bug创建的,当时有人并没有按照算法的规定在河豚加密中使用big-endian字节顺序。这里已经有一个问题了:
from Crypto.Cipher import Blowfish
from binascii import hexlify
def encrypt(key, string):
"""
Encrypts input string using BlowFish-Compat ECB algorithm.
:param key: secret key
:param string: string to encrypt
:return: encrypted string
"""
cipher = Blowfish.new(key, Blowfish.MODE_ECB)
return hexlify(_reverse_bytes(cipher.encrypt(_reverse_bytes(string)))).decode('utf-8')
@staticmethod
def _reverse_bytes(data):
"""
Takes data and reverses byte order to fit blowfish-compat format. For example, using _reverse_bytes('12345678')
will return 43218765.
:param data as bytes
:return: reversed bytes
"""
data_size = 0
for n in data:
data_size += 1
reversed_bytes = bytearray()
i = 0
for x in range(0, data_size // 4):
a = (data[i:i + 4])
i += 4
z = 0
n0 = a[z]
n1 = a[z + 1]
n2 = a[z + 2]
n3 = a[z + 3]
reversed_bytes.append(n3)
reversed_bytes.append(n2)
reversed_bytes.append(n1)
reversed_bytes.append(n0)
return bytes(reversed_bytes)