Java 将整数[]保存为数组

我试图找出如何将方法的返回值

Integer[]{longest，count，mably}

保存为局部变量，并使用局部变量作为返回值

我遇到的一个问题是，当我编译代码时，我得到一个错误，int不能转换为boolean，它在return语句中引用了“可能”

private Integer[] longestLength(int col, int row, boolean color) 
    {
        // longest equals length of the longest pattern of the same color
        // count equals number of the longest pattern of the same color
        // possible equals number of spots, that you can play off of.
        int longest = 0;
        int count = 0;
        int possible = 0; 

        //this for loop counts to 4, the patterns of the 4 possible wins
        for (int i = 1; i <= 4; i++) {
            //lengthOfColor saves the lengthOfColor() method to avoid calling it multiple times throughout longestLength.
            Integer[] lengthOfColor = lengthOfColor(col, row, i, color);
            int length = lengthOfColor[0];
            //if a new longest is found, its new value is now set to itself
            if (length > longest) {
                longest = length;
                count = 0;
                possible = lengthOfColor[1];
            }
            //if length is the same as longest, we increase the count, and make possible equal too the larger one
            if (longest != 0 && length == longest) {
                count++;
                possible = Math.max(lengthOfColor[1], possible);
            }
        }
        return new Integer[]{longest, count, possible};   
    }

最简单的解决方案：

return new Integer[]{longest, count, possible? 1 : 0}; 

但一般来说，创建新的帮助器类是个好主意：

class LongestLengthRersponse{
     private int longest;
     private int count;
     private boolean possible;
     //constructor, and getters

---

弄明白了，我想努力。我只需要在返回整数之前保存它，这样以后就更容易访问它，并且有一个名称

Integer[] longestLengthArray = new Integer[]{longest, count, possible};
        return longestLengthArray; 

---

您在哪一行得到错误。我怀疑问题实际上来自您的

lengthOfColor

方法。可能是

int

而不是

boolean

。正如codebender评论的那样，可能是int，1:0到底是什么mean@Brentonr25查找“三元运算符”。

Integer[] longestLengthArray = new Integer[]{longest, count, possible};
        return longestLengthArray;