Java 函数只返回偶数
我的程序应该打印给定数字的所有百分比。在我添加一个为结果着色的函数(红色为低,绿色为高)之前,它工作得很好。现在它只打印奇数或偶数,但不能同时打印两者。至于颜色,它是反向工作的,从绿色到红色。我希望所有的结果打印出来,并根据它们的价值进行着色 这是密码Java 函数只返回偶数,java,for-loop,colors,Java,For Loop,Colors,我的程序应该打印给定数字的所有百分比。在我添加一个为结果着色的函数(红色为低,绿色为高)之前,它工作得很好。现在它只打印奇数或偶数,但不能同时打印两者。至于颜色,它是反向工作的,从绿色到红色。我希望所有的结果打印出来,并根据它们的价值进行着色 这是密码 public class Window extends JFrame implements ActionListener{ private JButton theButton = new JButton("Calculer sur 100");
public class Window extends JFrame implements ActionListener{
private JButton theButton = new JButton("Calculer sur 100");
private JEditorPane text = new JEditorPane();
private JTextField textField = new JTextField("Écrire un nombre");
private JScrollPane scroller = new JScrollPane(text);
private StringBuilder sb = new StringBuilder();
private Style style;
public Window() {
setLayout(new BorderLayout());
setTitle("Test");
setSize(400, 500);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setLocationRelativeTo(null);
text.setContentType("text/html");
theButton.addActionListener(this);
getContentPane().add(scroller, BorderLayout.CENTER);
getContentPane().add(textField, BorderLayout.NORTH);
getContentPane().add(theButton, BorderLayout.SOUTH);
setVisible(true);
}
/**
* Prints the result on text
* @param num
*/
private void print100(int num) {
for (int i = 1; i < num + 1; i++) {
text.setText(appendString(i));
}
}
/**
* Color from red to green according to the result
* @param a
* @return a haxaecimal to color the answer
*/
private String colorOnDigit(double a) {
double green, red;
int g, r;
double power = a;
int blue = 0;
green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));
int precision = 10; //Number of zero = number of digits
green = Math.floor(green * precision + .5) / precision;
red = Math.floor(red * precision + .5) / precision;
r = (int) red;
g = (int) green;
String hex = String.format("#%02x%02x%02x", r, g, blue);
System.out.println("blue " + blue);
System.out.println("Green " + green);
System.out.println("Red " + red);
System.out.println("----------");
return "<font color = \"" + hex + ">";
}
/**
* convert the number to string
* @param i
* @return a string that contains the information
*/
private String appendString(int i){
double a = doMath(i, checkForNumber());
String s = "<br>" + colorOnDigit(a) + i + " : " + a + "</font>";
return sb.append(s).toString();
}
/**
* Check if the text in the text is numbers
* return numl
*/
private int checkForNumber() {
int numl;
try {
numl = Integer.parseInt(textField.getText());
} catch (NumberFormatException e) {
text.setText("Essayer avec des nombres...");
return 0;
}
return numl;
}
/**
* leave specific number of digit after the dot
* return myNum
*/
private double doMath(int i, int num) {
double myNum = ((double) i / num) * 100;
int precision = 100; //Number of zero = number of digits
myNum = Math.floor(myNum * precision + .5) / precision;
return myNum;
}
public void actionPerformed(ActionEvent e) {
if (e.getSource() == theButton) {
text.setText("");
print100(checkForNumber());
}
}
为了测试,我将您的应用程序稍微更改为一个简单的Java应用程序。我通过模拟
textField
中的输入来测试这个程序(修改为print100
方法的参数)
然而,程序给出了从1到100的正常输出,没有跳过奇数,偶数12作为print100
方法的参数
无论如何,您应该将colorOnDigit的最后一行更改为return”“代码>。缺少结束双引号(应该包含在结果HTML标记中)。
我认为这可能是输出中缺少奇数标记的原因
public class OneHundred {
/**
* leave specific number of digit after the dot
* return myNum
*/
private static double doMath(int i, int num) {
double myNum = ((double) i / num) * 100;
int precision = 100; //Number of zero = number of digits
myNum = Math.floor(myNum * precision + .5) / precision;
return myNum;
}
/**
* Color from red to green according to the result
* @param a
* @return a haxaecimal to color the answer
*/
private static String colorOnDigit(double a) {
double green, red;
int g, r;
double power = a;
int blue = 0;
green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));
int precision = 10; //Number of zero = number of digits
green = Math.floor(green * precision + .5) / precision;
red = Math.floor(red * precision + .5) / precision;
r = (int) red;
g = (int) green;
String hex = String.format("#%02x%02x%02x", r, g, blue);
System.out.println("blue " + blue);
System.out.println("Green " + green);
System.out.println("Red " + red);
System.out.println("----------");
return "<font color = \"" + hex + "\">";
}
/**
* convert the number to string
* @param i
* @return a string that contains the information
*/
private static String appendString(StringBuilder b, int i, int input){
double a = doMath(i, input /* assumed an arbitrary input*/ );
String s = "<br>" + colorOnDigit(a) + i + " : " + a + "</font>\n";
return b.append(s).toString();
}
private static String print100(int num) {
StringBuilder text = new StringBuilder();
for (int i = 1; i < 100 + 1; i++) {
appendString(text, i, num);
}
return text.toString();
}
/**
* @param args
*/
public static void main(String[] args) {
String l = print100(7);
System.err.println(l);
}
}
公共类100{
/**
*在点后留下具体数字
*返回八哥
*/
私有静态双域(inti,intnum){
双myNum=((双)i/num)*100;
int precision=100;//零位数=位数
myNum=数学地板(myNum*精度+0.5)/精度;
返回myNum;
}
/**
*根据结果将颜色从红色变为绿色
*@param a
*@返回一个haxaecimal来着色答案
*/
专用静态字符串colorOnDigit(双a){
重瓣绿色,红色;
int g,r;
双功率=a;
int蓝色=0;
绿色=255*Math.sqrt(Math.cos(power*Math.PI/200));
红色=255*Math.sqrt(Math.sin(power*Math.PI/200));
int precision=10;//零位数=位数
绿色=数学地板(绿色*精度+0.5)/精度;
红色=数学地板(红色*精度+0.5)/精度;
r=(int)红色;
g=(int)绿色;
字符串十六进制=String.format(#%02x%02x%02x),r,g,蓝色);
系统输出打印项次(“蓝色”+蓝色);
System.out.println(“绿色”+绿色);
系统输出打印项次(“红色”+红色);
System.out.println(“--------------”;
返回“”;
}
/**
*将数字转换为字符串
*@param i
*@返回包含信息的字符串
*/
私有静态字符串appendString(StringBuilder b、int i、int input){
double a=doMath(i,input/*假设为任意输入*/);
字符串s=“
”+colorOnDigit(a)+i+:“+a+”\n”;
返回b.append.toString();
}
私有静态字符串print100(int num){
StringBuilder text=新的StringBuilder();
对于(int i=1;i<100+1;i++){
追加字符串(文本,i,num);
}
返回text.toString();
}
/**
*@param args
*/
公共静态void main(字符串[]args){
字符串l=print100(7);
系统错误println(l);
}
}
如果以前一切正常,为什么不把这两个版本区别开来,看看你在添加颜色变化时无意中引入了什么变化呢?@mars我只添加了函数colorOnDigit
,然后它就被窃听了。当一开始不知道代码应该做什么时,很难告诉别人代码中有什么问题。你没有真正解释这个计划的目的。它试图解决什么问题。商业规则是什么?等等。请澄清。@hfontanez我的程序应该打印一组的所有百分比。第一行。但更明确地说,它需要一个给定的数字,它给出了集合中所有的百分比(这有点难以解释,因为我的母语不是英语)。我把我的问题编辑得更具体一些。我找到了解决方案的一部分,但我不知道如何解决它。有时绿色或红色的值为NaN。根据它的意思,这不是一个数字。所以我可能在做一些我不应该做的算术。现在问题在哪里。你是对的,只是少了一个\。我现在觉得自己有点迟钝:P。非常感谢你的回答。不客气。我真的很高兴我能帮上忙。
public class OneHundred {
/**
* leave specific number of digit after the dot
* return myNum
*/
private static double doMath(int i, int num) {
double myNum = ((double) i / num) * 100;
int precision = 100; //Number of zero = number of digits
myNum = Math.floor(myNum * precision + .5) / precision;
return myNum;
}
/**
* Color from red to green according to the result
* @param a
* @return a haxaecimal to color the answer
*/
private static String colorOnDigit(double a) {
double green, red;
int g, r;
double power = a;
int blue = 0;
green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));
int precision = 10; //Number of zero = number of digits
green = Math.floor(green * precision + .5) / precision;
red = Math.floor(red * precision + .5) / precision;
r = (int) red;
g = (int) green;
String hex = String.format("#%02x%02x%02x", r, g, blue);
System.out.println("blue " + blue);
System.out.println("Green " + green);
System.out.println("Red " + red);
System.out.println("----------");
return "<font color = \"" + hex + "\">";
}
/**
* convert the number to string
* @param i
* @return a string that contains the information
*/
private static String appendString(StringBuilder b, int i, int input){
double a = doMath(i, input /* assumed an arbitrary input*/ );
String s = "<br>" + colorOnDigit(a) + i + " : " + a + "</font>\n";
return b.append(s).toString();
}
private static String print100(int num) {
StringBuilder text = new StringBuilder();
for (int i = 1; i < 100 + 1; i++) {
appendString(text, i, num);
}
return text.toString();
}
/**
* @param args
*/
public static void main(String[] args) {
String l = print100(7);
System.err.println(l);
}
}