Java 解析查询SQL喜欢匹配开括号和闭括号

我有一根这样的绳子

((one = WORD) AND (two != 2) AND (three > 3) AND (four >= 4) AND (five < 5) AND (six <= 6) AND (seven IN (seven1, seven2)) AND (eight LIKE 'like'))

one = WORD
two != 2
three > 3
four >= 4
five < 5
six <= 6
seven IN (seven1, seven2)
eight LIKE 'like'

string = string.substring(2, string.length() - 2);
String[] split = string.split("\\) AND \\(");

for (String s : split)
    System.out.println(s);

（（一个=单词）和（两个！=2）和（三个>3）和（四个>=4）和（五个<5）和（六个<3
四>=4
五岁以下
使用中的模式，我编写了这个示例代码

String string = "((one = WORD) AND (two != 2) AND (three > 3) AND (four >= 4) AND (five < 5) AND (six <= 6) AND (seven IN (seven1, seven2)) AND (eight LIKE '1,2,3'))";

long start_time = System.currentTimeMillis();

Pattern pattern = Pattern.compile("\\(([^()]*|\\([^()]*\\))*\\)");
Matcher matcher = pattern.matcher(string);

while (matcher.find())
    System.out.println(matcher.group());

long stop_time = System.currentTimeMillis();
System.out.println("Time " + (stop_time - start_time) + "ms");

我不在我的编译器附近，所以我无法测试它，但是您是否尝试过将String
split（）
方法与
”和“
参数一起使用？这应该会返回您想要的字符串数组，然后对于每个字符串，您可以对其进行修剪并删除前导字符和尾随字符（应该是括号）如果一个值包含单词
和
？比如
（one=LAND）
这可能会引起兴趣…谢谢，请看下面我的答案。可能您可以使用不同的方法：
string = string.substring(2, string.length() - 2);
String[] split = string.split("\\) AND \\(");

for (String s : split)
    System.out.println(s);