Java JPA:映射多个关系引用了不正确的列名
这个问题与我昨天问的有关。 我在Employee和SkillSet表之间有多对多关系,每个关系都有额外的numberOfYears列Java JPA:映射多个关系引用了不正确的列名,java,jpa,orm,spring-data-jpa,Java,Jpa,Orm,Spring Data Jpa,这个问题与我昨天问的有关。 我在Employee和SkillSet表之间有多对多关系,每个关系都有额外的numberOfYears列 employeeId skillSetId numberOfYears 10 101 2 由于EmployeeSkillSet表中没有ID列,所以我使用@IdClass来定义复合键 @Entity class Employee { private @Id Long id; @OneToMany(mapped
employeeId skillSetId numberOfYears
10 101 2
由于EmployeeSkillSet表中没有ID列,所以我使用@IdClass
来定义复合键
@Entity
class Employee {
private @Id Long id;
@OneToMany(mappedBy="employeeId")
private List<EmployeeSkillSet> skillSets;
}
class SkillSet {
private @Id Long id;
}
@IdClass(EmpSkillKey.class)
@Entity
class EmployeeSkillSet {
@Id
@Column("employee_id")
private Long employeeId;
@Id
@Column("skill_id")
private @Id Long skillId;
@ManyToOne
private Employee employee;
private int numberOfYears;
}
class EmpSkillKey{
private int employeeId;
private int skillId;
}
interface EmployeeRepository extends JPARepository{
List<Employee> getEmployeesBySkillSetSkillId(long id);
}
生成的查询是这样的。(我已将其转换为员工用例,无法共享实际查询)
例外情况
WARN - SqlExceptionHelper - SQL Error: 207, SQLState: ZZZZZ
ERROR - SqlExceptionHelper - Invalid column name 'employee'.
org.hibernate.exception.GenericJDBCException: could not extract ResultSet
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:91)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.getResultSet(AbstractLoadPlanBasedLoader.java:449)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeQueryStatement(AbstractLoadPlanBasedLoader.java:202)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeLoad(AbstractLoadPlanBasedLoader.java:137)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeLoad(AbstractLoadPlanBasedLoader.java:102)
at org.hibernate.loader.collection.plan.AbstractLoadPlanBasedCollectionInitializer.initialize(AbstractLoadPlanBasedCollectionInitializer.java:100)
at org.hibernate.persister.collection.AbstractCollectionPersister.initialize(AbstractCollectionPersister.java:693)
at org.hibernate.event.internal.DefaultInitializeCollectionEventListener.onInitializeCollection(DefaultInitializeCollectionEventListener.java:92)
at org.hibernate.internal.SessionImpl.initializeCollection(SessionImpl.java:1933)
at org.hibernate.collection.internal.AbstractPersistentCollection$4.doWork(AbstractPersistentCollection.java:559)
at org.hibernate.collection.internal.AbstractPersistentCollection.withTemporarySessionIfNeeded(AbstractPersistentCollection.java:261)
at org.hibernate.collection.internal.AbstractPersistentCollection.initialize(AbstractPersistentCollection.java:555)
at org.hibernate.collection.internal.AbstractPersistentCollection.read(AbstractPersistentCollection.java:143)
at org.hibernate.collection.internal.PersistentBag.iterator(PersistentBag.java:294)
可能是我无法在同一类中定义
@Id employeeId
和@manytone employee
。但是如何解决这个问题呢?不管怎样,我找到了解决办法。注释了@ManyToOne
与@JoinColumn
的关系以及实际的列名。不确定为什么它要求将可更新
和可插入
设置为错误
。必须弄清楚我的基本知识:)
select ud.employee_id , ud.employee_id , ud.employee , ud.employee_value , rd.employee_id
from employee_skill_set ud left outer join employee rd
on ud.employee=rd.employee_id
where ud.employee_id=?
WARN - SqlExceptionHelper - SQL Error: 207, SQLState: ZZZZZ
ERROR - SqlExceptionHelper - Invalid column name 'employee'.
org.hibernate.exception.GenericJDBCException: could not extract ResultSet
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:91)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.getResultSet(AbstractLoadPlanBasedLoader.java:449)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeQueryStatement(AbstractLoadPlanBasedLoader.java:202)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeLoad(AbstractLoadPlanBasedLoader.java:137)
at org.hibernate.loader.plan.exec.internal.AbstractLoadPlanBasedLoader.executeLoad(AbstractLoadPlanBasedLoader.java:102)
at org.hibernate.loader.collection.plan.AbstractLoadPlanBasedCollectionInitializer.initialize(AbstractLoadPlanBasedCollectionInitializer.java:100)
at org.hibernate.persister.collection.AbstractCollectionPersister.initialize(AbstractCollectionPersister.java:693)
at org.hibernate.event.internal.DefaultInitializeCollectionEventListener.onInitializeCollection(DefaultInitializeCollectionEventListener.java:92)
at org.hibernate.internal.SessionImpl.initializeCollection(SessionImpl.java:1933)
at org.hibernate.collection.internal.AbstractPersistentCollection$4.doWork(AbstractPersistentCollection.java:559)
at org.hibernate.collection.internal.AbstractPersistentCollection.withTemporarySessionIfNeeded(AbstractPersistentCollection.java:261)
at org.hibernate.collection.internal.AbstractPersistentCollection.initialize(AbstractPersistentCollection.java:555)
at org.hibernate.collection.internal.AbstractPersistentCollection.read(AbstractPersistentCollection.java:143)
at org.hibernate.collection.internal.PersistentBag.iterator(PersistentBag.java:294)
@IdClass(EmpSkillKey.class)
@Entity
class EmployeeSkillSet {
@Id
@Column("employee_id")
private Long employeeId;
@Id
@Column("skill_id")
private @Id Long skillId;
@JoinColumn(name="employee_id", insertable=false, updatable=false)
@ManyToOne
private Employee employee;
private int numberOfYears;
}