Java hibernate中的单表策略继承

我将使用三个简单的

Person

、

Teacher

和

Student

类在hibernate中进行简单的继承

这是我的父类（

Person.java

）

我的

Teacher.java

Class:

@Entity
@DiscriminatorValue(value = "Teacher")
public class Teacher extends Person implements Serializable {

    private String teacherDegree;

    public String getTeacherDegree() {
        return teacherDegree;
    }

    public void setTeacherDegree(String teacherDegree) {
        this.teacherDegree = teacherDegree;
    }
}

还有我的

Student.java

课程：

@Entity
@DiscriminatorValue(value = "Student")
public class Student extends Person implements Serializable {

    private String studentCollege;

    public String getStudentCollege() {
        return studentCollege;
    }

    public void setStudentCollege(String studentCollege) {
        this.studentCollege = studentCollege;
    }
}

休眠配置：

...
        <property name="hibernate.hbm2ddl.auto">update</property>
        <property name="hibernate.current_session_context_class">thread</property>
        <mapping class="com.abc.Person"/>
        <mapping class="com.abc.Teacher"/>
        <mapping class="com.abc.Student"/>
...

但我有一个错误：

ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Type) values ('NewYork', 'Teacher ABC', 'phd', 'Teacher')' at line 1

---

同样作为惯例，你应该遵循以下风格。我现在记不起来了，但我想你需要某种形式的转义来填补列名中的空白

@DiscriminatorColumn(name = "PERSON_TYPE" , discriminatorType = DiscriminatorType.STRING)

---

有时，遵守大多数社区的编码习惯会更容易。

不确定您是否有权（取决于您的基础数据库）使用带空格的鉴别器列名。您还可以使用hibernate属性来显示sql，这使调试更容易。..true

ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Type) values ('NewYork', 'Teacher ABC', 'phd', 'Teacher')' at line 1

@DiscriminatorColumn(name = "PERSON_TYPE" , discriminatorType = DiscriminatorType.STRING)