Java 将JSONObject转换为JSONArray时出现的问题
因此,我的应用程序有一个小错误,阻止我进行货币转换Java 将JSONObject转换为JSONArray时出现的问题,java,android,android-studio,android-json,gson,Java,Android,Android Studio,Android Json,Gson,因此,我的应用程序有一个小错误,阻止我进行货币转换 03-01 03:56:05.810 18853-18870/com.example.justin.currencyconverter20 D/JSON Parser: result: {"base":"SGD","date":"2016-02-29","rates":{"AUD":0.99576,"BGN":1.2762,"BRL":2.8316,"CAD":0.96359,"CHF":0.71217,"CNY":4.6559,"CZK":1
03-01 03:56:05.810 18853-18870/com.example.justin.currencyconverter20 D/JSON Parser: result: {"base":"SGD","date":"2016-02-29","rates":{"AUD":0.99576,"BGN":1.2762,"BRL":2.8316,"CAD":0.96359,"CHF":0.71217,"CNY":4.6559,"CZK":17.655,"DKK":4.868,"GBP":0.51276,"HKD":5.5237,"HRK":4.9764,"HUF":203.11,"IDR":9500.4,"ILS":2.7769,"INR":48.537,"JPY":80.352,"KRW":879.31,"MXN":12.92,"MYR":2.9931,"NOK":6.2018,"NZD":1.0804,"PHP":33.68,"PLN":2.8413,"RON":2.9205,"RUB":53.927,"SEK":6.0828,"THB":25.336,"TRY":2.1059,"USD":0.71047,"ZAR":11.391,"EUR":0.65253}}
03-01 03:56:05.811 18853-18870/com.example.justin.currencyconverter20 E/JSON Parser: Error parsing data org.json.JSONException: Value {"AUD":0.99576,"BGN":1.2762,"BRL":2.8316,"CAD":0.96359,"CHF":0.71217,"CNY":4.6559,"CZK":17.655,"DKK":4.868,"GBP":0.51276,"HKD":5.5237,"HRK":4.9764,"HUF":203.11,"IDR":9500.4,"ILS":2.7769,"INR":48.537,"JPY":80.352,"KRW":879.31,"MXN":12.92,"MYR":2.9931,"NOK":6.2018,"NZD":1.0804,"PHP":33.68,"PLN":2.8413,"RON":2.9205,"RUB":53.927,"SEK":6.0828,"THB":25.336,"TRY":2.1059,"USD":0.71047,"ZAR":11.391,"EUR":0.65253} at rates of type org.json.JSONObject cannot be converted to JSONArray
这是我的JSONParser:
package com.example.justin.currencyconverter20;
import android.util.Log;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLEncoder;
import java.util.HashMap;
public class JSONParser {
String charset = "UTF-8";
HttpURLConnection conn;
DataOutputStream wr;
StringBuilder result;
URL urlObj;
JSONArray Obj = null;
StringBuilder sbParams;
String paramsString;
public JSONArray makeHttpRequest(String url, String method) {
int i = 0;
if(method.equals("GET")){
try {
urlObj = new URL(url);
conn = (HttpURLConnection) urlObj.openConnection();
conn.setDoOutput(false);
conn.setRequestMethod("GET");
conn.setConnectTimeout(15000);
conn.connect();
} catch (IOException e) {
e.printStackTrace();
}
}
try {
//Receive the response from the server
InputStream in = new BufferedInputStream(conn.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("JSON Parser", "result: " + result.toString());
} catch (IOException e) {
e.printStackTrace();
}
conn.disconnect();
// try parse the string to a JSON object
try {
JSONObject jObj = new JSONObject(result.toString());
Obj = jObj.getJSONArray("rates");
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON Object
return Obj;
}
}
任何帮助都将不胜感激。注意:我对这一点还是相当陌生的,所以如果可能,请简化,非常感谢
编辑:
好的,我使用的JSON api是,我使用www.jsonlint.com将其转换为JSON格式,转换为以下JSON:
{
"base": "SGD",
"date": "2016-02-29",
"rates": {
"AUD": 0.99576,
"BGN": 1.2762,
"BRL": 2.8316,
"CAD": 0.96359,
"CHF": 0.71217,
"CNY": 4.6559,
"CZK": 17.655,
"DKK": 4.868,
"GBP": 0.51276,
"HKD": 5.5237,
"HRK": 4.9764,
"HUF": 203.11,
"IDR": 9500.4,
"ILS": 2.7769,
"INR": 48.537,
"JPY": 80.352,
"KRW": 879.31,
"MXN": 12.92,
"MYR": 2.9931,
"NOK": 6.2018,
"NZD": 1.0804,
"PHP": 33.68,
"PLN": 2.8413,
"RON": 2.9205,
"RUB": 53.927,
"SEK": 6.0828,
"THB": 25.336,
"TRY": 2.1059,
"USD": 0.71047,
"ZAR": 11.391,
"EUR": 0.65253
}
}
JSON字符串中没有JSON数组。因此,您必须获得另一个JSON对象
JSONObject ratesObject = jObj.getJSONIObject("rates");
然后您可以很容易地得到如下值
Double aud = ratesObject.getDouble("AUD");
Double bgn = ratesObject.getDouble("BGN");
如果费率为数组,则代码如下:
JSONArray Objs = jObj.getJSONArray("rates");
但字符串中有一个JSON对象“rates”:
因此,请使用下面的代码:
JSONObe Obj = jObj.getJSONObject("rates");
您可以通过以下方式访问Obj的任何字段:
Double php = Obj.getDouble("PHP");
或获取字符串类型:
String php = Obj.getString("PHP");
试试这个
public JSONObject makeHttpRequest(String url, String method) {
try {
JSONObject jObj = new JSONObject(result.toString());
JSONObject jObj2 = jObj.getJSONObject("rates");
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return jObj2;
}
首先,在尝试解析Json格式的数据时,应该能够区分JSONObject和JSONArray。这方面有很多工具,但我建议: 其次,可以使用之类的库将json格式的数据转换为java POJO类和对象。为此,您可以使用以下工具,该工具将生成使用Gson需要创建的等效POJO类: 最后,您应该在代码中进行以下更改以删除错误:
JSONObject ratesObject = jObj.getJSONIObject("rates");
String aud = ratesObject.getString("AUD");
请发布您从服务器获得的json数据,如错误消息所示,json字符串以
{
开头,这意味着它是一个json对象而不是数组,您需要将其解析为一个对象而不是数组,rates是json对象而不是数组使用json数据进行更新//尝试将字符串解析为json对象重试{JSONObject jObj=new JSONObject(result.toString());Obj=jObj.getJSONArray(“rates”);}catch(JSONException e){Log.e(“JSON解析器”,“错误解析数据”+e.toString());}在这个try blockHmm中,在这样做之后,我得到了这个错误:03-01 04:37:22.960 19287-19335/com.example.justin.currencyconverter20 E/JSON解析器:错误解析数据org.JSON.JSONException:No value for RUNyes当然……因为JSON中没有键“RUN”。我看到的是“RON”。
JSONObject ratesObject = jObj.getJSONIObject("rates");
String aud = ratesObject.getString("AUD");