在WHERE子句中使用多个变量的Java SQL Select语句

在WHERE子句中使用多个变量的Java SQL Select语句,java,sql,sockets,jdbc,udp,Java,Sql,Sockets,Jdbc,Udp,我正在使用UDP套接字编写一个简单的程序。我需要输入患者的姓名并从数据库中检索其详细信息。患者的姓名输入到医生类中并发送到服务器类。然后,服务器类执行查询以检索患者的详细信息。问题出在SQL语句中。当我只使用变量firstname时,它工作正常,但当我放置第二个变量lastname时,PatientRecord变量为NULL 服务器类: public class Server { public static Connection con; public static Stri

我正在使用UDP套接字编写一个简单的程序。我需要输入患者的姓名并从数据库中检索其详细信息。患者的姓名输入到医生类中并发送到服务器类。然后,服务器类执行查询以检索患者的详细信息。问题出在SQL语句中。当我只使用变量firstname时,它工作正常,但当我放置第二个变量lastname时,PatientRecord变量为NULL

服务器类:

public class Server {

    public static Connection con;

    public static String PatientRecords;

    public static String QueryPatientInfo(String PatientDetails) throws SQLException {

        System.out.print("\nNew Patient query received:\n");

        String [] PatientDetArray = PatientDetails.split(",");

        String firstname,lastname;

        firstname = PatientDetArray[1];
        lastname  = PatientDetArray[2];

        System.out.println("First Name: "+ firstname);
        System.out.println("Last Name: "+ lastname);

        Statement query = con.createStatement();

        query.execute("SELECT * FROM patient WHERE FirstName = '"+firstname+"'  AND LastName = '"+lastname+"' ");

        ResultSet rs = query.getResultSet();

        String sex;
        String dob ;
        String address ;
        String occupation;
        String phoneno  ;


        if(rs != null){

            while (rs.next()){

                sex = rs.getString("Sex");
                dob = rs.getString("DOB");
                address = rs.getString("Address");
                occupation = rs.getString("Occupation");
                phoneno = rs.getString("PhoneNo");

                PatientRecords = sex + "," + dob + "," + address + "," + occupation + "," + phoneno;
            }

            System.out.print("Patient records successfully retrieved from database !\n\n");

            return PatientRecords;
        }

        else {

            System.out.print("Error occurred patient records not found !\n\n");

            return "Error occurred patient records not found !";
        }

    }

    public static void main(String[] args) throws IOException, SQLException {

        // Connecting to database - using xampp

        try
        {
            Class.forName("com.mysql.jdbc.Driver");
            con = DriverManager.getConnection("jdbc:mysql://localhost/patientrecord", "root", "");
            System.out.println("Database is connected !");

        }
        catch(Exception e)
        {
            System.out.println("Database connection error: " + e);
        }

        DatagramSocket serverSocket = new DatagramSocket(8008);

        byte[] receiveData = new byte[1024];

        byte[] sendData;

        System.out.println("Server ready and waiting for clients to connect...");

        while (true) {

            DatagramPacket receivePacket =  new DatagramPacket(receiveData, receiveData.length);

            serverSocket.receive(receivePacket);

            String PatientDetails = new String(receivePacket.getData());

            String message;

            message = QueryPatientInfo(PatientDetails);

            System.out.print(message);

            InetAddress IPAddress = receivePacket.getAddress();

            int port = receivePacket.getPort();

            sendData = message.getBytes();

            DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length, IPAddress, port);

            serverSocket.send(sendPacket);

        }
    }

}
博士班:

public class Doctor {

    public static void main(String[] args) throws IOException {


        BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));

        DatagramSocket clientSocket = new DatagramSocket();

        InetAddress IPAddress = InetAddress.getByName("localhost");

        // Creating array of bytes to send and receive packet
        byte[] sendData;

        byte[] receiveData = new byte[1024];

        String request,firstName,lastName;

        request = "query";

        System.out.print("Patient Registration");

        System.out.print("\n\nEnter Patient Details:\n");

        // User input
        System.out.print("First name: \n");

        firstName= inFromUser.readLine();

        System.out.print("Last name: \n");
        lastName = inFromUser.readLine();

        String PatientDetails = request + ","+ firstName + "," +lastName;

        sendData = PatientDetails.getBytes();

        DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length,IPAddress, 8008);

        // Send data packet to server
        clientSocket.send(sendPacket);

        DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);

        //Receive data packet from server
        clientSocket.receive(receivePacket);

        String PatientRecords =  new String(receivePacket.getData());

        //System.out.print(PatientRecords);

        String [] PatientDetArray = PatientRecords.split(",");

        String sex,dob,address,occupation,phoneno;

        sex = PatientDetArray[0];
        dob = PatientDetArray[1];
        address = PatientDetArray[2];
        occupation = PatientDetArray[3];
        phoneno = PatientDetArray[4];

        System.out.println("FROM SERVER: ");

        System.out.println("Details for patient : " + firstName + " " + lastName);
        System.out.println("Sex: " + sex);
        System.out.println("Date of birth: " +dob );
        System.out.println("Address: " + address );
        System.out.println("Occupation: " + occupation);
        System.out.println("Phone number: " + phoneno);

        clientSocket.close();

    }

}

这显然意味着下面的
WHERE
条件与任何记录都不匹配,因此不会提取任何记录。尝试直接在SQL中运行查询,查看您得到了多少条记录。或者尝试将条件从
更改为
,这会让您有所了解

WHERE FirstName = '"+firstname+"'  AND LastName = '"+lastname+"' 

BTW,您的代码对<代码> SQL注入< /代码>开放,因此考虑使用参数化查询。

当字符串有空格时可能发生这种情况,以避免这种情况,您可以使用<代码> Times()/代码>如下:

query.execute("SELECT * FROM patient WHERE FirstName = '" + firstname.trim() + 
               "'  AND LastName = '" + lastname.trim() + "' ");
您设置变量的方式不安全,它可能会导致语法错误或导致SQL注入,因此建议使用此方式。此方式更安全,因此您可以使用以下方式代替您的查询:

PreparedStatement preparedStatement = connection.prepareCall("SELECT * FROM patient WHERE FirstName = ? AND LastName = ? ");
preparedStatement.setString(1, firstname.trim());
preparedStatement.setString(2, lastname.trim());
ResultSet result = preparedStatement.executeQuery();

希望这能对您起作用。

名字和姓氏是否与数据库中的记录匹配?当然,当我在SQL中这样写名字时:“选择*来自患者,其中姓氏='david'和姓氏='john'”;它很好用。当我使用变量firstname时,它只起作用。仅当使用这两个变量时,它不起作用
System.out.println(“First Name:+firstname”);System.out.println(“姓氏:”+lastname)打印副本超过确切结果从Doctor类收到的名称,这将用于查询您说它仅适用于firstname。如果您只使用姓氏怎么办?那么它能工作吗?当手动输入名称时,查询返回良好的结果,如下所示:其中FirstName='david'和LastName='john'谢谢!!!!我使用修剪()并且它工作!!!但是,我不明白为什么有必要这样做,因为输入的名称中没有空格。