Java OOP继承作业（动物到狮子的超类继承）

我需要： 使用狮子类扩展动物类，并具有不同的特性

添加一个名为Liontype类的字段，并添加一个按权重对lion类型进行分类的方法。需要从超类派生

然后打印出来

我的代码中有错误，我一直在尝试修复它。 提前感谢您的帮助

public class Animal {
  private int numTeeth = 0;
  private boolean spots = false;
  private int weight = 0;

  public Animal(int numTeeth, boolean spots, int weight){
    this.setNumTeeth(numTeeth);
    this.setSpots(spots);
    this.setWeight(weight);
  }

  public int getNumTeeth(){
    return numTeeth;
  }

  public void setNumTeeth(int numTeeth) {
    this.numTeeth = numTeeth;
  }

  public boolean getSpots() {
    return spots;
  }

  public void setSpots(boolean spots) {
    this.spots = spots;
  }

  public int getWeight() {
    return weight;
  }

  public void setWeight(int weight) {
    this.weight = weight;
  }
}

//Extend animal class
 public class Lion extends Animal{
  public Lion (int numTeeth, boolean spots, int weight){
  super(numTeeth, spots, weight);
  //Add new attributes
    int age = 0;
    int cubs = 0;
  }

 public static void main(String args[]){
   //Create lions and assign attributes
   Lion lion1 = new Lion();
   lion1.numTeeth = 12;
   lion1.spots = 1;
   lion1. weight = 86;
   lion1.age = 7;
   lion1.cubs = 3;

    //Print attributes
    System.out.println("Lion1 attributes:");
    System.out.println("Number of teeth : " + numTeeth);
    System.out.println("Number of spots : " + spots);
    System.out.println("Weight of lion : " + weight + " kgs");
    System.out.println("Age : " + age);
    System.out.println("No of cubs : " + cubs);
    System.out.println(" ");

   Lion lion2 = new Lion();
   lion2.numTeeth = 16;
   lion2.spots = 0;
   lion2. weight = 123;
   lion2.age = 13;
   lion2.cubs = 5;

    System.out.println("Lion2 attributes:");
    System.out.println("Number of teeth : " + numTeeth);
    System.out.println("Number of spots : " + spots);
    System.out.println("Weight of lion : " + weight + " kgs");
    System.out.println("Age : " + age);
    System.out.println("No of cubs : " + cubs);
    System.out.println(" ");
}

public class Liontype{
  //Trying to get weight from another class
  public Integer getWeight()
  {
    if (weight > 120)
    {
      System.out.println("This lion is a cub");
    }
    else if (weight >= 120 && weight < 180)
    {
      System.out.println("This lion is a female");
    }
    else if (weight >= 180)
    {
      System.out.println("This lion is a male");
    }
  }
}
}


Expected outcome:

Lion attributes:
Number of teeth : 16
Spots : true
Weight of lion : 83kgs
Age : 13
No of cubs : 3
This lion is a female

---

是的，您的代码中存在许多问题，这些问题将在编译阶段获得。也许你没有正确地说明你的例子。因此，请提供您的问题的详细信息

我要指出一些显而易见的事实：

您声明了局部变量

int年龄=0； int-cubs=0

在构造函数中，它实际上没有使用新属性扩展Lion类。将这些属性作为字段添加到类Animal中：

然后根据需要在Lion类的构造函数中初始化它们

在方法public static void mainString args[]中，您试图使用 狮子类的田野年龄大，幼崽少。见第1点

Liontype类的公共整数getWeight有2个错误。首先，未定义可变权重，其次，尽管方法必须返回整数值，但缺少return语句

---

除了Dmitry指出的错误外，Lion类中的主要错误还包括：

 public static void main(String args[]){
   //Create lions and assign attributes
   Lion lion1 = new Lion();
   lion1.numTeeth = 12;
   lion1.spots = 1;
   lion1. weight = 86;
   lion1.age = 7;
   lion1.cubs = 3;

numTeeth spots weight和所有其他字段都设置为私有。您的Lion类无法直接访问这些字段。你应该用你的接球手和接球手来对付动物

在Lion中打印属性时，也要执行以下操作：

字段是对象的属性。尝试直接打印这些字段将导致编译器错误，因为这些是Lion1对象的属性。您需要像这样使用点运算符：

System.out.println("Number of Teeth" + Lion1.getNumTeeth());

---

什么错误？编译器还是运行时？请具体说明LionType resp在哪里。狮

 //Print attributes
    System.out.println("Lion1 attributes:");
    System.out.println("Number of teeth : " + numTeeth);
    System.out.println("Number of spots : " + spots);
    System.out.println("Weight of lion : " + weight + " kgs");
    System.out.println("Age : " + age);
    System.out.println("No of cubs : " + cubs);
    System.out.println(" ");

System.out.println("Number of Teeth" + Lion1.getNumTeeth());