Java 为了阻止输出包含重复对象,需要对代码进行哪些更改
程序根据对象的名称对对象进行排序。程序使用多线程,但当我使用它时,输出包含列表中第一项的副本。在添加多线程(特别是可运行)之前,程序运行良好。不过,在对列表进行排序之后,就会出现错误 这是包含排序方法的ClassRank类的一部分:Java 为了阻止输出包含重复对象,需要对代码进行哪些更改,java,multithreading,sorting,runnable,Java,Multithreading,Sorting,Runnable,程序根据对象的名称对对象进行排序。程序使用多线程,但当我使用它时,输出包含列表中第一项的副本。在添加多线程(特别是可运行)之前,程序运行良好。不过,在对列表进行排序之后,就会出现错误 这是包含排序方法的ClassRank类的一部分: public List<Student> nameOrder(List<Student> students) { //Keeps sorting until sorted. boolean notSor
public List<Student> nameOrder(List<Student> students)
{
//Keeps sorting until sorted.
boolean notSorted = true;
while (notSorted)
{
//Count keeps track of how many items are in order.
int count = 1;
for (int i = 0; i < students.size() - 1; i++)
{
//nameFront is a name ahead of the nameBehind in the list.
String nameFront = students.get(i).getName();
String nameBehind = students.get(i + 1).getName();
//Determines lexicographical relationship between the names.
if (nameFront.compareToIgnoreCase(nameBehind) > 0 )
{
Student studentFront = students.get(i);
students.set(i, students.get(i + 1));
students.set(i + 1, studentFront);
}
else if (nameFront.compareToIgnoreCase(nameBehind) == 0)
{
double frontWorth = students.get(i).pointValue();
double behindWorth = students.get(i + 1).pointValue();
if(frontWorth < behindWorth)
{
Student studentFront = students.get(i);
students.set(i, students.get(i + 1));
students.set(i + 1, studentFront);
}
}
else
{
count++;
}
try {
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
if (count == students.size())
{
notSorted = false;
}
}
return students;
}
这段代码可能会产生这样的结果,抛出一个
ConcurentModificationException
或显示未排序的ArrayList.ArrayList不能同时访问,因此您将获得一些有趣的效果。在打印结果之前,您需要等待线程的执行完成。请尝试在name.start()之后添加name.join()
代码>。为什么要在排序中休眠线程?它看起来像是冒泡排序的低效实现,而不是多线程排序。通常不允许一个线程在另一个线程迭代集合时修改集合。
List<Student> list1 = new ArrayList<Student>();
//students is the list made from extracting the data file with
//the objects
for(Student student: students)
{
list1.add(student);
}
ClassRank listNames = new ClassRank();
Thread name = new Thread(new Runnable()
{
public void run()
{
//Command to sort students alphabetically
listNames.nameOrder(list1);
}
});
name.start();
for (Student i : list1)
{
System.out.println(i.toString());
}
System.out.println();
Matthew Diaz 3.6 1420 3
Carl Baab 1.6 750 2
Connor Morgan 3.2 1260 3
Daniel Deyoung 2.8 460 3
David Navas 2.9 1450 1
Dominic Mazza 3.9 1460 3
Ethan Gieger 3.5 1310 3
George Scaglione 3.5 1300 1
Hayle Short 3.8 1410 7
Jake Orlick 4.0 1340 5
Joshua Saunders 3.5 1510 7
Matthew Diaz 3.6 1420 3
Robert Dick 3.8 1460 2
Samuel Rodriguez 3.8 1360 3