Xml Java解析

我正在尝试解析这个

.xml

文件来提取歌曲名，我已经尝试过了

public class StudentDOMParser {

    public static void main(String[] args) throws Exception {
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document document = builder.parse("itunes3.xml");

        Element root = document.getDocumentElement();
        System.out.println(root.getNodeName());
        System.out.println("============================");

        NodeList nList = document.getElementsByTagName("dict");

        //  NodeList xList = document.getElementsByTagName("student");
        // Iterate through each employee and print their details
        for (int i = 0; i < nList.getLength(); i++) {

            // Extract each individual employee
            Node node = nList.item(i);

            if (node.getNodeType() == Node.ELEMENT_NODE) {

                Element eElement = (Element) node;  
                System.out.println("song name : " + eElement.getElementsByTagName("string").item(0).getTextContent());
                //  System.out.println("song name : " + eElement.getFirstChild().getTextContent());
            }
            //System.out.println("college name : " + eElement.getElementsByTagName("Track").item(0).getTextContent());
        }
    }
}

---

关于如何解析这首歌以获得“比阳光更明亮”的歌曲名的建议使用XPath获取所需数据可能是一种更有效的选择

下面的示例使用XPath从xml获取所有plist/dict/dict/dict/string

    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();

    Document document = builder.parse(ResourceUtils.getFile("/itunes.xml").getAbsolutePath());

    Element root = document.getDocumentElement();
    System.out.println(root.getNodeName());
    System.out.println("============================");

    XPath xPath = XPathFactory.newInstance().newXPath();
    NodeList nList = (NodeList)xPath.evaluate("/plist/dict/dict/dict/string", root, XPathConstants.NODESET);
    for (int i = 0; i < nList.getLength(); ++i) {
        Element e = (Element) nList.item(i);
        String value = e.getFirstChild().getNodeValue();
        logger.info("string:" + value);
    }

公共类CustomXMLParse{
公共静态void main（字符串[]args）{
试一试{
FileInputStream file=newfileinputstream（新文件（“/home/amitparashar/Documents/itunes3.xml”）；
DocumentBuilderFactory builderFactory=DocumentBuilderFactory.newInstance（）；
DocumentBuilder=builderFactory.newDocumentBuilder（）；
Document xmlDocument=builder.parse（文件）；
XPath=XPathFactory.newInstance（）.newXPath（）；
字符串表达式=“/plist/dict/dict/dict/String[1]”；
System.out.println（表达式）；
NodeList NodeList=（NodeList）xPath.compile（expression.evaluate（xmlDocument，XPathConstants.NODESET）；
for（int i=0；i

我想你是被那个

.xml

文件卡住了吧？你不能改变吗？设计不是很好。不幸的是，我不能，我可以得到字符串值，但我想添加更多的标记，这样我可以提取更多的歌曲名称。如果我想得到一个特定的字符串，那么如果我在字符串标记中添加一个值，我将如何做到这一点？这只是常规的xpath语法。此XPath将获取具有“比阳光更明亮”的字符串/plist/dict/dict/dict/string[包含（，'Brighter'）]

    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();

    Document document = builder.parse(ResourceUtils.getFile("/itunes.xml").getAbsolutePath());

    Element root = document.getDocumentElement();
    System.out.println(root.getNodeName());
    System.out.println("============================");

    XPath xPath = XPathFactory.newInstance().newXPath();
    NodeList nList = (NodeList)xPath.evaluate("/plist/dict/dict/dict/string", root, XPathConstants.NODESET);
    for (int i = 0; i < nList.getLength(); ++i) {
        Element e = (Element) nList.item(i);
        String value = e.getFirstChild().getNodeValue();
        logger.info("string:" + value);
    }

plist
============================
Nov 20, 2015 4:40:59 PM demo.TestCode testXml
INFO: string:Brighter Than Sunshine
Nov 20, 2015 4:41:00 PM demo.TestCode testXml
INFO: string:Aqualung
Nov 20, 2015 4:41:00 PM demo.TestCode testXml
INFO: string:Aqualung

public class CustomXMLParse {
    public static void main(String[] args) {

        try {
            FileInputStream file = new FileInputStream(new File("/home/amitparashar/Documents/itunes3.xml"));
            DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = builderFactory.newDocumentBuilder();
            Document xmlDocument = builder.parse(file);
            XPath xPath = XPathFactory.newInstance().newXPath();
            String expression = "/plist/dict/dict/dict/string[1]";
            System.out.println(expression);
            NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
            for (int i = 0; i < nodeList.getLength(); i++) {
                System.out.println(nodeList.item(i).getFirstChild().getNodeValue());
            }
        } catch (Exception e) {

        }

    }
}