Java 用随机数填充我的数组?
在我的测试类中,我很难将随机数放入数组。代码是用java编写的。我不能单独做,因为最终我将不得不用多达600个值填充数组。以下是测试类:Java 用随机数填充我的数组?,java,arrays,random,int,Java,Arrays,Random,Int,在我的测试类中,我很难将随机数放入数组。代码是用java编写的。我不能单独做,因为最终我将不得不用多达600个值填充数组。以下是测试类: import java.util.Random; public class test { /** * @param args */ public static void main(String[] args) { int size = 1000; int max = 5000;
import java.util.Random;
public class test {
/**
* @param args
*/
public static void main(String[] args) {
int size = 1000;
int max = 5000;
int[] array = new int[size];
int loop = 0;
Random generator = new Random();
//Write a loop that generates 1000 integers and
//store them in the array using generator.nextInt(max)
generator.nextInt(max); //generating one
//I need to generate 1000
//So I need some kind of loop that will generate 1000 numbers.
for (int i =0; i<1000; i++)
{
generator.nextInt(max);
}
/**
* After I do this, I'll have the array, array.
* Then comes what's under this.
* THat method is for measuring the time.
* System.currentTimeMillis();,
* with this, I can collect a time for the start of the method
* and one for the end.
* Time at the end, minus the time at the start
* gets us the running time.
*/
long result;
long startTime = System.currentTimeMillis();
sort.quickSort(array, 100, array.length-1);
long endTime = System.currentTimeMillis();
result = endTime-startTime;
System.out.println("The quick sort runtime is " + result + " miliseconds");
long result2;
long startTime2 = System.currentTimeMillis();
sort.partition(array, 100, array.length-1);
long endTime2 = System.currentTimeMillis();
result2 = endTime2 - startTime2;
System.out.println("The partition runtime is "+result2 + " miliseconds");
long result3;
long startTime3 = System.currentTimeMillis();
sort.bubbleSort(array, 100);
long endTime3 = System.currentTimeMillis();
result3 = endTime3-startTime3;
System.out.println("The bubble sort runtime is "+result3 + " miliseconds");
long result4;
long startTime4 = System.currentTimeMillis();
sort.selectionSort(array, 100); //change the second number to change
//the size of an array.
long endTime4 = System.currentTimeMillis();
result4 = endTime4-startTime4;
System.out.println("The selection sort runtime is "+result4 + " miliseconds");
}
}
import java.util.Random;
公开课考试{
/**
*@param args
*/
公共静态void main(字符串[]args){
int size=1000;
int max=5000;
int[]数组=新的int[size];
int循环=0;
随机生成器=新随机();
//写一个循环,生成1000个整数和
//使用generator.nextInt(max)将它们存储在阵列中
generator.nextInt(max);//正在生成一个
//我需要生成1000个
//所以我需要一种循环,可以产生1000个数字。
对于(inti=0;i,您只需更改循环内的行即可将随机数分配给数组的当前索引
array[i] = generator.nextInt(max);
查看教程线程,了解有关创建、初始化和访问阵列的所有信息
顺便说一下,不要重复1000
,您的循环条件可能会增加到size
for (int i = 0; i < size; i++)
for(int i=0;i
自1.8以来
Arrays.setAll(array, i -> {
return generator.nextInt(max);
});
这将使用介于0(包含)和max
(独占)之间的随机数填充数组
进一步阅读:及
话虽如此,我还是喜欢使用蜥蜴比尔提供的方法,使用循环来初始化每个值。@MariaStewart你知道为什么有必要吗?问问自己:如果你不把生成的值放在数组中,它们是如何进入数组的?如果你使用代码,插入,或者我认为它“神奇地工作”。