Java 如何将ArrayList转换为不工作的JSON

我正在尝试将

ArrayList

转换为JSON对象。问题是我在任何地方都得到了相同的值

这是我的密码：

Location l = new Location((long) 1,"u222","fdfgs","morococ","2dqrg","8drgf5","8dfg");
        Location l2 = new Location((long) 1,"u222","fedsfsds","modfrococ","27","876gtfgfg85","8 25 98");
        Location l3 = new Location((long) 1,"u222","fes","morococ","27","876fghfgh85","8 25 98");

        List<Location> locs = new ArrayList<Location>();;
        locs.add(l);
        locs.add(l2);
        locs.add(l3);
        
        List<JsonValid> jsons = new ArrayList<JsonValid>();
        JsonValid jsonV = new JsonValid();

         //copying to another list to a valid format of json
        for(int i = 0 ; i<locs.size();i++)
        {
            jsonV.title = locs.get(i).city;
            jsonV.lat = locs.get(i).latitude;
            jsonV.lng = locs.get(i).longitude;
            
            jsons.add(jsonV);
            
        }
        
        System.out.println(jsons.size());
        
        gson = new Gson();
        String jsonStudents = gson.toJson(jsons);
        //Here i'm getting the same values 
        System.out.println(jsonStudents);

---

这不是我想要的！我遗漏了什么吗？

您的循环中有一个bug-您每次都在使用

jsonV

尝试将

jsonV

声明移动到循环中：

//copying to another list to a valid format of json
for(int i = 0 ; i<locs.size();i++)
{
    JsonValid jsonV = new JsonValid();
    // ...
}

//将复制到另一个列表以获得json的有效格式
对于（int i=0；i
//copying to another list to a valid format of json
for(int i = 0 ; i<locs.size();i++)
{
    JsonValid jsonV = new JsonValid();
    // ...
}