Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/java/320.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/4/maven/6.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java 数组HashMap元素到数组的ArrayList_Java_Android_Arrays_Arraylist_Hashmap - Fatal编程技术网

Java 数组HashMap元素到数组的ArrayList

Java 数组HashMap元素到数组的ArrayList,java,android,arrays,arraylist,hashmap,Java,Android,Arrays,Arraylist,Hashmap,如何在HashMaps的ArrayList中获取元素数组?我有一个带有url键的HashMap。该值是一个url地址。多个哈希映射存储在ArrayList中。我想要的是一个包含所有url字符串的数组。我对我找到的解决方案不满意,因为我认为它可以通过一些操作从ArrayList中提取出来 // Hashmap for ListView ArrayList<HashMap<String, String>> itemsList = new Arr

如何在
HashMaps
ArrayList
中获取元素数组?我有一个带有url键的HashMap。该值是一个url地址。多个
哈希映射
存储在
ArrayList
中。我想要的是一个包含所有url字符串的
数组。我对我找到的解决方案不满意,因为我认为它可以通过一些操作从
ArrayList
中提取出来

    // Hashmap for ListView        
    ArrayList<HashMap<String, String>> itemsList = new ArrayList<HashMap<String, String>>();

    // Creating JSON Parser instance
    JSONParser jParser = new JSONParser();
    jParser.execute(url); 

    try {
        JSONObject json = jParser.get();

        items = json.getJSONArray(TAG_ITEMS);
        //This is the solution that I want to optimize
        urls = new String[items.length()];

        // looping through All items
        for(int i = 0; i < items.length(); i++){
            JSONObject c = items.getJSONObject(i);

            // Storing each json item in variable
            String title = c.getString(TAG_TITLE);
            String description = c.getString(TAG_DESCRIPTION);
            String author = c.getString(TAG_AUTHOR);

            // Media is another JSONObject
            JSONObject m = c.getJSONObject(TAG_MEDIA);
            String url = m.getString(TAG_URL);

            // creating new HashMap
            HashMap<String, String> map = new HashMap<String, String>();

            // adding each child node to HashMap key => value
            map.put(TAG_TITLE, title);
            map.put(TAG_DESCRIPTION, description);
            map.put(TAG_AUTHOR, author);
            map.put(TAG_URL, url);

            // Solution
            urls[i] = url;

            // adding HashList to ArrayList
            itemsList.add(map);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    } catch (InterruptedException e) {
        e.printStackTrace();
    } catch (ExecutionException e) {
        e.printStackTrace();
    }
//ListView的Hashmap
ArrayList itemsList=新的ArrayList();
//创建JSON解析器实例
JSONParser jParser=新的JSONParser();
jParser.execute(url);
试一试{
JSONObject json=jParser.get();
items=json.getJSONArray(TAG_items);
//这是我想要优化的解决方案
URL=新字符串[items.length()];
//循环浏览所有项目
对于(int i=0;ivalue
地图放置(标签标题、标题);
地图放置(标签描述,描述);
map.put(TAG_AUTHOR,AUTHOR);
map.put(TAG_URL,URL);
//解决方案
url[i]=url;
//将哈希列表添加到ArrayList
itemsList.add(地图);
}
}捕获(JSONException e){
e、 printStackTrace();
}捕捉(中断异常e){
e、 printStackTrace();
}捕获(执行例外){
e、 printStackTrace();
}

看起来您正在构建一个表。如果您可以添加Google Guava库,您可以使用以下内容:

Table<Integer, String, String> Table = HashedBasedTable.create()
Table Table=HashedBasedTable.create()
请参阅JavaDoc:


看起来你在建一张桌子。如果您可以添加Google Guava库,您可以使用以下内容:

Table<Integer, String, String> Table = HashedBasedTable.create()
Table Table=HashedBasedTable.create()
请参阅JavaDoc:


从你的问题中我可以推断出,听起来你在尝试做以下事情

// Assuming previously declared and instantiated urls ArrayList with populated values in the nested HashMaps. 
ArrayList<HashMap<String, String>> urls;
// Create a new List using HashMap.values from urls.
List<String> urlList = new ArrayList<String>(urls.get(index).values());

请原谅我的错误变量名

从你的问题中我可以推断出,听起来你在尝试做以下事情

// Assuming previously declared and instantiated urls ArrayList with populated values in the nested HashMaps. 
ArrayList<HashMap<String, String>> urls;
// Create a new List using HashMap.values from urls.
List<String> urlList = new ArrayList<String>(urls.get(index).values());
请原谅我的错误变量名