Java 基于对另一个ArrayList的排序对ArrayList进行排序
我在一个类(Java 基于对另一个ArrayList的排序对ArrayList进行排序,java,android,arrays,sorting,arraylist,Java,Android,Arrays,Sorting,Arraylist,我在一个类(GlobalDataHolder.cardNameAndDescription)中有一个ArrayList()),我想按字母顺序对它进行排序,但在对前面提到的ArrayList()进行排序时,我也想对ArrayList()(UserBoxGlbImageAdapter.mGLBIcons)进行排序 旁注:两个数组的大小均为3(0-2) 我正在编写自己的自定义compare()方法来完成此操作,但我没有实现我所寻找的。当我单击运行排序代码的按钮时,除非我单击按钮3次,否则无法实现正确的
GlobalDataHolder.cardNameAndDescription
)中有一个ArrayList()
),我想按字母顺序对它进行排序,但在对前面提到的ArrayList()进行排序时,我也想对ArrayList()
(UserBoxGlbImageAdapter.mGLBIcons
)进行排序
旁注:两个数组的大小均为3(0-2)
我正在编写自己的自定义compare()方法来完成此操作,但我没有实现我所寻找的。当我单击运行排序代码的按钮时,除非我单击按钮3次,否则无法实现正确的顺序,尽管字符串数组列表
确实按字母顺序排序。所以我想我只需要按照数组大小的多少对数组进行排序(大约3倍)
总之,字符串和整数数据的顺序应该是相同的,因为它们依赖于它的另一个,但我不能让这两个数组都工作
这些都不管用。有人能告诉我第二个数组的排序有什么问题吗?这是我的密码:
public class SortingDialog extends DialogFragment {
@NonNull
@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {
// Create a builder to make the dialog building process easier
AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
builder.setTitle("Sorting Dialog");
builder.setSingleChoiceItems(R.array.sorting_options, 0,
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
if (i == 1) {
Toast.makeText(getActivity(), "2nd option Clicked", Toast.LENGTH_SHORT).show();
if (getActivity().getSupportFragmentManager().findFragmentByTag("GLOBAL_FRAGMENT") != null) {
sortGlobalListsBasedOnNameAndDesc();
}
}
for (int j = 0; j < GlobalDataHolder.cardNameAndDescription.size(); j++) {
Log.v("card_names", GlobalDataHolder.cardNameAndDescription.get(j));
}
}
});
builder.setPositiveButton("OK", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
createToast();
dismiss();
}
});
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
dismiss();
}
});
return builder.create();
}
private void sortGlobalListsBasedOnNameAndDesc() {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
GlobalDataHolder.cardNameAndDescription.sort(new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
int id1 = GlobalDataHolder.cardNameAndDescription.indexOf(s1);
int id2 = GlobalDataHolder.cardNameAndDescription.indexOf(s2);
if (s1.equals(s2)) {
return 0;
} else if (s1.compareToIgnoreCase(s2) > 0) { //s1 is greater
//Collections.swap(UserBoxGlbImageAdapter.mGLBIcons,id2,id1);
swap(UserBoxGlbImageAdapter.mGLBIcons,id2,id1);
swap(GlobalDataHolder.cardNameAndDescription,id2,id1);
Log.d("case1","Called 1 time");
return 1;
} else if (s1.compareToIgnoreCase(s2) < 0) { //s1 is smaller
//Collections.swap(UserBoxGlbImageAdapter.mGLBIcons,id1,id2);
swap(UserBoxGlbImageAdapter.mGLBIcons,id1,id2);
swap(GlobalDataHolder.cardNameAndDescription,id1,id2);
Log.d("case2","Called 1 time");
return -1;
} else {
return 0;
}
}
});
}
}
private void swap(List list,int objIndex1, int objIndex2) {
for (int i=0;i < list.size(); i++) {
Collections.swap(list,objIndex1,objIndex2);
UserBoxGlbImageAdapter.refreshFragmentView(UserBoxGLBFragment.getUserBoxAdapter());
}
}
private void createToast() {
Toast.makeText(getActivity(), "Cards sorted based on AVG Stats", Toast.LENGTH_SHORT).show();
}
}
公共类排序对话框扩展了DialogFragment{
@非空
@凌驾
创建对话框上的公共对话框(Bundle savedInstanceState){
//创建一个生成器,以简化对话框的生成过程
AlertDialog.Builder=新建AlertDialog.Builder(getActivity());
builder.setTitle(“排序对话框”);
builder.setSingleChoiceItems(R.array.sorting_选项,0,
新建DialogInterface.OnClickListener(){
@凌驾
公共void onClick(DialogInterface,inti){
如果(i==1){
Toast.makeText(getActivity(),“单击第二个选项”,Toast.LENGTH_SHORT.show();
if(getActivity().getSupportFragmentManager().findFragmentByTag(“全局_片段”)!=null){
SortGlobalListBasedOnNameandDesc();
}
}
对于(int j=0;j=Build.VERSION\u code.N){
GlobalDataHolder.cardNameAndDescription.sort(新的比较器(){
@凌驾
公共整数比较(字符串s1、字符串s2){
int id1=GlobalDataHolder.cardname和description.indexOf(s1);
int id2=GlobalDataHolder.cardname和description.indexOf(s2);
如果(s1等于(s2)){
返回0;
}如果(s1.compareToIgnoreCase(s2)>0){//s1大于
//swap(UserBoxGlbImageAdapter.mGLBIcons,id2,id1);
交换(UserBoxGlbImageAdapter.mGLBIcons,id2,id1);
掉期(GlobalDataHolder.CardName和Description,id2,id1);
Log.d(“案例1”,“被叫1次”);
返回1;
}else如果(s1.compareToIgnoreCase(s2)<0){//s1更小
//swap(UserBoxGlbImageAdapter.mGLBIcons,id1,id2);
交换(UserBoxGlbImageAdapter.mGLBIcons,id1,id2);
交换(GlobalDataHolder.CardName和Description,id1,id2);
日志d(“案例2”,“调用1次”);
返回-1;
}否则{
返回0;
}
}
});
}
}
专用无效交换(列表列表,int-objIndex1,int-objIndex2){
对于(int i=0;i
对索引列表而不是列表本身进行排序并不困难。从此,您可以轻松地重新排列列表
public class Test {
List<String> testStrings = Arrays.asList(new String[]{"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"});
List<Integer> testNumbers = Arrays.asList(new Integer[]{1, 2, 3, 4, 5, 6, 7, 8, 9, 10});
static <T extends Comparable<T>> List<Integer> getSortOrder(List<T> list) {
// Ints in increasing order from 0. One for each entry in the list.
List<Integer> order = IntStream.rangeClosed(0, list.size() - 1).boxed().collect(Collectors.toList());
Collections.sort(order, new Comparator<Integer>() {
@Override
public int compare(Integer o1, Integer o2) {
// Comparing the contents of the list at the position of the integer.
return list.get(o1).compareTo(list.get(o2));
}
});
return order;
}
static <T> List<T> reorder(List<T> list, List<Integer> order) {
return order.stream().map(i -> list.get(i)).collect(Collectors.toList());
}
public void test() {
System.out.println("The strings: " + testStrings);
List<Integer> sortOrder = getSortOrder(testStrings);
System.out.println("The order they would be if they were sorted: " + sortOrder + " i.e. " + reorder(testStrings, sortOrder));
List<Integer> reordered = reorder(testNumbers, sortOrder);
System.out.println("Numbers in alphabetical order of their names: " + reordered);
}
public static void main(String[] args) {
new Test().test();
System.out.println("Hello");
}
}
公共类测试{
List testStrings=Arrays.asList(新字符串[]{“一”、“二”、“三”、“四”、“五”、“六”、“七”、“八”、“九”、“十”});
List testNumbers=Arrays.asList(新的整数[]{1,2,3,4,5,6,7,8,9,10});
静态列表getSortOrder(列表列表){
//整数从0递增。列表中的每个条目对应一个整数。
List order=IntStream.rangeClosed(0,List.size()-1).boxed().collect(Collectors.toList());
Collections.sort(order,newcomparator(){
@凌驾
公共整数比较(整数o1,整数o2){
//比较整数位置处的列表内容。
返回list.get(o1).compareTo(list.get(o2));
}
});
退货单;
}
静态列表重新排序(列表、列表顺序){
returnorder.stream().map(i->list.get(i)).collect(Collectors.toList());
}
公开无效测试(){
System.out.println(“字符串:“+testStrings”);
List sortOrder=getSortOrder(testStrings);
System.out.println(“如果对它们进行排序,它们的顺序是:“+sortOrder+”,即“+reorder(testStrings,sortOrder));
列表重新排序=重新排序(TestNumber,sortOrder);
System.out.println(“按名称字母顺序排列的数字:”+重新排序