Java 使用apache commons exec运行包含多个参数的命令时出错
使用apache commons exec运行以下命令时遇到问题:Java 使用apache commons exec运行包含多个参数的命令时出错,java,sysctl,apache-commons-exec,Java,Sysctl,Apache Commons Exec,使用apache commons exec运行以下命令时遇到问题:sysctl-n net.ipv4.neigh.default.gc\u thresh3 问题是它给出了以下错误: Exception in thread "main" java.lang.RuntimeException: Could not run command [/bin/sh, -c, sysctl, -n, net.ipv4.neigh.default.gc_thresh3] at Testing.runCom
sysctl-n net.ipv4.neigh.default.gc\u thresh3
问题是它给出了以下错误:
Exception in thread "main" java.lang.RuntimeException: Could not run command [/bin/sh, -c, sysctl, -n, net.ipv4.neigh.default.gc_thresh3]
at Testing.runCommand(Testing.java:44)
at Testing.main(Testing.java:97)
Caused by: org.apache.commons.exec.ExecuteException: Process exited with an error: 1 (Exit value: 1)
at org.apache.commons.exec.DefaultExecutor.executeInternal(DefaultExecutor.java:404)
at org.apache.commons.exec.DefaultExecutor.execute(DefaultExecutor.java:166)
at org.apache.commons.exec.DefaultExecutor.execute(DefaultExecutor.java:153)
at Testing.runCommand(Testing.java:31)
... 1 more
下面是我的代码:
private String runCommand(String cmd, String params) {
CommandLine commandLine = new CommandLine(cmd);
commandLine.addArguments(params);
ByteArrayOutputStream stdout = new ByteArrayOutputStream();
ByteArrayOutputStream stderr = new ByteArrayOutputStream();
PumpStreamHandler pumpStreamHandler = new PumpStreamHandler(stdout, stderr);
ExecuteWatchdog watchdog = new ExecuteWatchdog(30000); // 30s timeout
DefaultExecutor executor = new DefaultExecutor();
executor.setStreamHandler(pumpStreamHandler);
executor.setWatchdog(watchdog);
try {
int retCode = executor.execute(commandLine);
System.out.println("Executed '" + cmd + "'\n"
+ "returnCode: " + retCode + "\n"
+ "stdout:\n" + stdout.toString() + "\n"
+ "stderr:\n" + stderr.toString());
if (retCode == 0) {
return stdout.toString();
} else {
throw new NonZeroExitStatusReturnedException(commandLine.toString(), retCode);
}
} catch (IOException e) {
throw new RuntimeException("Could not run command "+ commandLine.toString(), e);
}
}
我正在使用cmd-/bin/sh
和params--c sysctl-n net.ipv4.neigh.default.gc\u thresh3
如何使用apache commons exec运行这样的命令而不遇到此类错误?我不需要完整的解决方案。任何好的方向对我都没问题。问题是
/bin/sh
不是运行此类命令的正确路径。该命令应在以下位置执行:/sbin/sysctl
另外,不同的操作系统需要不同的运行路径。请参见
man系统控制列表
因此,cmd是-/sbin/sysctl
和params-新字符串[]{“-n”,“net.ipv4.neigh.default.gc_thresh3”}
代码如下所示:
private String runCommand(String cmd, String[] params) {
CommandLine commandLine = new CommandLine(cmd);
commandLine.addArguments(params, false);
ByteArrayOutputStream stdout = new ByteArrayOutputStream();
ByteArrayOutputStream stderr = new ByteArrayOutputStream();
PumpStreamHandler pumpStreamHandler = new PumpStreamHandler(stdout, stderr);
ExecuteWatchdog watchdog = new ExecuteWatchdog(30000); // 30s timeout
DefaultExecutor executor = new DefaultExecutor();
executor.setStreamHandler(pumpStreamHandler);
executor.setWatchdog(watchdog);
try {
int retCode = executor.execute(commandLine);
System.out.println("Executed '" + cmd + "'\n"
+ "returnCode: " + retCode + "\n"
+ "stdout:\n" + stdout.toString() + "\n"
+ "stderr:\n" + stderr.toString());
if (retCode == 0) {
return stdout.toString();
} else {
throw new NonZeroExitStatusReturnedException(commandLine.toString(), retCode);
}
} catch (IOException e) {
throw new RuntimeException("Could not run command "+ commandLine.toString(), e);
}
}