Java 如何从光标中删除唯一值
我正在开发一个应用程序,在这个应用程序中,我只应该向用户显示重复的电话联系人,这样他们就可以删除重复的联系人。 到目前为止,我可以使用以下代码显示所有联系人: 主要活动:Java 如何从光标中删除唯一值,java,android,cursor,android-contacts,Java,Android,Cursor,Android Contacts,我正在开发一个应用程序,在这个应用程序中,我只应该向用户显示重复的电话联系人,这样他们就可以删除重复的联系人。 到目前为止,我可以使用以下代码显示所有联系人: 主要活动: private void showContacts() { Cursor cursor = ContactHelper.getContactCursor(getContentResolver(),""); String[] fields = new String[]{ContactsContract.Data.DISPLAY
private void showContacts() {
Cursor cursor = ContactHelper.getContactCursor(getContentResolver(),"");
String[] fields = new String[]{ContactsContract.Data.DISPLAY_NAME};
adapter =new SimpleCursorAdapter(this,android.R.layout.simple_list_item_multiple_choice,cursor,fields,new int[]{android.R.id.text1});
listView.setAdapter(adapter);
adapter.notifyDataSetChanged(); }
public static Cursor getContactCursor(ContentResolver contactHelper,
String startsWith) {
String[] projection = { ContactsContract.CommonDataKinds.Phone._ID,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Phone.NUMBER };
Cursor cur = null;
try {
if (startsWith != null && !startsWith.equals("")) {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " like \"" + startsWith + "%\"", null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
} else {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection, null, null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
}
cur.moveToFirst();
} catch (Exception e) {
e.printStackTrace();
}
return cur;
}
private static long getContactID(ContentResolver contactHelper,
String number) {
Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI,
Uri.encode(number));
String[] projection = { ContactsContract.PhoneLookup._ID };
Cursor cursor = null;
try {
cursor = contactHelper.query(contactUri, projection, null, null,
null);
if (cursor.moveToFirst()) {
int personID = cursor.getColumnIndex(ContactsContract.PhoneLookup._ID);
return cursor.getLong(personID);
}
return -1;
} catch (Exception e) {
e.printStackTrace();
} finally {
if (cursor != null) {
cursor.close();
cursor = null;
}
}
return -1; }
ContactHelper.GetContactsCursor函数:
private void showContacts() {
Cursor cursor = ContactHelper.getContactCursor(getContentResolver(),"");
String[] fields = new String[]{ContactsContract.Data.DISPLAY_NAME};
adapter =new SimpleCursorAdapter(this,android.R.layout.simple_list_item_multiple_choice,cursor,fields,new int[]{android.R.id.text1});
listView.setAdapter(adapter);
adapter.notifyDataSetChanged(); }
public static Cursor getContactCursor(ContentResolver contactHelper,
String startsWith) {
String[] projection = { ContactsContract.CommonDataKinds.Phone._ID,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Phone.NUMBER };
Cursor cur = null;
try {
if (startsWith != null && !startsWith.equals("")) {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " like \"" + startsWith + "%\"", null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
} else {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection, null, null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
}
cur.moveToFirst();
} catch (Exception e) {
e.printStackTrace();
}
return cur;
}
private static long getContactID(ContentResolver contactHelper,
String number) {
Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI,
Uri.encode(number));
String[] projection = { ContactsContract.PhoneLookup._ID };
Cursor cursor = null;
try {
cursor = contactHelper.query(contactUri, projection, null, null,
null);
if (cursor.moveToFirst()) {
int personID = cursor.getColumnIndex(ContactsContract.PhoneLookup._ID);
return cursor.getLong(personID);
}
return -1;
} catch (Exception e) {
e.printStackTrace();
} finally {
if (cursor != null) {
cursor.close();
cursor = null;
}
}
return -1; }
如何从光标中筛选唯一值?如果可能的话,只根据电话号码保留重复的联系人?可能会这样做
try {
if (startsWith != null && !startsWith.equals("")) {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " like \"" + startsWith + "%\""
+ " AND "
+ ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " IN (SELECT " + ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " as name FROM view_data GROUP BY " +ContactsContract.CommonDataKinds.Phone.NUMBER + " HAVING COUNT(name)>1)",
null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
} else {
cur = contactHelper.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
projection,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " IN (SELECT " + ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " as name FROM view_data GROUP BY " +ContactsContract.CommonDataKinds.Phone.NUMBER + " HAVING COUNT(name)>1)",
null,
ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
+ " ASC");
}
cur.moveToFirst();
} catch (Exception e) {
e.printStackTrace();
}