Java 二进制值为';t从十进制转换为二进制后显示足够的8位
我在这里需要编码方面的帮助。我想将RGB值(十进制)转换为二进制值。但只要二进制值前面有“0”位,结果就不会显示“0”位 示例:十进制=94,二进制=0101110。但我的结果显示为1011110 我想为我的程序,图像隐写分析,分析所有的二进制位。如果没有足够的8个二进制位,恐怕会出错 以下是我的密码:Java 二进制值为';t从十进制转换为二进制后显示足够的8位,java,binary,decimal,rgb,pixel,Java,Binary,Decimal,Rgb,Pixel,我在这里需要编码方面的帮助。我想将RGB值(十进制)转换为二进制值。但只要二进制值前面有“0”位,结果就不会显示“0”位 示例:十进制=94,二进制=0101110。但我的结果显示为1011110 我想为我的程序,图像隐写分析,分析所有的二进制位。如果没有足够的8个二进制位,恐怕会出错 以下是我的密码: public class getPixelData { private static final double bitPerColor = 4.0; public getPixelData(
public class getPixelData
{
private static final double bitPerColor = 4.0;
public getPixelData()
{
}
public int[] getPixelData(BufferedImage img, int w, int h) throws IOException
{
int argb = img.getRGB(w, h);
int rgb[] = new int[]
{
(argb >> 16) & 0xff, //red
(argb >> 8) & 0xff, //green
(argb ) & 0xff //blue
};
int red = rgb[0];
int green = rgb[1]; //RGB Value in Decimal
int blue = rgb[2];
System.out.println("\nRGBValue in Decimal --> " + "\nRed: " + red + " Green: " + green + " Blue: " + blue);
//Convert each channel RGB to Hexadecimal value
String rHex = Integer.toHexString((int)(red));
String gHex = Integer.toHexString((int)(green));
String bHex = Integer.toHexString((int)(blue));
System.out.println("\nRGBValue in Hexa --> " + "\nRed Green Blue " + rHex + gHex + bHex);
//Convert each channel RGB to binary
String r4bit = Integer.toBinaryString((int)(red));
String g4bit = Integer.toBinaryString((int)(green));
String b4bit = Integer.toBinaryString((int)(blue));
//Convert concatonate 0's in front to get desired bit count
int rDifference = (int)bitPerColor - r4bit.length();
int gDifference = (int)bitPerColor - g4bit.length();
int bDifference = (int)bitPerColor - b4bit.length();
//this code should work but i guess it isn't
for (int i = rDifference; i > 0; i--)
{
r4bit = "0" + r4bit;
}
for (int i = gDifference; i > 0; i--)
{
g4bit = "0" + g4bit;
}
for (int i = bDifference; i > 0; i--)
{
b4bit = "0" + b4bit;
}
System.out.println("\nRGB Value in binary (Red) is: " + r4bit);
System.out.println("RGB Value in binary (Green) is: " + g4bit);
System.out.println("RGB Value in binary (Blue) is: " + b4bit);
return rgb;
}
}
我应该在这里添加什么代码?仅供参考,我对Java语言还是新手。如果我在这里犯了错误,请纠正我
谢谢你不需要除以幂吗
float power = Math.pow(2, 4);
String r4bit = Integer.toBinaryString((int)(red/power));
String g4bit = Integer.toBinaryString((int)(green/power));
String b4bit = Integer.toBinaryString((int)(blue/power));
您需要自己用0填充它们。如果我没弄错的话,这里有一个类似的问题:
我以前做过。它没有显示完整的8个二进制位。只显示前4个二进制位,我读过了,我不太懂代码。你能指导我如何用0位填充它吗?