Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/opencv/3.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Javascript 在脱机事件phonegap应用程序中显示div_Javascript_Jquery_Cordova_Phonegap Plugins_Phonegap - Fatal编程技术网

Javascript 在脱机事件phonegap应用程序中显示div

Javascript 在脱机事件phonegap应用程序中显示div,javascript,jquery,cordova,phonegap-plugins,phonegap,Javascript,Jquery,Cordova,Phonegap Plugins,Phonegap,我正在使用phonegap创建webview应用程序 我使用iframe方法来获取我的网站 <iframe src="http://www.google.com" id="iframe"></iframe> 反正也不行 我复习了几十个主题,但不适合我 我也试过这个,但不起作用 // offline event function checkConnection() { var networkState = navigator.network.conn

我正在使用phonegap创建webview应用程序
我使用iframe方法来获取我的网站

<iframe src="http://www.google.com" id="iframe"></iframe>
反正也不行 我复习了几十个主题,但不适合我

我也试过这个,但不起作用

// offline event
function checkConnection() {
           var networkState = navigator.network.connection.type;
           var states = {};
           states[Connection.UNKNOWN]  = 'Unknown connection';
           states[Connection.ETHERNET] = 'Ethernet connection';
           states[Connection.WIFI]     = 'WiFi connection';
           states[Connection.CELL_2G]  = 'Cell 2G connection';
           states[Connection.CELL_3G]  = 'Cell 3G connection';
           states[Connection.CELL_4G]  = 'Cell 4G connection';
           states[Connection.NONE]     = 'No network connection';

           return networkState;

       }

function onDeviceReady() {
       var networkState = checkConnection();
    /* load local files if there is not network connection */
                  if (networkState == Connection.NONE) {
                      window.location="offline.html"; 
                  } 
     }

你检查过启动的onOffline()函数了吗?@AliEsmaeili如何检查,这是我第一个使用phonegap的项目
// offline event
function checkConnection() {
           var networkState = navigator.network.connection.type;
           var states = {};
           states[Connection.UNKNOWN]  = 'Unknown connection';
           states[Connection.ETHERNET] = 'Ethernet connection';
           states[Connection.WIFI]     = 'WiFi connection';
           states[Connection.CELL_2G]  = 'Cell 2G connection';
           states[Connection.CELL_3G]  = 'Cell 3G connection';
           states[Connection.CELL_4G]  = 'Cell 4G connection';
           states[Connection.NONE]     = 'No network connection';

           return networkState;

       }

function onDeviceReady() {
       var networkState = checkConnection();
    /* load local files if there is not network connection */
                  if (networkState == Connection.NONE) {
                      window.location="offline.html"; 
                  } 
     }