Javascript 检查数组元素中的两个空格字符

如何判断数组元素是否由三个单词组成（即，其中是否有两个空格字符）？它可能看起来像“abc def ghi”。我正试图在数组中搜索此表单的元素，并将删除此表单，而其他格式为“jkl xyz”或“jkl”的元素将保留在数组中。

您可以使用类似以下的正则表达式：

/^[^\s]+\s[^\s]+\s[^\s]+$/.test("abc def def") // true
/^[^\s]+\s[^\s]+\s[^\s]+$/.test("abc def ") // false

这意味着：

^ Start of string
[^\s]+ 1 or more none space characters
\s a space character
[^\s]+ 1 or more none space characters
\s a space character
[^\s]+ 1 or more none space characters
\s a space character
$ End of string

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您可以将

搜索

功能与以下正则表达式一起使用：

str.search(/\b(\w+ \w+ \w+)\b/g);

详细阅读

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正则表达式解释：

\w+ \w+ \w+
-----------

Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “ ” literally « »
Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “ ” literally « »
Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»

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请共享您的代码-这样可以更轻松地调查您的问题所在

["jkl xyz", "gty slp"]

\w+ \w+ \w+
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Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “ ” literally « »
Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “ ” literally « »
Match a single character that is a “word character” (ASCII letter, digit, or underscore only) «\w+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»