Javascript 子集和-获取数组索引而不是值

我有以下功能：

function createSubsets(numbers, target) {
  // filter out all items larger than target
  numbers = numbers.filter(function (value) {
    return value <= target;
  });

  // sort from largest to smallest
  numbers.sort(function (a, b) {
    return b - a;
  });

  // array with all the subsets
  var result = [];

  while (numbers.length > 0) {
    var i;
    var sum = 0;
    var addedIndices = [];

    // go from the largest to the smallest number and
    // add as many of them as long as the sum isn't above target
    for (i = 0; i < numbers.length; i++) {
      if (sum + numbers[i] <= target) {
        sum += numbers[i];
        addedIndices.push(i);
      }
    }
    console.log(addedIndices);
    // remove the items we summed up from the numbers array, and store the items to result
    // since we're going to splice the numbers array several times we start with the largest index
    // and go to the smallest to not affect index position with splice.
    var subset = [];
    for (i = addedIndices.length - 1; i >= 0; i--) {
      subset.unshift(numbers[addedIndices[i]]);
      numbers.splice(addedIndices[i], 1);
    }
    result.push(subset);
  }
  return result;
}

函数创建子集（数字、目标）{
//筛选出大于目标的所有项目
数字=数字。过滤器（函数（值）{
返回值（0）{
var i；
var总和=0；
var addedices=[]；
//从最大数到最小数，然后
//只要总数不超过目标，就添加尽可能多的
对于（i=0；iif（sum+numbers[i]当你有值时，你可以找到它的索引。在开始时使用filter函数你可以创建一个新的数组，因此找到的索引将与原始的索引不匹配。你不能只做：subset.unshift（addedIndices[i]）；当您到达while循环数数组时，它不是原始数组。它是经过排序和筛选的。请记住。