Javascript 使用新数据重新加载D3力定向布局

Javascript 使用新数据重新加载D3力定向布局,javascript,d3.js,Javascript,D3.js,我使用d3力定向图布局来显示一些数据。当我双击节点旁边的名称时,我想用新数据重新渲染图形。我找到了一份工作,但对我来说并不是很好。这里的关键似乎是force.start()我正在调用的方法。到目前为止,这就是我编写的代码。它被缩短到绝对最小 var height = 600; var width = 800; var color = d3.scale.category20(); var svg = d3.select('body').append('svg').attr('width', wi

我使用d3力定向图布局来显示一些数据。当我双击节点旁边的名称时,我想用新数据重新渲染图形。我找到了一份工作,但对我来说并不是很好。这里的关键似乎是
force.start()我正在调用的方法。到目前为止,这就是我编写的代码。它被缩短到绝对最小

var height =  600;
var width = 800;
var color = d3.scale.category20();
var svg = d3.select('body').append('svg').attr('width', width).attr('height',
        height).attr("pointer-events", "all").append("g").append("g");
svg.append("rect").attr("class", "overlay").attr("width", width).attr("height", height);

function draw(json) {
    var force = self.force = d3.layout.force()
        .nodes(json.nodes)
        .links(json.links)
        .gravity(.05)
        .distance(150)
        .charge(-100)
        .size([width, height])
        .start();

    var link = svg.selectAll(".link").data(json.links).enter().append("line")
            .attr("class", "link").style("stroke-width", 1);

    var gnodes = svg.selectAll('g.gnode').data(json.nodes).enter().append('g').classed('gnode', true);


    var node = gnodes.append("circle").attr("class", "node").attr("r", 5)
            .style("fill", function(d) {
                return color(d.group);
            });

    var labels = gnodes.append("text").text(function(d) {
        return d.name;
    }).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
        redraw();
    });
    gnodes.selectAll("circle.node").on("click", function() {
        d3.select(this);
    });
    force.on("tick", tick);

    function tick() {
      link.attr("x1", function(d) { return d.source.x; })
          .attr("y1", function(d) { return d.source.y; })
          .attr("x2", function(d) { return d.target.x; })
          .attr("y2", function(d) { return d.target.y; });
      gnodes.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
    }
force.start();
};


function invoke(){
    inputString = {
            "nodes":[
                     {"concept":"man","name":"John","id":0,"shortname":"","group":2},
                     {"concept":"woman","name":"Mia","id":1,"shortname":"","group":6},
                     {"concept":"child","name":"Harry","id":2,"shortname":"","group":7},
                     {"concept":"child","name":"Sally","id":3,"shortname":"","group":7},
                     {"concept":"old women","name":"Judith","id":4,"shortname":"","group":8},
                     {"concept":"old man","name":"Lionel","id":5,"shortname":"","group":7}
                  ],
                  "links":[
                     {"source":0,"target":1,"relation":"married"},
                     {"source":0,"target":2,"relation":"father"},
                     {"source":1,"target":2,"relation":"mother"},
                     {"source":0,"target":3,"relation":"father"},
                     {"source":1,"target":3,"relation":"mother"},
                     {"source":5,"target":2,"relation":"grandfather"},
                     {"source":5,"target":3,"relation":"grandfather"},
                     {"source":4,"target":2,"relation":"grandmother"},
                     {"source":4,"target":3,"relation":"grandmother"},
                     {"source":5,"target":1,"relation":"father"},
                     {"source":4,"target":1,"relation":"mother"}
                  ]
             };
    draw(inputString);
}

function redraw(){
    inputString = {
            "nodes":[
                     {"concept":"man","name":"Alan","id":0,"shortname":"","group":2},
                     {"concept":"woman","name":"Judith","id":1,"shortname":"","group":6},
                     {"concept":"child","name":"Jack","id":2,"shortname":"","group":7},
                     {"concept":"child","name":"Rosana","id":3,"shortname":"","group":7},
                     {"concept":"old women","name":"Evelyn","id":4,"shortname":"","group":8},
                     {"concept":"old man","name":"Charlie","id":5,"shortname":"","group":7}
                  ],
                  "links":[
                     {"source":0,"target":1,"relation":"married"},
                     {"source":0,"target":2,"relation":"father"},
                     {"source":1,"target":2,"relation":"mother"},
                     {"source":0,"target":3,"relation":"father"},
                     {"source":1,"target":3,"relation":"mother"},
                     {"source":5,"target":2,"relation":"grandfather"},
                     {"source":5,"target":3,"relation":"grandfather"},
                     {"source":4,"target":2,"relation":"grandmother"},
                     {"source":4,"target":3,"relation":"grandmother"},
                     {"source":5,"target":1,"relation":"father"},
                     {"source":4,"target":1,"relation":"mother"}
                  ]
             };
    draw(inputString);
}

var inputString = undefined;

invoke();
调用双击行为的部分如下所示:

var labels = gnodes.append("text").text(function(d) {
        return d.name;
    }).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
        redraw();
});

redraw()
有新数据,应该只调用我的函数来再次绘制图形。在我看来,双击一个节点只能工作一次。即使是他们,它也会提取旧数据。我准备了一份工作,用我目前所拥有的一切
在重新渲染图形时我做错了什么?

在使用draw函数进行渲染之前,您需要删除节点和链接

function draw(json) {
  svg.selectAll(".link").remove();//add this to remove the links
  svg.selectAll(".gnode").remove();//add this to remove the nodes
...your old code.

工作代码。

谢谢,有时解决方案会如此简单,真是令人惊讶:)