Javascript 使用新数据重新加载D3力定向布局
我使用d3力定向图布局来显示一些数据。当我双击节点旁边的名称时,我想用新数据重新渲染图形。我找到了一份工作,但对我来说并不是很好。这里的关键似乎是Javascript 使用新数据重新加载D3力定向布局,javascript,d3.js,Javascript,D3.js,我使用d3力定向图布局来显示一些数据。当我双击节点旁边的名称时,我想用新数据重新渲染图形。我找到了一份工作,但对我来说并不是很好。这里的关键似乎是force.start()我正在调用的方法。到目前为止,这就是我编写的代码。它被缩短到绝对最小 var height = 600; var width = 800; var color = d3.scale.category20(); var svg = d3.select('body').append('svg').attr('width', wi
force.start()代码>我正在调用的方法。到目前为止,这就是我编写的代码。它被缩短到绝对最小
var height = 600;
var width = 800;
var color = d3.scale.category20();
var svg = d3.select('body').append('svg').attr('width', width).attr('height',
height).attr("pointer-events", "all").append("g").append("g");
svg.append("rect").attr("class", "overlay").attr("width", width).attr("height", height);
function draw(json) {
var force = self.force = d3.layout.force()
.nodes(json.nodes)
.links(json.links)
.gravity(.05)
.distance(150)
.charge(-100)
.size([width, height])
.start();
var link = svg.selectAll(".link").data(json.links).enter().append("line")
.attr("class", "link").style("stroke-width", 1);
var gnodes = svg.selectAll('g.gnode').data(json.nodes).enter().append('g').classed('gnode', true);
var node = gnodes.append("circle").attr("class", "node").attr("r", 5)
.style("fill", function(d) {
return color(d.group);
});
var labels = gnodes.append("text").text(function(d) {
return d.name;
}).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
redraw();
});
gnodes.selectAll("circle.node").on("click", function() {
d3.select(this);
});
force.on("tick", tick);
function tick() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
gnodes.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
force.start();
};
function invoke(){
inputString = {
"nodes":[
{"concept":"man","name":"John","id":0,"shortname":"","group":2},
{"concept":"woman","name":"Mia","id":1,"shortname":"","group":6},
{"concept":"child","name":"Harry","id":2,"shortname":"","group":7},
{"concept":"child","name":"Sally","id":3,"shortname":"","group":7},
{"concept":"old women","name":"Judith","id":4,"shortname":"","group":8},
{"concept":"old man","name":"Lionel","id":5,"shortname":"","group":7}
],
"links":[
{"source":0,"target":1,"relation":"married"},
{"source":0,"target":2,"relation":"father"},
{"source":1,"target":2,"relation":"mother"},
{"source":0,"target":3,"relation":"father"},
{"source":1,"target":3,"relation":"mother"},
{"source":5,"target":2,"relation":"grandfather"},
{"source":5,"target":3,"relation":"grandfather"},
{"source":4,"target":2,"relation":"grandmother"},
{"source":4,"target":3,"relation":"grandmother"},
{"source":5,"target":1,"relation":"father"},
{"source":4,"target":1,"relation":"mother"}
]
};
draw(inputString);
}
function redraw(){
inputString = {
"nodes":[
{"concept":"man","name":"Alan","id":0,"shortname":"","group":2},
{"concept":"woman","name":"Judith","id":1,"shortname":"","group":6},
{"concept":"child","name":"Jack","id":2,"shortname":"","group":7},
{"concept":"child","name":"Rosana","id":3,"shortname":"","group":7},
{"concept":"old women","name":"Evelyn","id":4,"shortname":"","group":8},
{"concept":"old man","name":"Charlie","id":5,"shortname":"","group":7}
],
"links":[
{"source":0,"target":1,"relation":"married"},
{"source":0,"target":2,"relation":"father"},
{"source":1,"target":2,"relation":"mother"},
{"source":0,"target":3,"relation":"father"},
{"source":1,"target":3,"relation":"mother"},
{"source":5,"target":2,"relation":"grandfather"},
{"source":5,"target":3,"relation":"grandfather"},
{"source":4,"target":2,"relation":"grandmother"},
{"source":4,"target":3,"relation":"grandmother"},
{"source":5,"target":1,"relation":"father"},
{"source":4,"target":1,"relation":"mother"}
]
};
draw(inputString);
}
var inputString = undefined;
invoke();
调用双击行为的部分如下所示:
var labels = gnodes.append("text").text(function(d) {
return d.name;
}).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
redraw();
});
redraw()
有新数据,应该只调用我的函数来再次绘制图形。在我看来,双击一个节点只能工作一次。即使是他们,它也会提取旧数据。我准备了一份工作,用我目前所拥有的一切
在重新渲染图形时我做错了什么?在使用draw函数进行渲染之前,您需要删除节点和链接
function draw(json) {
svg.selectAll(".link").remove();//add this to remove the links
svg.selectAll(".gnode").remove();//add this to remove the nodes
...your old code.
工作代码。谢谢,有时解决方案会如此简单,真是令人惊讶:)