Javascript 从数组JSON输入返回所有字段的JSON路径？

输入JSON数组时，我需要一个JSON路径来返回所有字段。这就像将数组JSON转换为平面JSON文件

数组JSON输入：

{
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arrayfield1": [
        {
            "arr1": "625347",
            "arr2": "rere"
        },
        {
            "arr1": "634441",
            "arr2": "sdfsd"
        }
    ]
}

[
  {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arr1": "625347",
    "arr2": "rere"
  },
  {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arr1": "634441",
    "arr2": "sdfsd"
  }
]

上述数组json必须转换为2条记录，如下所示。因此，我尝试使用json路径来实现这一点

所需输出：

{
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arrayfield1": [
        {
            "arr1": "625347",
            "arr2": "rere"
        },
        {
            "arr1": "634441",
            "arr2": "sdfsd"
        }
    ]
}

[
  {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arr1": "625347",
    "arr2": "rere"
  },
  {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arr1": "634441",
    "arr2": "sdfsd"
  }
]

我尝试的是JSON路径

$.arrayfield1*

但它只返回数组字段。如果JSON路径不是实现这一点的方法，请您建议javascript代码返回所有字段

---

谢谢。

您可能想试试这个：

var arr = {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arrayfield1": [
        {
            "arr1": "625347",
            "arr2": "rere"
        },
        {
            "arr1": "634441",
            "arr2": "sdfsd"
        }
    ],
    "arrayfield2": [
        {
            "arr1": "625347",
            "arr2": "rere"
        },
        {
            "arr1": "634441",
            "arr2": "sdfsd"
        }
    ]
};

console.log(conversion(arr));

function conversion(arr) {
    var oneLevel = {};
    var multiLevel = [];
    for(var key in arr) {
        var item = arr[key];
        if(typeof item != "object") {
            oneLevel[key] = item;
        } else {
            multiLevel = multiLevel.concat(item);
        }
    }

    for(var i in multiLevel) {
        for(var j in oneLevel) {
            multiLevel[i][j] = oneLevel[j];
        }
    }

    return multiLevel;
}

下面是测试的小提琴链接

尝试以下方法：

---

尝试使用

Array.prototype.map（）

，

作为循环中的
Array.prototype.forEach（）


var数据={
“字段1”：“ALNT12345”，
“字段2”：“ALNT345346”，
“字段3”：“2015353423”，
“字段4”：“2332124343”，
“arrayfield1”：[
{
“arr1”：“625347”，
“arr2”：“rere”
},
{
“arr1”：“634441”，
“arr2”：“sdfsd”
}
]
};
var res=data.arrayfield1.map（函数（val，键）{
var obj={}；
用于（数据中的var i）{
if（！Array.isArray（数据[i]））{
obj[i]=数据[i]
}
}
变量名称=Object.keys（val）；
name.forEach（函数（值、索引）{
obj[名称[索引]]=val[值]
})
返回obj
});
console.log（JSON.stringify（res，null，4））
试试这个：-

var x = {
    "field1": "ALNT12345",
    "field2": "ALNT345346",
    "field3": "2015353423",
    "field4": "2332124343",
    "arrayfield1": [
        {
            "arr1": "625347",
            "arr2": "rere"
        },
        {
            "arr1": "634441",
            "arr2": "sdfsd"
        }
    ]
};



var arr = [];

if(x.hasOwnProperty('arrayfield1')) {
    x.arrayfield1.forEach(function(obj1){
        var obj = JSON.parse(JSON.stringify(x));
        delete obj.arrayfield1;
        for(key in obj1) {
            obj[key] = obj1[key];
        }
        arr.push(obj);
    });
}   

console.log(arr);