Javascript 在Mongodb/Mongoose聚合中的子集内应用$cond
假设我有这个文档:Javascript 在Mongodb/Mongoose聚合中的子集内应用$cond,javascript,node.js,mongodb,mongoose,aggregation-framework,Javascript,Node.js,Mongodb,Mongoose,Aggregation Framework,假设我有这个文档: { "_id" : 1, "first_name" : "Matt", "roles": ['editor', 'publisher', 'siteAdmin'] } { "_id" : 1, "first_name" : "Harry", "roles": ['publisher', 'siteAdmin'] } { "_id" : 1, "first_name" : "Rob", "roles": ['editor'] } 现在我想使用mongoose聚合($cond)
{ "_id" : 1, "first_name" : "Matt", "roles": ['editor', 'publisher', 'siteAdmin'] }
{ "_id" : 1, "first_name" : "Harry", "roles": ['publisher', 'siteAdmin'] }
{ "_id" : 1, "first_name" : "Rob", "roles": ['editor'] }
现在我想使用mongoose聚合($cond
)来输出此文档。我怎么得到这个?我会感谢你在这方面的帮助
{ "first_name" : "Matt", "isSiteAdmin": true }
{ "first_name" : "Harry", "isSiteAdmin": true }
{ "first_name" : "Rob", "isSiteAdmin": false }
下面这样的管道应该适合您
YourModel.aggregate([
{
$project: {
_id: 0,
first_name: 1,
isSiteAdmin: {
$setIsSubset: [["siteAdmin"], "$roles"]
}
}
}
])
成功了。非常感谢你。