Javascript 忽略允许的单词的消息筛选器

我一直在尝试重做一个消息过滤器有一段时间了，我被它难住了。我有一个不同类别的不同单词的列表，过滤器会阻止这些单词，但也有一个允许单词的位置，它会忽略这些单词。这是我的代码

    for (var i in curse) {
        if(msg.includes(curse[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Profanity.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)})
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    } 

    for (var i in inap) {
        if(msg.includes(inap[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Inappropriate Content.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)})
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    }

    for (var i in encvio) {
        if(msg.includes(encvio[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Encouraging Violence or Hatred towards others.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)}) 
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    }

    for (var i in web) {
        if(msg.includes(web[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Website Links or Advertising.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)})
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    }

    for (var i in racism) {
        if(msg.includes(racism[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Racism.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)})
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    }

    for (var i in blacklistwords) {
        if(msg.includes(blacklistwords[i])) {
            const filterViolation = new Discord.RichEmbed()
            .setColor('#ff0000')
            .setAuthor(message.author.username, message.author.avatarURL)
            .setTitle('Filter Violation')
            .setDescription(`${rule} **Blacklisted Words Usage.** \n${ifcont}`)
            .setTimestamp()
            .setFooter(copyright);
            message.delete()
            message.author.send(filterViolation).then(msg => {msg.delete(30000)})
            message.channel.send(msgvio).then(msg => {msg.delete(15000)})
            logger.write(logviolation)
        } 
    }

    for (var i in allowed) {
        if(msg.includes(allowed[i])) return;
     }

---

例如，每当有人说“夜”这个词时，它都会将其视为种族主义，因为它会检查前3个字母，并将其视为种族主义，即使“夜”这个词在允许的单词列表中，也不确定我做错了什么。我试图让它忽略“夜晚”这个词（或者列表中的任何其他单词），但是继续检查这个消息。

在这个逻辑中，我有一点麻烦，但是我会考虑反转它。将消息拆分为一个单词数组，然后检查消息中的每个单词，查看它是否在黑名单中，而不在白名单中

让checkMessage=msg.split（“”）；
for（设i=0；i

有没有办法去掉标点和空格，因为我确信人们会使用“s.hit”和“s h I t”等词？你可以用正则表达式替换一个.replace（）。看起来有人在这里给出了答案：非常感谢，Tarazed:）