Javascript 如何检查数组中的对象在参数ID中是否存在ID属性?
我需要如何执行此操作的帮助,我有todos,如果参数中有todos isComplete属性的ID,我想更新数组中的todos isComplete属性,类似以下代码:Javascript 如何检查数组中的对象在参数ID中是否存在ID属性?,javascript,arrays,Javascript,Arrays,我需要如何执行此操作的帮助,我有todos,如果参数中有todos isComplete属性的ID,我想更新数组中的todos isComplete属性,类似以下代码: const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}]; const myArgs = [2,3]; const completeAl
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
const myArgs = [2,3];
const completeAllTodos = todos.filter(todoItem.id => myArgs.includes(todoItem.id));
completeAllTodos.map( todoItem => todoItem.isComplete = true);
在completeAllTodos上,我希望返回参数数组中存在ID的todos对象,然后将completeAllTodos isComplete属性更新为true。我也希望异步执行,但我是javascript新手。我已经想了好几个小时了,但是我不能让我的大脑做我想做的事情。帮助?如果您只想将isCompletes设置为true:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
todos.forEach(el=>myArgs.indexOf(el.id)+1?el.isComplete=true:0);
如果你也想要这个元素:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
var result=todos.filter(el=>myArgs.indexOf(el.id)+1).map(el=>!(el.isComplete=true)||el);
如果你两者都想要:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
var results=todos.reduce((arr,el)=>myArgs.indexOf(el.id)+1?(el.isComplete=true,arr.push(el),arr):arr);
如果您确实需要异步实现(我不这么认为):
如果您只想将isCompletes设置为true:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
todos.forEach(el=>myArgs.indexOf(el.id)+1?el.isComplete=true:0);
如果你也想要这个元素:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
var result=todos.filter(el=>myArgs.indexOf(el.id)+1).map(el=>!(el.isComplete=true)||el);
如果你两者都想要:
const todos = [{id: 1, text:"one",isComplete:false},{id:2,text:"two",isComplete:false},{id:3,text:"three",isComplete:false}];
myArgs = [2,3];
var results=todos.reduce((arr,el)=>myArgs.indexOf(el.id)+1?(el.isComplete=true,arr.push(el),arr):arr);
如果您确实需要异步实现(我不这么认为):
这里有一条路
const todos = [{
id: 1,
text: "one",
isComplete: false
}, {
id: 2,
text: "two",
isComplete: false
}, {
id: 3,
text: "three",
isComplete: false
}];
const myArgs = [2, 3];
const completeAllTodos = todos
.filter(todo => {
return myArgs.includes(todo.id)
})
.map(todo => {
todo.isComplete = true
return todo
});
console.log(completeAllTodos)
这里有一条路
const todos = [{
id: 1,
text: "one",
isComplete: false
}, {
id: 2,
text: "two",
isComplete: false
}, {
id: 3,
text: "three",
isComplete: false
}];
const myArgs = [2, 3];
const completeAllTodos = todos
.filter(todo => {
return myArgs.includes(todo.id)
})
.map(todo => {
todo.isComplete = true
return todo
});
console.log(completeAllTodos)
只需在过滤器循环块中执行所有操作:
const todos=[{
id:1,
正文:“一”,
isComplete:错误
}, {
id:2,
文本:“两个”,
isComplete:错误
}, {
id:3,
正文:“三”,
isComplete:错误
}];
常量args=[2,3];
const completedTodos=todos.filter(item=>args.includes(item.id)和&(item.isComplete=true));
console.log(completedTodos)代码>只需在过滤器循环块中执行所有操作:
const todos=[{
id:1,
正文:“一”,
isComplete:错误
}, {
id:2,
文本:“两个”,
isComplete:错误
}, {
id:3,
正文:“三”,
isComplete:错误
}];
常量args=[2,3];
const completedTodos=todos.filter(item=>args.includes(item.id)和&(item.isComplete=true));
console.log(completedTodos)筛选器中的code>对于函数参数,todoItem.id
不是有效名称筛选器中的:todoItem.id
对于函数参数不是有效名称我尝试了[…todos,…completeAllTodos],但我想用2和3 id重写todos,帮助?我尝试了[…todos,…completeAllTodos]但我想用2号和3号id覆盖TODO,帮帮忙?