Javascript 与鼠标事件的工作混淆。onmouseleave

下面是HTML代码

<div id="_navigation">
            <ul>
                <li>Destinations</li>
                <li><a href="HtmlPage.html">Culture</a></li>
                <li><a href="HtmlPage.html">Adventure</a></li>
                <li><a href="HtmlPage.html">Hotels</a></li>
                <li><a href="HtmlPage.html">Wild Life</a></li>
                <li><a href="HtmlPage.html">History</a></li>
                <li><a href="HtmlPage.html">About</a></li>
            </ul>
            <div id="_subNavigation">
                <div id="_navigationFirst">
                    this is first subnavigation it must be showed when user clicks on Distinations
                </div>
                <div id="_navigationSecond">
                    this is second subnavigation it must be showed when user clicks on Culture
                </div>
                <div id="_navigationThird">
                    this is third subnavigation it must be showed when user clicks on Adventure
                </div>
            </div>
        </div>

那么CodeGurus我错在哪里？以及如何获得我想要的效果

将其更改为“

onmouseout

”。我不确定“onmouseout”是不是你想要的效果。你可以看看。如果需要“onmouseleave”效果，就必须依赖jquery，因为javascript没有内置的对“onmouseleave”的支持。我在这里工作

"use strict";
document.getElementById("_navigation").getElementsByTagName("ul")[0].getElementsByTagName("li")[0].onclick = function () {
    console.log("got into block");
    document.getElementById("_navigationFirst").style.display = "block";
}
document.getElementById("_navigation").onmouseleave = function () {
    console.log("you left _navigation block");
    document.getElementById("_navigationFirst").style.display = "none";
}

document.getElementById("_navigation").onmouseout = function () {
    console.log("you left _navigation block");
    document.getElementById("_navigationFirst").style.display = "none";
}