Javascript Angular和Jasmine:如何模拟返回承诺的服务
我有以下AngularJS中的控制器,它从AngularMaterial调用“$mdSidenav”提供的服务。这是通过工厂方法提供的服务Javascript Angular和Jasmine:如何模拟返回承诺的服务,javascript,angularjs,unit-testing,mocking,jasmine,Javascript,Angularjs,Unit Testing,Mocking,Jasmine,我有以下AngularJS中的控制器,它从AngularMaterial调用“$mdSidenav”提供的服务。这是通过工厂方法提供的服务 angular.module('leopDirective', []) .controller('MenuCtrl', function ($scope,$timeout,$mdSidenav,$log) { $scope.mdSidenav = $mdSidenav; $scope.close = function () {
angular.module('leopDirective', [])
.controller('MenuCtrl', function ($scope,$timeout,$mdSidenav,$log) {
$scope.mdSidenav = $mdSidenav;
$scope.close = function () {
$mdSidenav('left').close().then(function() {$scope.closed=true; });
};
});
为了测试我的控制器,我试图模拟该服务($mdSidenav)。以下是我试图定义的Jasmine测试的源代码:
describe('Controller: MenuCtrl', function() {
var $rootScope, $scope, $controller, $q, menuCtrl,
mock__mdSidenav = function(component) {
return {
// THIS FUNCTION IS EMPTY SINCE $Q IS NOT AVAILABLE
close: function() {}
}
};
beforeEach(function() {
module('leopDirective', function($provide) {
// I HAVE TO PROVIDE THE MOCK UP BEFORE INJECTING $Q
$provide.value('$mdSidenav', mock__mdSidenav);
});
inject(function($injector) {
$rootScope = $injector.get('$rootScope');
$controller = $injector.get('$controller');
$q = $injector.get('$q');
$scope = $rootScope.$new();
});
menuCtrl = $controller("MenuCtrl", { $scope: $scope });
});
it('should create the $mdSidenav object', function() {
var deferred = $q.defer(),
promise = deferred.promise;
// NOW THAT $Q IS AVAILABLE, I TRY TO FILL UP THE FUNCTION
mock__mdSidenav.close = function() {
return promise.then(function(response){return response.success;});
};
// force `$digest` to resolve/reject deferreds
$rootScope.$digest();
// INVOKE FUNCTION TO TEST
$scope.close();
});
});
我遇到的问题是,我不知道如何为mock创建一个返回承诺的函数:
TypeError: Cannot read property 'then' of undefined
at Scope.$scope.close (app.js:7:35)
模拟具有返回承诺的函数的服务的正确方法是什么?首先,使模拟服务方法返回承诺对象:
mock__mdSidenav = function(component) {
return {
isMock: true,
close: function() {
return $q.when();
}
}
};
然后将其注入控制器实例:
menuCtrl = $controller("MenuCtrl", {
$scope: $scope,
$mdSidenav: mock__mdSidenav
});
最后,写下一些期望:
it('should create the $mdSidenav object', function() {
$scope.close();
$rootScope.$digest();
expect($scope.closed).toBe(true);
});
演示:非常感谢您的帮助。我仍然无法理解的是,如果尚未注入模拟变量,那么在创建模拟变量时如何使用$q……好吧,从技术上讲,您是正确的,这有点令人困惑。最好在定义
$q
之后的每个块之前在中创建模拟服务。但是,在您的情况下,当创建mock_uumdsidenav
时,不使用$q
,仅当调用close
时才使用它。当它发生时,$q
已经定义好了。好吧,这里的关键是要理解,当你在变量的定义中使用$q时,它的分辨率是“惰性的”。这个假设正确吗?