Javascript jquery合并两个对象

如何将jquery对象合并在一起

我有

 {
  "merchantcontract":"Ready Reserve Foods 10104.01",
  "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
  "smi_transactiondate":"\/Date(1332140400000)\/",
  "smi_glamount2":15.2600,
  "smi_transactionclass":180870001,
  "smi_transactionclassname":"Residual Agent Commission",
  "smi_contractprodcutidname":"Traditional",
  "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
  "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
 },

 {
  "merchantcontract":"Ready Reserve Foods 10104.01",
  "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
  "smi_transactiondate":"\/Date(1332140400000)\/",
  "smi_glamount2":2.6000,
  "smi_transactionclass":180870001,
  "smi_transactionclassname":"Residual Agent Commission",
  "smi_contractprodcutidname":"Traditional",
  "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
  "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
     }

我想要

     {
      "merchantcontract":"Ready Reserve Foods 10104.01",
      "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
      "smi_transactiondate":"\/Date(1332140400000)\/",
      "smi_glamount2":15.2600,
      "smi_transactionclass":180870001,
      "smi_transactionclassname":"Residual Agent Commission",
      "smi_contractprodcutidname":"Traditional",
      "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
      "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
      },

       {
      "merchantcontract":"Ready Reserve Foods 10104.01",
      "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
      "smi_transactiondate":"\/Date(1332140400000)\/",
      "smi_glamount2":2.6000,
      "smi_transactionclass":180870001,
      "smi_transactionclassname":"Residual Agent Commission",
      "smi_contractprodcutidname":"Traditional",
      "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
      "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
       }

    {"merchantcontract":"Ready Reserve Foods 10104.01"{

      "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
      "smi_transactiondate":"\/Date(1332140400000)\/",
      "smi_glamount2":15.2600,
      "smi_transactionclass":180870001,
      "smi_transactionclassname":"Residual Agent Commission",
      "smi_contractprodcutidname":"Traditional",
      "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
      "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
   },
   {

      "merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
      "smi_transactiondate":"\/Date(1332140400000)\/",
      "smi_glamount2":2.6000,
      "smi_transactionclass":180870001,
      "smi_transactionclassname":"Residual Agent Commission",
      "smi_contractprodcutidname":"Traditional",
      "smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
      "smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
   }
}

所以两个对象都在一个对象下。我可能有两个以上的对象

这些对象是在jquery中创建的

---

我不知道如何开始这项工作。

你能把它们放在一个数组中吗

var myObjects = [];

在创建它们的每个位置添加：

myObjects.push(newObject);

jQuery会做你想做的事情

//merging two objects into new object
var new_object = $.extend({}, object1, object2);

//merge object2 into object1
$.extend(object1, object2);

---

如果希望递归合并它们，请提供参数

deep

。如果

deep=true

合并将递归进行。上面的一个例子

// Initialize two objects.
var json1 = { "a": { "a1": "value1", "a2": "value2" }};
var json2 = { "a": { "a3": "value3" }};

// Merge them recursively.
var newJson = $.extend(true, {}, json1, json2);

// Test it.
if (newJson.a.a1 && newJson.a.a3) {
    console.log("Success");
}

---

如果要更新现有对象，请使用：

$.extend(obj1, obj2); //update obj1 and put all obj2 values in it.

$.extend将更改现有对象的值

要创建两个对象之和的新的第三个对象，可以使用此函数

function merger_objects(obj1,obj2){
  $.each(obj2, function(key, value) {
     obj1[key] = value;    
  });
 return obj1;
}

示例

var fruit = {apple:"sweet",graps:"bitter"}
var vege = {cucamber:"bitter",letuce:"bitter"}

var fruit_and_vege = merger_objects(fruit,vege); 
//returns {apple:"sweet",graps:"bitter",cucamber:"bitter",letuce:"bitter"}

---

查看这篇文章，寻找可能的答案。是否可以动态创建一个新对象并将其添加到父对象中。我需要的是标题值为a的所有对象，以及标题值为B的所有对象，等等。。组合在一个新对象中。目前，json没有分组。可以有无限组。是的，任何事情都有可能！但是，你不再仅仅是合并对象，所以你必须用$/A/while循环来迭代对象，并将每一个键->值PAR与某个新的对象添加到一个特定的键，并将具有不同键的所有PARS添加到另一个对象中。

var fruit = {apple:"sweet",graps:"bitter"}
var vege = {cucamber:"bitter",letuce:"bitter"}

var fruit_and_vege = merger_objects(fruit,vege); 
//returns {apple:"sweet",graps:"bitter",cucamber:"bitter",letuce:"bitter"}