Javascript 处理硬件返回按钮单击

我不知道如何使我的winjs（react winjs）应用程序与硬件后退按钮一起工作。这是我的导航功能的一个示例：

handleNavigation(location) {
    this.setState({
        location: location
    });

    WinJS.Navigation.navigate(`/${location}`);
    console.log(WinJS.Navigation.history);
}

console.log（WinJS.Navigation.history）

以正确的历史顺序输出名为“backStack”的正确数组，但单击windows phone emulator上的硬件后退按钮只是简单地退出应用程序

我错过了什么明显的东西吗

这是我设法找到并尝试的，但没有成功（我也找到了一些好的C#文档，但不是我需要的）：

---

谢谢

确实这是一个非常愚蠢的错误，我在没有等待winjs/windows准备好的情况下初始化了我的应用程序，我应该这样初始化它：

(function () {
"use strict";

var app = WinJS.Application;
var activation = Windows.ApplicationModel.Activation;

app.onactivated = function (args) {
    if (args.detail.kind === activation.ActivationKind.launch) {
        if (args.detail.previousExecutionState !== activation.ApplicationExecutionState.terminated) {
            // This is how you should initialize your app
            ReactDOM.render(<App />, document.getElementById('app'));
        } else {
            // TODO: This application was suspended and then terminated.
            // To create a smooth user experience, restore application state here so that it looks like the app never stopped running.
        }
        args.setPromise(WinJS.UI.processAll());
    }
};

app.oncheckpoint = function (args) {
    // TODO: This application is about to be suspended. Save any state that needs to persist across suspensions here.
    // You might use the WinJS.Application.sessionState object, which is automatically saved and restored across suspension.
    // If you need to complete an asynchronous operation before your application is suspended, call args.setPromise().
};

app.start();
})();

---

显示您连接此事件处理程序的代码在哪里？另外，您是否尝试从第一条路径返回？有“链接1”和“链接3”，忘记添加“链接2”

componentWillMount() {
    WinJS.Application.addEventListener("backclick", function () {
        document.body.style.background = "red"; //or for example setState/show notification etc...
    });
}