Javascript 在js文件更改时调用闭包
我正在使用google闭包编译器和gulp缩小我的angularjs文件 这是我的gulpfile代码Javascript 在js文件更改时调用闭包,javascript,gulp,google-closure-compiler,gulp-watch,Javascript,Gulp,Google Closure Compiler,Gulp Watch,我正在使用google闭包编译器和gulp缩小我的angularjs文件 这是我的gulpfile代码 var closureCompiler = require('google-closure-compiler').gulp(); var flatmap = require('gulp-flatmap'); var path = require('path'); gulp.task('js-closure', function () { return gulp.src(['app/j
var closureCompiler = require('google-closure-compiler').gulp();
var flatmap = require('gulp-flatmap');
var path = require('path');
gulp.task('js-closure', function () {
return gulp.src(['app/js/*.js', 'dist/single.js'], {base: './'})
.pipe(flatmap(function(stream, file) {
return stream.pipe(closureCompiler({
compilation_level: 'SIMPLE_OPTIMIZATIONS',
warning_level: 'QUIET',
language_in: 'ECMASCRIPT6_STRICT',
language_out: 'ECMASCRIPT5_STRICT',
output_wrapper: '(function(){\n%output%\n}).call(this)',
js_output_file: path.basename(file.path).replace(/js$/, 'min.js')
}))
}))
.pipe(gulp.dest('./dist/js'));
});
代码运行良好。但是,我必须在命令行上手动运行gulpjsclosure来编译js文件
我想在任何一个js文件被更改时自动编译js文件
编辑:GulpWatch似乎很适合解决这个问题。如何修改代码以使用gulp watch?有好的示例吗?直接来自gulp api文档:
var watcher = gulp.watch(['app/js/*.js', 'dist/single.js'], ['js-closure']);
watcher.on('change', function(event) {
console.log('File ' + event.path + ' was ' + event.type + ', running tasks...');
});
正如您所指出的,使用gulp watch是正确的方法。一个简单的改变就足够了
var closureCompiler = require('google-closure-compiler').gulp();
var flatmap = require('gulp-flatmap');
var watch = require('gulp-watch');
gulp.task('js-closure', function () {
return watch(['app/js/*.js', 'dist/single.js'], function()
{
gulp.src(['app/js/*.js', 'dist/single.js'], {base: './'})
.pipe(flatmap(function(stream, file) {
return stream.pipe(closureCompiler({
compilation_level: 'SIMPLE_OPTIMIZATIONS',
warning_level: 'QUIET',
language_in: 'ECMASCRIPT6_STRICT',
language_out: 'ECMASCRIPT5_STRICT',
output_wrapper: '(function(){\n%output%\n}).call(this)',
js_output_file: path.basename(file.path).replace(/js$/, 'min.js')
}))
}))
.pipe(gulp.dest('./dist/js'));
});
});
您添加了gulp watch作为问题标签-这也是答案。谢谢提示。一些示例会有所帮助。