NodeJS中的JavaScript类和模块
我很难理解如何将单独的.js文件导入到index.js节点文件中 我创建了一个文件pokemon.js,如下所示:NodeJS中的JavaScript类和模块,javascript,node.js,Javascript,Node.js,我很难理解如何将单独的.js文件导入到index.js节点文件中 我创建了一个文件pokemon.js,如下所示: var pokemon = (function(){ function Pokemon(name) { this.name = name; console.log("pokemon"); } })(); module.exports.Pokemon = pokemon; 现在在我的index.js中,我想使用它: var Pokemon = r
var pokemon = (function(){
function Pokemon(name) {
this.name = name;
console.log("pokemon");
}
})();
module.exports.Pokemon = pokemon;
现在在我的index.js中,我想使用它:
var Pokemon = require('./models/pokemon.js');
//如何调用口袋妖怪函数
更新:
var Pokemon = require('./models/models.js');
var app = express();
var pokemons = [];
app.get("/pokemon/all",function(req,res){
var pokemon = Pokemon("Pikachu"); // Pokemon is not a function
})
以下是我找到的解决方案:
models.js:
module.exports = function(name) {
this.name = name;
}
index.js:
var Pokemon = require('./models/models.js');
var app = express();
var pokemons = [];
app.get("/pokemon/all",function(req,res){
var pokemon = new Pokemon('Pikachu');
pokemons.push(pokemon);
res.json(pokemons);
})
@catta提供的代码只是有一个小错误,请尝试:
var pokemon = function(name) {
this.name = name;
console.log("pokemon");
}
module.exports.Pokemon = pokemon;
在index.js中
var Pokemon = require('./models.js');
Pokemon.Pokemon('name') //output name
我知道您想要导出对象构造函数
pokemon.js
function Pokemon(name){
this.name = name;
console.log(this.name);
}
// if any prototype
Pokemon.prototype.serviceOne = function(){ };
Pokemon.prototype.serviceTwo = function(){ };
module.exports = Pokemon;
index.js
var Pokemon = require('path/to/pokemon');
app.get("/pokemon/all",function(req,res){
var pikachu= new Pokemon("Pikachu");
pikachu.serviceOne();
pikachu.serviceTwo();
})
var pokemon = function(str){
this.name = str;
console.log(this.name);
};
module.exports.Pokemon = pokemon;
var Pokemon = require('./models/models.js');
var app = express();
var pokemons = [];
app.get("/pokemon/all",function(req,res){
pokemons.push(Pokemon.Pokemon("Pikachu"));
})
pokemon.js
var Pokemon = require('path/to/pokemon');
app.get("/pokemon/all",function(req,res){
var pikachu= new Pokemon("Pikachu");
pikachu.serviceOne();
pikachu.serviceTwo();
})
var pokemon = function(str){
this.name = str;
console.log(this.name);
};
module.exports.Pokemon = pokemon;
var Pokemon = require('./models/models.js');
var app = express();
var pokemons = [];
app.get("/pokemon/all",function(req,res){
pokemons.push(Pokemon.Pokemon("Pikachu"));
})
main.js
var Pokemon = require('path/to/pokemon');
app.get("/pokemon/all",function(req,res){
var pikachu= new Pokemon("Pikachu");
pikachu.serviceOne();
pikachu.serviceTwo();
})
var pokemon = function(str){
this.name = str;
console.log(this.name);
};
module.exports.Pokemon = pokemon;
var Pokemon = require('./models/models.js');
var app = express();
var pokemons = [];
app.get("/pokemon/all",function(req,res){
pokemons.push(Pokemon.Pokemon("Pikachu"));
})
当您将var key设置为require时,它只引用该文件。因此,您需要“Pokemon.Pokemon()”您的iLife不会返回任何内容,因此
Pokemon
是未定义的。删除iLife部分并使Pokemon=function Pokemon…
。您能将其作为一个答案来编写,以便我有更好的想法吗?如果pokemon有方法或函数怎么办。@johndoe你应该用解决方案回答你自己的问题。仍然没有定义。最后一行:pokemon.pokemon(“name”);它不是口袋妖怪(“名字”);或者粘贴当前代码只是在我的笔记本电脑@john doeb07/apps/test/over$more models.js var pokemon=function(name){this.name=name;console.log(“pokemon”);}module.exports.pokemon=pokemon;douxsey@douxsey-CR70-2M-CX70-2OC-CX70-2OD:/mnt/9aa1c3fe-f4e9-4867-afef-8ab2db92eb07/apps/test/over$more index.js var Pokemon=require('./models.js');Pokemon.Pokemon('name')//输出名称douxsey@douxsey-CR70-2M-CX70-2OC-CX70-2OD:/mnt/9aa1c3fe-f4e9-4867-afef-8ab2db92eb07/apps/test/over$node index.js口袋妖怪
也是很好的解决方案。我也得到了同样的结果。口袋妖怪没有定义。同样使用上述方法,如何将函数添加到Pokemon类(function)。@johndoe export-as-constructor。编辑,非常感谢!如果我正在使用上述技术,如何将原型函数添加到Pokemon对象中。您可以:Pokemon.Prototype.f=function(){}