Javascript 具有异步函数的Sailsjs策略

Javascript 具有异步函数的Sailsjs策略,javascript,node.js,async-await,sails.js,Javascript,Node.js,Async Await,Sails.js,我试图做的是将expressbrute作为策略实现到sailsjs应用程序 因此,我注册了一个策略bruteForce 我的bruteForce.js文件包含: const ExpressBrute = require('express-brute'), moment = require('moment'), SequelizeStore = require('express-brute-sequelize'), Sequelize = require('sequelize');

我试图做的是将expressbrute作为策略实现到sailsjs应用程序

因此,我注册了一个策略bruteForce

我的bruteForce.js文件包含:

const ExpressBrute = require('express-brute'),
  moment = require('moment'),
  SequelizeStore = require('express-brute-sequelize'),
  Sequelize = require('sequelize');

const failCallback = (req, res, next, nextValidRequestDate) =>  {
  res.status(429).json({
    message: 'You\'ve made too many failed attempts in a short period of time, please try again '+moment(nextValidRequestDate).fromNow(),
    nextValidRequestDate,
    tryAgainIn: moment(nextValidRequestDate).diff(moment)
  })
}

const handleStoreError = (error) => {
  sails.log.error(error);
  throw {
    message: error.message,
    parent: error.parent
  };
}

const store = new ExpressBrute.MemoryStore();

const bruteForceOptions = {
  freeRetries: 3,
  minWait: 1000*60,
  maxWait: 1000*60*15,
  failCallback,
  handleStoreError
}

const bruteforce = new ExpressBrute(store, bruteForceOptions)

module.exports = async function (req, res, next) {
  return bruteforce.prevent(req, res, next)
};
到目前为止,这是可行的,但是当我尝试设置另一个商店驱动程序时,我现在选择了Sequelize驱动程序

因此,我补充说:

const sequelize = new Sequelize('table', 'root', 'secret', {
  host: '127.0.0.1',
  dialect: 'mysql',
  operatorsAliases: false,
  logging: sails.log.debug
});

const getBruteforce = async function(){
  new SequelizeStore(sequelize, 'bruteStore', {}, function(store) {
    console.log(store)
    return new ExpressBrute(store, bruteForceOptions)
  });
}
我的新政策职能是:

module.exports = async function (req, res, next) {
  const bruteforce = await getBruteforce()
  return bruteforce.prevent(req, res, next)
};
但在这里,我总是得到错误bruteforce undefined,并且在新SequelizeStore的回调中调用console.log

我不明白我怎么能解决这个问题


有人知道吗?

因为你的
getBruteforce()
函数实际上并没有返回任何东西

const getBruteforce = async function(){
  new SequelizeStore(sequelize, 'bruteStore', {}, function(store) {
    console.log(store)
    // Below returns from the callback, **not** the async function
    return new ExpressBrute(store, bruteForceOptions)
  });
}
改为这样做:

const getBruteforce = function(){
  return new Promise(resolve => {
    new SequelizeStore(sequelize, 'bruteStore', {}, function(store) {
      console.log(store)
      // Fulfill the returned promise
      resolve(new ExpressBrute(store, bruteForceOptions))
    });
  });
}
我建议你仔细阅读一下如何做