Javascript 夜视-如果元素不存在,则执行另一个操作

Javascript 夜视-如果元素不存在,则执行另一个操作,javascript,if-statement,nightwatch.js,Javascript,If Statement,Nightwatch.js,如何在NightwatchJS中编写简单的if/else?如果存在元素,请单击此元素,否则-单击另一个元素 'Test2: click login button': function(client) { client.expect.element('.login .btn').to.be.present; client.click('.login .btn'); // if "client.expect.element('.login .btn') is not pres

如何在NightwatchJS中编写简单的if/else?如果存在元素,请单击此元素,否则-单击另一个元素

'Test2: click login button': function(client) {

    client.expect.element('.login .btn').to.be.present;
    client.click('.login .btn');


//  if "client.expect.element('.login .btn') is not present(visible)" - 
//      but "client.expect.element('a.menu-link').to.be.present(visible)";
//  client.click('a.menu-link');


    client.pause(1000);
});

},执行此操作的方法可能不止一种,但我会使用的函数:

'Test2: click login button': client => {
  const buttonSelector = '.login .btn';
  const menuLinkSelector = 'a.menu-link';
  client.element('css selector', buttonSelector, result => {
    if (result.status > -1) {
      // `.login .btn` is present
      client.click(buttonSelector);
    } else {
      // else, check for `a.menu-link`
      client.element('css selector', menuLinkSelector, () => {
        client.click(menuLinkSelector);
      });
    }   
  });
  client.end();
}