Javascript jQuery隐藏/显示问题
我有一个问题,我显示一辆车,我希望用户能够改变颜色的汽车以及轮辋Javascript jQuery隐藏/显示问题,javascript,html,Javascript,Html,我有一个问题,我显示一辆车,我希望用户能够改变颜色的汽车以及轮辋 <script type="text/javascript"> function showImage(image){ var mainImage = document.getElementById('mainImage'); mainImage.src = image; } f
<script type="text/javascript">
function showImage(image){
var mainImage = document.getElementById('mainImage');
mainImage.src = image;
}
function toggleThumbnails(){
var thumbnails = document.getElementById('color-options');
if(thumbnails.style.display == 'block'){
thumbnails.style.display = 'none';
} else {
thumbnails.style.display = 'block';
}
}
function showImage(image){
var mainImage = document.getElementById('mainwheelImage');
mainImage.src = image;
}
function toggleThumbnails(){
var thumbnails = document.getElementById('wheel-options');
if(thumbnails.style.display == 'block'){
thumbnails.style.display = 'none';
} else {
thumbnails.style.display = 'block';
}
}
</script>
<section id="footer-wrapper">
<!-- Color Selector -->
<div id="color-options">
<h1>Colors</h1>
<div class="color-container">
<div class="color-center">
<span><img src="img/colors/black.png" onclick="showImage('img/colors/cars/black.png')" /></span>
<span><img src="img/colors/white.png" onclick="showImage('img/colors/cars/white.png')" /></span>
<span><img src="img/colors/red.png" onclick="showImage('img/colors/cars/red.png')" /></span>
<span><img src="img/colors/silver.png" onclick="showImage('img/colors/cars/silver.png')" /></span>
<span><img src="img/colors/metalic_black.png" onclick="showImage('img/colors/cars/metalic_black.png')" /></span>
<span><img src="img/colors/metalic_grey.png" onclick="showImage('img/colors/cars/metalic_grey.png')" /></span>
</div>
</div>
</div>
<!-- /Color Selector -->
<div class="divider"></div>
<!-- Wheels Selector -->
<div id="wheel-options">
<h1>Wheels</h1>
<div class="wheel-container">
<div class="wheel-center">
<span><img src="img/wheels/17.jpg" onclick="showImage('img/wheels/cars_overlay/17.png')" /></span>
<span><img src="img/wheels/18.jpg" onclick="showImage('img/wheels/cars_overlay/18_regular.png')" /></span>
<span><img src="img/wheels/18_twin.jpg" onclick="showImage('img/wheels/cars_overlay/18_twin.png')" /></span>
<span><img src="img/wheels/18_twin_7spoke.jpg" /></span>
</div>
</div>
</div>
<!-- /Wheels Selector -->
函数showImage(图像){
var mainImage=document.getElementById('mainImage');
mainImage.src=图像;
}
函数切换缩略图(){
var thumbnails=document.getElementById('color-options');
if(thumbnails.style.display=='block'){
thumbnails.style.display='none';
}否则{
thumbnails.style.display='block';
}
}
函数showImage(图像){
var mainImage=document.getElementById('mainwheelImage');
mainImage.src=图像;
}
函数切换缩略图(){
var thumbnails=document.getElementById('wheel-options');
if(thumbnails.style.display=='block'){
thumbnails.style.display='none';
}否则{
thumbnails.style.display='block';
}
}
颜色
车轮
这样可以切换汽车和轮辋的颜色。但是如果我选择了一种颜色,那么当我选择一个边缘时,颜色默认回到原始图像。在选择轮辋时,有没有办法保持颜色处于选定状态?您对不同的功能使用了两次相同的功能名称,这会使浏览器感到困惑。尝试将函数名更改为类似以下内容:
function changeColor()
function toggleColorThumbnails()
及
您两次声明了
showImage
和toggleThumbnails
函数。试着给他们起不同的名字。
function changeRim()
function toggleRimThumbnails()