Javascript 如何删除节点计划中的所有计划？

我看从你可以删除一个一个的名字，例如

var schedule = require('node-schedule');

 // sample announcement

 var rule = new schedule.RecurrenceRule();
 rule.dayOfWeek = [1, 2, 3, 4, 5];
 rule.minute = 50;
 rule.hour = 12;

 var message = schedule.scheduleJob("AnnouncementOne", rule, function() {
    // make my announcement
})

AnnouncementOne.cancel();

但我希望代码能够获取所有计划的作业，然后循环通过它们删除每个作业。我认为下面的人得到了所有的工作

var jobList = schedule.scheduledJobs;

以下哪个输出到控制台

{ 'AnnouncementOne':
   Job {
     job: [Function],
     callback: false,
     name: 'AnnouncementOne',
     trackInvocation: [Function],
     stopTrackingInvocation: [Function],
     triggeredJobs: [Function],
     setTriggeredJobs: [Function],
     cancel: [Function],
     cancelNext: [Function],
     reschedule: [Function],
     nextInvocation: [Function],
     pendingInvocations: [Function] },
  'AnnouncementTwo':
   Job {
     job: [Function],
     callback: false,
     name: 'AnnouncementTwo',
     trackInvocation: [Function],
     stopTrackingInvocation: [Function],
     triggeredJobs: [Function],
     setTriggeredJobs: [Function],
     cancel: [Function],
     cancelNext: [Function],
     reschedule: [Function],
     nextInvocation: [Function],
     pendingInvocations: [Function] } }

如何循环作业列表以删除每个作业

备选代码：

var jobList = schedule.scheduledJobs;

for(jobName in jobList){
  var job = 'jobList.' + jobName;
  eval(job+'.cancel()');
}

---

可能不是最优雅的方法，但由于jobList缺少长度字段，因此有一种方法可以实现这一点：

var schedule = require('node-schedule');

// sample announcement

var rule = new schedule.RecurrenceRule();
rule.dayOfWeek = [1, 2, 3, 4, 5];
rule.minute = 50;
rule.hour = 12;

var message = schedule.scheduleJob("Announcement0", rule, function() {
    // make my announcement
})

var message = schedule.scheduleJob("Announcement1", rule, function() {
    // make my announcement
})

var jobList = schedule.scheduledJobs;

for (var i = 0; i < 2; i++) {
   eval('jobList.Announcement'+i+'.cancel()');
}

---

最好远离

eval

const schedule = require('node-schedule');
const _ = require('lodash');
const j = schedule.scheduleJob('SomeDirtyWork', '42 * * * *', () => {
  // Something is going on
});

const jobNames = _.keys(schedule.scheduledJobs);
for(let name of jobNames) schedule.cancelJob(name);

一行：

for (const job in schedule.scheduledJobs) schedule.cancelJob(job);

---

我得到'jobList.Announcement0.cancel（）^TypeError:无法读取未定义的'cancel'属性，在尝试取消作业之前，我如何测试该作业是否存在，因为我无法确定它是否存在，如果确实存在，则只希望将其删除。出现此错误是因为作业列表中不存在DeleteTesting0。在删除作业之前，我通过检查作业是否存在更新了答案。明白了，谢谢，顺便说一句，作为一个选项，我可以检查对象并使用添加到问题底部的代码删除每个作业吗？我不在乎是否所有作业都被删除。那很好，只要记住如果在结果中使用for，那么结果在常规for循环中是有序的，而不是有序的。所以你可能会经历一些意想不到的行为。根据我的经验，我一般不使用for，但我的领域主要是在前端浏览器设置中使用JavaScript，在那里无法提供意外的行为。我会小心使用eval。为什么不列出作业列表['Announcement'+i].cancel（）？另外，为什么scheduledJobs没有出现在节点调度文档中？

const schedule = require('node-schedule');
const _ = require('lodash');
const j = schedule.scheduleJob('SomeDirtyWork', '42 * * * *', () => {
  // Something is going on
});

const jobNames = _.keys(schedule.scheduledJobs);
for(let name of jobNames) schedule.cancelJob(name);

var jobList = cron.scheduledJobs; //Get All scheduled jobs

Object.values(jobList).map(job => {
  console.log("Each Job", job.name);

    cron.cancelJob(job.name);
  })

for (const job in schedule.scheduledJobs) schedule.cancelJob(job);