Javascript 为什么查询只返回函数中不包含的数据
为什么这段代码能工作(只要它能在Chrome控制台中收回一个空的“CustomerObject”就行了Javascript 为什么查询只返回函数中不包含的数据,javascript,parse-platform,Javascript,Parse Platform,为什么这段代码能工作(只要它能在Chrome控制台中收回一个空的“CustomerObject”就行了 var CustomerObject = Parse.Object.extend("CustomerObject"); var retrieve = new Parse.Query(CustomerObject); retrieve.equalTo("customernumber", $('#searchnumber').val()); retrieve.first({
var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);
retrieve.equalTo("customernumber", $('#searchnumber').val());
retrieve.first({
success: function(retrieveResults)
{
}
});
var cname = retrieve.get("customername");
var cnumber = retrieve.get("customernumber");
但是,当用户单击搜索按钮时,函数中的代码不会返回任何“CustomerObject”
HTML
缺少括号Find
<input type="text" name="searchnumber" id="searchnumber" value="" placeholder="Customer Number"/>
<button type="submit" onclick = "search" >Find</button>
function search() {
var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);
retrieve.equalTo("customernumber", $('#searchnumber').val());
retrieve.first({
success: function(retrieveResults)
{
}
});
var cname = retrieve.get("customername");
var cnumber = retrieve.get("customernumber");
};