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Javascript 为什么查询只返回函数中不包含的数据_Javascript_Parse Platform - Fatal编程技术网

Javascript 为什么查询只返回函数中不包含的数据

Javascript 为什么查询只返回函数中不包含的数据,javascript,parse-platform,Javascript,Parse Platform,为什么这段代码能工作(只要它能在Chrome控制台中收回一个空的“CustomerObject”就行了 var CustomerObject = Parse.Object.extend("CustomerObject"); var retrieve = new Parse.Query(CustomerObject); retrieve.equalTo("customernumber", $('#searchnumber').val()); retrieve.first({

为什么这段代码能工作(只要它能在Chrome控制台中收回一个空的“CustomerObject”就行了

var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);  
retrieve.equalTo("customernumber", $('#searchnumber').val()); 
        retrieve.first({ 
            success: function(retrieveResults) 

        {

        }

    });
        var cname = retrieve.get("customername");  
        var cnumber = retrieve.get("customernumber"); 
但是,当用户单击搜索按钮时,函数中的代码不会返回任何“CustomerObject”

HTML

缺少括号
Find

  <input type="text" name="searchnumber" id="searchnumber" value="" placeholder="Customer Number"/>  
    <button type="submit" onclick = "search" >Find</button> 
function search() {
var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);  
retrieve.equalTo("customernumber", $('#searchnumber').val()); 
        retrieve.first({ 
            success: function(retrieveResults) 

        {

        }

    });
        var cname = retrieve.get("customername");  
        var cnumber = retrieve.get("customernumber"); 

  };