Javascript 在嵌套数组中循环

我有一个数组，实际上是一系列表行

0: Array[5]
0: ""
1: ""
2: "Is there at least one teacher or other adult in this school that you can talk to if you have a problem?"
3: ""
4: ""

1: Array[5]
0: ""
1: ""
2: "Yes"
3: "No"
4: "Not sure"

2: Array[5]
0: "Grade"
1: "6th"
2: "55%"
3: "20%"
4: "25%"

如果遇到某些内容，例如“？”我想将该行分配给一个新的JSON对象。我用forEach循环遍历数组，如下所示：

function parseRow(element, index, array) {
    element.forEach(parseCell);
  }
function parseCell(element, index, array) {
    if (element.indexOf("?") > -1) { // if it is a question
      //do something to tell indicate this is a question row

    }  else { 
      // table cell
    }
  }

 {
"question": "Is there at least...",
"Category": "Overall",
"Division" : "All",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},
{
"question": "Is there at least...",
"Category" : "Grade",
"Division" : "6th",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},
{
"question": "Is there at least...",
"Category" : "Grade",
"Division" : "7th",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},

我需要在我的目标上更加明确。我有一个行值数组（作为数组），其中一些包含表定义问题，一些是标题行，一些是表行。我想写出一个JSON对象，格式如下：

function parseRow(element, index, array) {
    element.forEach(parseCell);
  }
function parseCell(element, index, array) {
    if (element.indexOf("?") > -1) { // if it is a question
      //do something to tell indicate this is a question row

    }  else { 
      // table cell
    }
  }

 {
"question": "Is there at least...",
"Category": "Overall",
"Division" : "All",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},
{
"question": "Is there at least...",
"Category" : "Grade",
"Division" : "6th",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},
{
"question": "Is there at least...",
"Category" : "Grade",
"Division" : "7th",
"Yes" : "65.00%",
"No": "11.70%",
"Not Sure" : "23.30%",
},

---

JSON对象可能嵌套得更为嵌套，这似乎是最容易处理的构建。

您可以使用可以返回对象的map函数，以便从元素数组中获取一系列问题：

function parseRow(element, index, array) {
   var questions = element.map(function(el,i){
       if(el.indexOf("?") > -1){
          return el;
       }
   });
}

---

这将为您提供一个包含问题的元素数组。

如果您想保持

forEach

循环，您需要为这两个循环使用一个公共闭包。或者，使用

map

，然后您确实可以将经过处理的内容返回到

parseRow

可以使用的表单中。当遇到

？

字符时，您具体想做什么？当遇到“？”时，我想将元素分配给一个newObj{“question”：element}，但我还想使它成为一个新表的标记@JonathanBrooksthanks，我接受这个答案，因为它回答了基本问题，谢谢