Javascript 如何在jQuery中重复函数？_Javascript_Html_Jquery

Javascript 如何在jQuery中重复函数？

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Javascript 如何在jQuery中重复函数？,javascript,html,jquery,Javascript,Html,Jquery,我尝试在这个函数中使用无限循环，但是当我设置setInterval时，函数不会重复。问题是当用户发送表单时，时间间隔过后。该函数保留在发送的消息上，不会从头开始。请看我的 Javascript: $(function(){ function show_fb() { $("#feedback_box").show("slow"); } function hideAll() { $("#feedback_box").hide("slow"); } $

我尝试在这个函数中使用无限循环，但是当我设置

setInterval

时，函数不会重复。问题是当用户发送表单时，时间间隔过后。该函数保留在发送的消息上，不会从头开始。请看我的

Javascript:

$(function(){

  function show_fb() {
    $("#feedback_box").show("slow");    
  }

  function hideAll() {
    $("#feedback_box").hide("slow");
  }

  $("#feedback_box #close").click(function() { // When the X is pressed
    $("#feedback_box").hide("slow"); // Hide the form
  });

  setInterval(show_fb,1000); // Show the form after 6 seconds , you can change 6000 to anything you like    

  $("#feedback_form").submit(function() { //When the form is submitted

    $('#feedback_form #fb_title').css('background-color','#4444FF').text('Sending...').slideDown(900); //show "Sending" message

    $.post("form_submit.php",{ mesaj:$('#mesaj').val(),rand:Math.random() } ,function(data) { //subimit the feedback via AJAX

        $('#feed_subm').attr("disabled", "false"); //disable the "SEND" button
        $('#feedback_form #fb_title').css('background-color','#C33').text('Thank You!').slideDown(900); //Shows a thank you message
        setTimeout(hideAll,2000); // Hide the form after 2 seconds

    });

  });

  return false; //Tells the code not to post the form physically

});

</head>
<body>

    <div id="feedback_box"> 
        <form id="feedback_form"> 
            <span id="fb_title">Give us some feedback :)</span><span id="close">X</span> 
            <textarea id="mesaj"></textarea> 
            <input type="submit" value="Send" class="mysubm" id="feed_subm"/> 
        </form> 
    </div>

</body>

$(document).ready(function() {

  // First we will create the function that will be repeated
  function repeat() {

    setTimeout(function() {

      // Enter your code that you want to repeat in here

      repeat(); // This is where the function repeats

    }, 1); // Where 1 is the delay (in milliseconds)

  }

  repeat(); // Here we are initially firing the function

});

HTML:

$(function(){

  function show_fb() {
    $("#feedback_box").show("slow");    
  }

  function hideAll() {
    $("#feedback_box").hide("slow");
  }

  $("#feedback_box #close").click(function() { // When the X is pressed
    $("#feedback_box").hide("slow"); // Hide the form
  });

  setInterval(show_fb,1000); // Show the form after 6 seconds , you can change 6000 to anything you like    

  $("#feedback_form").submit(function() { //When the form is submitted

    $('#feedback_form #fb_title').css('background-color','#4444FF').text('Sending...').slideDown(900); //show "Sending" message

    $.post("form_submit.php",{ mesaj:$('#mesaj').val(),rand:Math.random() } ,function(data) { //subimit the feedback via AJAX

        $('#feed_subm').attr("disabled", "false"); //disable the "SEND" button
        $('#feedback_form #fb_title').css('background-color','#C33').text('Thank You!').slideDown(900); //Shows a thank you message
        setTimeout(hideAll,2000); // Hide the form after 2 seconds

    });

  });

  return false; //Tells the code not to post the form physically

});

</head>
<body>

    <div id="feedback_box"> 
        <form id="feedback_form"> 
            <span id="fb_title">Give us some feedback :)</span><span id="close">X</span> 
            <textarea id="mesaj"></textarea> 
            <input type="submit" value="Send" class="mysubm" id="feed_subm"/> 
        </form> 
    </div>

</body>

$(document).ready(function() {

  // First we will create the function that will be repeated
  function repeat() {

    setTimeout(function() {

      // Enter your code that you want to repeat in here

      repeat(); // This is where the function repeats

    }, 1); // Where 1 is the delay (in milliseconds)

  }

  repeat(); // Here we are initially firing the function

});


给我们一些反馈：）X

您可以在jQuery中重复如下函数：

Javascript:

$(function(){

  function show_fb() {
    $("#feedback_box").show("slow");    
  }

  function hideAll() {
    $("#feedback_box").hide("slow");
  }

  $("#feedback_box #close").click(function() { // When the X is pressed
    $("#feedback_box").hide("slow"); // Hide the form
  });

  setInterval(show_fb,1000); // Show the form after 6 seconds , you can change 6000 to anything you like    

  $("#feedback_form").submit(function() { //When the form is submitted

    $('#feedback_form #fb_title').css('background-color','#4444FF').text('Sending...').slideDown(900); //show "Sending" message

    $.post("form_submit.php",{ mesaj:$('#mesaj').val(),rand:Math.random() } ,function(data) { //subimit the feedback via AJAX

        $('#feed_subm').attr("disabled", "false"); //disable the "SEND" button
        $('#feedback_form #fb_title').css('background-color','#C33').text('Thank You!').slideDown(900); //Shows a thank you message
        setTimeout(hideAll,2000); // Hide the form after 2 seconds

    });

  });

  return false; //Tells the code not to post the form physically

});

</head>
<body>

    <div id="feedback_box"> 
        <form id="feedback_form"> 
            <span id="fb_title">Give us some feedback :)</span><span id="close">X</span> 
            <textarea id="mesaj"></textarea> 
            <input type="submit" value="Send" class="mysubm" id="feed_subm"/> 
        </form> 
    </div>

</body>

$(document).ready(function() {

  // First we will create the function that will be repeated
  function repeat() {

    setTimeout(function() {

      // Enter your code that you want to repeat in here

      repeat(); // This is where the function repeats

    }, 1); // Where 1 is the delay (in milliseconds)

  }

  repeat(); // Here we are initially firing the function

});

在上面的例子中，我不明白为什么需要不断重复函数，但你的问题是如何在jQuery中重复函数

我想这意味着如何在jQuery中重复函数

这是您的答案。

请不要发布带有可疑文件的Mediafire链接。使用jsBin或jsFiddle。好的，下一个问题我将使用jsBin谢谢您的信息。@BluemoonPro您不必等待下一个问题。使用演示替换此链接中的mediafire链接。此处显示其：

function repeat（）{setTimeout（function（）{repeat（）；}，1）；}repeat（）问题是你检查了脚本，你可以看到该功能正在发送一条消息，然后该功能重复它的操作，但从一开始就没有。除非引起用户的发送部分可以重新发送消息。