Javascript Symfony2嵌入式表单删除按钮功能
我在Symfony2中创建了一个嵌入式表单,在一个“部门”中有许多“员工”。现在,在“部门”表单中添加了许多名“Firstname”和“Lastname”的员工,效果很好(为此我使用了jQuery)。我想要表单上的“删除”按钮功能,我无法理解。有人能帮我使用删除按钮功能吗 DepartmentType.phpJavascript Symfony2嵌入式表单删除按钮功能,javascript,php,jquery,forms,symfony,Javascript,Php,Jquery,Forms,Symfony,我在Symfony2中创建了一个嵌入式表单,在一个“部门”中有许多“员工”。现在,在“部门”表单中添加了许多名“Firstname”和“Lastname”的员工,效果很好(为此我使用了jQuery)。我想要表单上的“删除”按钮功能,我无法理解。有人能帮我使用删除按钮功能吗 DepartmentType.php <?php namespace InstituteEvents\FormBundle\Form; use Symfony\Component\Form\AbstractType;
<?php
namespace InstituteEvents\FormBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class DepartmentType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('name')
->add('employees','collection', array(
'type' => new EmployeeType(),
'prototype' => true,
'allow_add' => true,
'by_reference' =>false
))
;
}
/**
* @param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'InstituteEvents\FormBundle\Entity\Department'
));
}
/**
* @return string
*/
public function getName()
{
return 'department';
}
}
按照找到的说明进行操作:
在DepartmentType
表单类中,将EmployeeType
集合的allow\u delete
属性设置为true
:
$builder
->add('name')
->add('employees','collection', array(
'type' => new EmployeeType(),
'prototype' => true,
'allow_add' => true,
'allow_delete' => true,//add this
'by_reference' =>false
)
);
接下来,添加delete按钮(通过EmployeeType
表单中的生成器(->add('delete','button')
),或手动添加(在tempalte中使用JS)。然后将事件侦听器附加到表单。假设您已添加delete按钮,如下所示:
//EmployeeType:
$builder->add('delete', 'button', ['attr' => ['class' => 'delete-employee']]);
如果要在视图中使用JS添加按钮,那么下面的代码应该可以做到:
$('#department-form-selector').children('employee-form-selector').each(function(i)
{
$(this).append('<button name="delete' + i + '" class="delete-employee">Delete</button>');
});
现在,要处理表单(假设实体设置正确):
请注意,此代码未经测试。这是最坏情况场景删除的基本流程(双向、一对多关系,反向,但未设置ondelete级联限制)。
使用此代码作为参考,您应该能够计算出它,尽管您应该使用文档:因为您所需要的全部都在文档中。我无法从食谱转换为上面index.html.twig中的jQuery代码,用于“删除员工”按钮及其代码。请帮助嘿,Udan,您可以帮助我使用“删除员工”的jQuery代码吗按钮?因为我不知道jQueryYou没有在您的部门类型
表单上设置允许删除
属性。如何处理删除被广泛介绍(PHP+jQ代码)谢谢您Elias Van Ootegem谢谢您的代码,但我想在“twig”(index.html.twig)中添加“删除员工”按钮,就像我在“添加”中所做的那样按钮,而不是在“EmployeeType.ie
类似地,我希望有“Delete employees”按钮,并在“index.html.twig”中有删除功能?你能在“index.html.twig”中作为一个整体提供代码吗?作为“添加”按钮,我在“DepartmentType”或“EmployeeType”中没有提供,但我在twig中使用了“添加”按钮的代码HTML@sachintendulkar:我添加了两种方法来为每个员工添加删除按钮(包含$(this.append()
)的位).deleteAll按钮与单个delete按钮基本相同,只需对所有员工表单元素调用remove()
,然后提交该表单,并以相同的方式处理它。只需添加一个button元素+事件处理程序,查询DOM中的所有员工表单,并在其上循环($('emplyee-form-selector')。每个(函数(){$(this.remove()})
),并提交form@sachintendulkar:除此之外:不,我不会向你提供所有的代码,这不是我的工作。如果你遇到特定的问题,我愿意帮助你,但我不会免费为你做工作……对不起,如果你能为我提供“删除员工”按钮及其在index.html.twig中的功能,就像我在“添加”按钮及其在“index.html.twig”中的代码一样,请
//EmployeeType:
$builder->add('delete', 'button', ['attr' => ['class' => 'delete-employee']]);
$('#department-form-selector').children('employee-form-selector').each(function(i)
{
$(this).append('<button name="delete' + i + '" class="delete-employee">Delete</button>');
});
$('#department-form-selector').on('click', '.delete-employee', function()
{
$(this).closest('form').delete();//remove element
//optionally submit department form via AJAX call to persist the delete
return false;//stop event
});
//in the controller that handles the form:
if ($form->isValid())
{
//1 => we need to query for the data in the DB, so we know what to delete
$current = $service->getCurrentDepartmentWithEmployees();
//get the current employees, that need to be updated
$oldEmployees = new ArrayCollection();
foreach ($current->getEmployees() as $employee)
$oldEmployees->add($employee);
//2 => get the form data
$department = $form->getData();
//3 => check if one or more eployees were deleted
foreach ($oldEmployees as $employee)
{
if (!$department->getEmployees()->contains($employee))
{//employee was removed, update entity/entities
$current->getEmployees()->removeElement($employee);
//depending on the relations you've specified:
$employee->setDepartment(null);
$em->persist($employee);
$em->persist($current);
}
}
$em->flush();
}