Javascript Node.js+;ObjectArray+;比较
可以在javascript中比较两个对象数组吗。我的要求是我必须比较两个对象数组,并且我必须在这两个对象数组之间获取公共对象: 考虑第一个对象数组:Javascript Node.js+;ObjectArray+;比较,javascript,node.js,Javascript,Node.js,可以在javascript中比较两个对象数组吗。我的要求是我必须比较两个对象数组,并且我必须在这两个对象数组之间获取公共对象: 考虑第一个对象数组: [ { id_0: 356, name_0: 'xxxxx', id_1: 33, name_1: 'yyyyyy', id_2: 602, name_2: 'zzzzzzz', collecteddate: '31/03/2011', key: 'kkkkkkk', value: '
[ { id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzzz',
collecteddate: '31/03/2011',
key: 'kkkkkkk',
value: '0.41' },
{ id_0: 356,
name_0: 'xxxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k1k1k1k1k1',
value: '0.20' },
{ id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k2k2k2k2k2k2k2',
value: '1.30' }}]
[ { id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzzz',
collecteddate: '31/03/2011',
key: 'kkkkkkk',
value: '0.41' },
{ id_0: 356,
name_0: 'xxxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k1k1k1k1k1',
value: '0.20' },
{ id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k2k2k2k2k2k2k2',
value: '1.30' }}]
我的第二个对象数组:
[ { id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzzz',
collecteddate: '31/03/2011',
key: 'kkkkkkk',
value: '0.41' },
{ id_0: 356,
name_0: 'xxxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k1k1k1k1k1',
value: '0.20' },
{ id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k2k2k2k2k2k2k2',
value: '1.30' }}]
[ { id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzzz',
collecteddate: '31/03/2011',
key: 'kkkkkkk',
value: '0.41' },
{ id_0: 356,
name_0: 'xxxxxx',
id_1: 33,
name_1: 'yyyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k1k1k1k1k1',
value: '0.20' },
{ id_0: 356,
name_0: 'xxxxx',
id_1: 33,
name_1: 'yyyyy',
id_2: 602,
name_2: 'zzzzzz',
collecteddate: '31/03/2011',
key: 'k2k2k2k2k2k2k2',
value: '1.30' }}]
我必须比较以上两个对象,并且我必须用上述两个对象的常用条目构建另一个对象。在上面的示例中,两个数组中的每个条目都是相同的,因此第三个数组应该包含3个条目。有没有可能帮我解决这个问题提前谢谢
编辑:
我使用了u40;下划线)库来检查如果两个对象相等,那么两个对象是否相等我将该对象推到了新数组中..它是否是好的解决方案..没有第三个库的解决方案-纯javascript 类似这样的东西(递归)-可以优化,但可读性较差
var compareAndMerge = function(object1, object2) {
var outputObject = {};
var compareSubObject = function(object1, object2) {
var outputObject = {};
for (var k in object1) {
for (var k2 in object2) {
if (typeof object1[k] === 'object' && typeof object2[k2] === 'object') {
var sameObject = compareSubObject(object1[k], object2[2]);
if (sameObject === false) {
return false;
}
outputObject[k] = object1[k];
} else if (object1[k] === object2[k]) {
outputObject[k] = object1[k];
} else {
return false;
}
}
}
return outputObject;
};
for (var k in object1) {
for (var k2 in object2) {
if (typeof object1[k] !== 'object' && object1[k] === object2[k]) {
outputObject[k] = object1[k];
} else if (typeof object1[k] === 'object') {
var sameObject = compareSubObject(object1[k], object2[k]);
if (sameObject !== false) {
outputObject[k] = sameObject;
}
}
}
}
return outputObject;
};
注意:此解决方案假定对象的所有值都是字符串或数字
function getCommonObjects(array1, array2) {
var result = [];
for (var i = 0; i < array1.length; i += 1) {
for (var j = 0; j < array2.length; j += 1) {
if (Object.keys(array1[i]).length === Object.keys(array2[j]).length){
var flag = true;
for (var key in array1[i]) {
if (array1[i][key] !== array2[j][key]) {
flag = false;
break;
}
}
if (flag) {
result.push(array2[j]);
break;
}
}
}
}
return result;
}
函数getCommonObjects(array1,array2){
var结果=[];
对于(变量i=0;i